Tìm x:
a) x-3/x+3=3/7
b) x+4/20=5/x+4
Tìm x:
a, 4.( x + 41 ) = 7
b, x. ( x-51 ) 2. 2 mũ 3 + 20
a) 4(x+41)=7
x+41=7/4
x=7/4-41
x=157/4
b) có gì đó sai sai-.-
Tìm x:
a, 4.( x + 41 ) = 7
b, 4. ( x-3 ) = 7 mũ 2 - 1 mũ 10
a. 4.(x+41) = 7
x + 41 = 7 : 4 = 1,75
x = 1,75 - 41 = -39,25
b. 4.(x-3) = 72 - 110 = 49 - 1 = 48
x - 3 = 48 : 4 = 12
x = 12 + 3 = 15
Tìm x:
a) X x 3 x 5 = 2,7 b) 1,2 : X x 4 = 20
a: \(x\cdot3\cdot5=2,7\)
=>\(x\cdot15=2,7\)
=>\(x=\dfrac{2,7}{15}=0,18\)
b: \(1,2:x\cdot4=20\)
=>\(1,2:x=20:4=5\)
=>\(x=1,2:5=0,24\)
Bài 4. Chứng minh rằng giá trị các biểu thức sau không phụ thuộc vào x:
a) (x-5)(2x+3)-2x(x-3)+x+7
b) x(2x+1)-x^2(x+2)+x^3-x+3
a) \(=2x^2-7x-15-2x^2+6x+x+7=-8\)
b) \(=2x^2+x-x^3-2x^2+x^3-x+3=3\)
Tìm x:
a, (x - 1/2) : 1/3 + 5/7 = 9 5/7
b, x + 30% x = - 1,31
c, -2/3.x + 1/5 = 1/10
\(a,\left(x-\dfrac{1}{2}\right):\dfrac{1}{3}+\dfrac{5}{7}=9\dfrac{5}{7}\)
\(\Leftrightarrow\left(x-\dfrac{1}{2}\right).3=\dfrac{68}{7}-\dfrac{5}{7}\)
\(\Leftrightarrow\left(x-\dfrac{1}{2}\right).3=9\)
\(\Leftrightarrow x-\dfrac{1}{3}=3\)
\(\Leftrightarrow x=3+\dfrac{1}{3}\)
\(\Leftrightarrow x=\dfrac{9}{3}+\dfrac{1}{3}\)
\(\Leftrightarrow x=\dfrac{10}{3}\)
\(b,x+30\%x=-1,31\)
\(\Leftrightarrow x+\dfrac{3}{10}.x=-\dfrac{131}{100}\)
\(\Leftrightarrow x.\left(1+\dfrac{3}{10}\right)=-\dfrac{131}{100}\)
\(\Leftrightarrow x.\dfrac{13}{10}=-\dfrac{131}{100}\)
\(\Leftrightarrow x=-\dfrac{131}{100}.\dfrac{10}{13}\)
\(\Leftrightarrow x=-\dfrac{131}{130}\)
\(c,-\dfrac{2}{3}x+\dfrac{1}{5}=\dfrac{1}{10}\)
\(\Leftrightarrow\dfrac{-2}{3}x=\dfrac{1}{10}-\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{-2}{3}x=\dfrac{1}{10}-\dfrac{2}{10}\)
\(\Leftrightarrow-\dfrac{2}{3}x=-\dfrac{1}{10}\)
\(\Leftrightarrow x=-\dfrac{1}{10}.\left(-\dfrac{3}{2}\right)\)
\(\Leftrightarrow x=\dfrac{3}{20}\)
Tim x:
a) \(\dfrac{13+x}{20}=\dfrac{3}{4}\)
b) \(\dfrac{23-x}{25}=\dfrac{4}{5}\)
`(13+x)/20 = 3/4`
`(13+x) xx4=3xx20`
`(13+x)xx4=60`
`13+x=60:4`
`13+x=15`
`x=15-13`
`x=2`
__
`(23-x)/25 =4/5`
`(23-x)xx5=4xx25`
`(23-x)xx5=100`
`23-x=100:5`
`23-x=20`
`x=23-20`
`x=3`
Tìm x:
a)x(x+4)+(5+x)(5-x)=3
b)(2x-3)^2=(4x+3)^2
mình cảm ơn
\(a,\Rightarrow x^2+4x+25-x^2=3\\ \Rightarrow4x=-22\Rightarrow x=-\dfrac{11}{2}\\ b,\Rightarrow\left(2x-3-4x-3\right)\left(2x-3+4x+3\right)=0\\ \Rightarrow6x\left(-2x-6\right)=0\Rightarrow\left[{}\begin{matrix}x=-3\\x=0\end{matrix}\right.\)
Tìm x:
a)x+3/4=5/3
b)x-2/3=7/2
a) x + \(\dfrac{3}{4}\) = \(\dfrac{5}{3}\)
x = \(\dfrac{5}{3}\) - \(\dfrac{3}{4}\)
x = \(\dfrac{20}{12}\) - \(\dfrac{9}{12}\)
x = \(\dfrac{11}{12}\)
b) x - \(\dfrac{2}{3}\) = \(\dfrac{7}{2}\)
x = \(\dfrac{7}{2}\) + \(\dfrac{2}{3}\)
x = \(\dfrac{21}{6}\) + \(\dfrac{4}{6}\)
x = \(\dfrac{25}{6}\)
Tìm x:
a) 2/5 = 3/4 : x = -1/2
b) 5/7 - 2/3 . x = 4/5
c) 1/2x + 3/5x = -2/3
d) 4/7x - x = -9/14
b: \(\dfrac{5}{7}-\dfrac{2}{3}\cdot x=\dfrac{4}{5}\)
=>\(\dfrac{2}{3}x=\dfrac{5}{7}-\dfrac{4}{5}=\dfrac{25-28}{35}=\dfrac{-3}{35}\)
=>\(x=-\dfrac{3}{35}:\dfrac{2}{3}=\dfrac{-3}{35}\cdot\dfrac{3}{2}=-\dfrac{9}{70}\)
c: \(\dfrac{1}{2}x+\dfrac{3}{5}x=-\dfrac{2}{3}\)
=>\(x\left(\dfrac{1}{2}+\dfrac{3}{5}\right)=-\dfrac{2}{3}\)
=>\(x\cdot\dfrac{5+6}{10}=\dfrac{-2}{3}\)
=>\(x\cdot\dfrac{11}{10}=-\dfrac{2}{3}\)
=>\(x=-\dfrac{2}{3}:\dfrac{11}{10}=-\dfrac{2}{3}\cdot\dfrac{10}{11}=\dfrac{-20}{33}\)
d: \(\dfrac{4}{7}\cdot x-x=-\dfrac{9}{14}\)
=>\(\dfrac{-3}{7}\cdot x=\dfrac{-9}{14}\)
=>\(\dfrac{3}{7}\cdot x=\dfrac{9}{14}\)
=>\(x=\dfrac{9}{14}:\dfrac{3}{7}=\dfrac{9}{14}\cdot\dfrac{7}{3}=\dfrac{3}{2}\)
Tìm x:
a) 3/4 x X = 5/8
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b) 5/6 - X = 1/ 12
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a)x=\(\dfrac{5}{8}:\dfrac{3}{4}=\dfrac{5}{6}\)
b) x=\(\dfrac{5}{6}-\dfrac{1}{12}=\dfrac{3}{4}\)
a \(x=\dfrac{5}{8}:\dfrac{3}{4}\)
\(x=\dfrac{5}{8}\times\dfrac{4}{3}\)
\(x=\dfrac{5}{6}\)
b \(x=\dfrac{5}{6}-\dfrac{1}{12}\)
\(x=\dfrac{10}{12}-\dfrac{1}{12}\)
\(x=\dfrac{9}{12}\)
\(x=\dfrac{3}{4}\)