\(\frac{x-3}{x+3}=\frac{3}{7}\Leftrightarrow\left(x-3\right).7=3.\left(x+3\right)\)
\(\Leftrightarrow7x-21=3x+9\Rightarrow7x-3x=9-\left(-21\right)\)
\(\Leftrightarrow4x=30;x=7,5\)
b) \(\frac{x+4}{20}=\frac{5}{x+4}\Leftrightarrow\left(x+4\right)\left(x+4\right)=5.20\)
\(x^2+\left(4+4\right)^2=100\)
\(x^2=100-64=36\)
\(\Rightarrow x\in\left\{-6;6\right\}\)