Sai nha bạn

TL: 

Sai nhé bạn 

Bạn k cho mik cái đi nhé 

@@@@@@@@@@@@@@@@@ 

HT

Sai nha

#Bonnie @Ngân Hà

a: Xét tứ giác AEHF có 

\(\widehat{AEH}=\widehat{AFH}=\widehat{FAE}=90^0\)

Do đó: AEHF là hình chữ nhật

Các bạn ơi giúp mình với,cho mình hỏi:Từ nào khác với các từ còn lại:A.Ứng dụng B.Vận dụng C.Áp dụng D.Công dụng.

Trả lời

D . công dụng 

hok tốt .

trả lời :

  D. công dụng

hok tốt !!!

công dụng bn nha mik đi thi tiếng việt nên đúng 100% luôn đó

c. Sụn tăng trưởng ở hai đầu xương

C

d

Giải:

a)\(\dfrac{3}{4}x-\dfrac{1}{3}=\dfrac{-5}{6}\) 

           \(\dfrac{3}{4}x=\dfrac{-5}{6}+\dfrac{1}{3}\) 

           \(\dfrac{3}{4}x=\dfrac{-1}{2}\) 

              \(x=\dfrac{-1}{2}:\dfrac{3}{4}\) 

             \(x=\dfrac{-2}{3}\) 

b)\(\left(2\dfrac{4}{5}x-0,2\right):\dfrac{4}{5}=\dfrac{7}{8}\) 

       \(\dfrac{14}{5}x-\dfrac{1}{5}=\dfrac{7}{8}.\dfrac{4}{5}\) 

        \(\dfrac{14}{5}x-\dfrac{1}{5}=\dfrac{7}{10}\) 

         \(\dfrac{14}{5}x=\dfrac{7}{10}+\dfrac{1}{5}\) 

          \(\dfrac{14}{5}x=\dfrac{9}{10}\) 

              \(x=\dfrac{9}{10}:\dfrac{14}{5}\) 

             \(x=\dfrac{9}{28}\) 

c) \(\dfrac{1}{4}+\dfrac{1}{3}:\left|2x-1\right|=\dfrac{11}{12}\) 

            \(\dfrac{1}{3}:\left|2x-1\right|=\dfrac{11}{12}-\dfrac{1}{4}\) 

            \(\dfrac{1}{3}:\left|2x-1\right|=\dfrac{2}{3}\) 

                  \(\left|2x-1\right|=\dfrac{1}{3}:\dfrac{2}{3}\) 

                  \(\left|2x-1\right|=\dfrac{1}{2}\) 

⇒2x-1=\(\dfrac{1}{2}\) hoặc 2x-1=\(\dfrac{-1}{2}\) 

        x=\(\dfrac{3}{4}\) hoặc x=\(\dfrac{1}{4}\)

câu a nha \(\dfrac{3}{4}x-\dfrac{1}{3}=-\dfrac{5}{6}\)

\(\dfrac{3}{4}x=-\dfrac{5}{6}+\dfrac{1}{3}\)

\(\dfrac{3}{4}x=-\dfrac{3}{6}\)

\(x=-\dfrac{3}{6}:\dfrac{3}{4}\)

\(x=-\dfrac{6}{4}.\dfrac{4}{3}\)

\(x=-\dfrac{24}{12}=-2\)

a) \(\dfrac{3}{4}+\dfrac{9}{5}\div\dfrac{3}{2}-1=\dfrac{3}{4}+\dfrac{18}{15}-1=\dfrac{39}{20}-1=\dfrac{19}{20}\)

b) \(\dfrac{6}{7}\cdot\dfrac{8}{13}+\dfrac{6}{13}\cdot\dfrac{9}{7}-\dfrac{4}{13}\cdot\dfrac{6}{7}=\dfrac{48}{91}+\dfrac{54}{91}-\dfrac{24}{91}=\dfrac{48+51-24}{91}=\dfrac{78}{91}=\dfrac{6}{7}\)

c) \(\dfrac{-3}{7}+\left(\dfrac{3}{-7}-\dfrac{3}{-5}\right)\)\(=\dfrac{-3}{7}+\left(\dfrac{-3}{7}-\dfrac{-3}{5}\right)=\dfrac{-3}{7}+\dfrac{6}{35}=-\dfrac{9}{35}\)

Bài 5: 

a: BC=10cm

b: HA=4,8cm

HB=3,6(cm)

HC=6,4(cm)

Bài 6:

\(x^3=6+3\sqrt[3]{\left(3+2\sqrt{2}\right)\left(3-2\sqrt{2}\right)}\left(\sqrt[3]{3+2\sqrt{2}}+\sqrt[3]{3-2\sqrt{2}}\right)\\ \Leftrightarrow x^3=6+3x\sqrt[3]{1}\\ \Leftrightarrow x^3-3x=6\\ y^3=34+3\sqrt[3]{\left(17+12\sqrt{2}\right)\left(17-12\sqrt{2}\right)}\left(\sqrt[3]{17+12\sqrt{2}}+\sqrt[3]{17-12\sqrt{2}}\right)\\ \Leftrightarrow y^3=34+3y\sqrt[3]{1}\\ \Leftrightarrow y^3-3y=34\\ \Leftrightarrow P=x^3-3x+y^3-3y+1980=6+34+1980=2020\)

gfrưerrrrrrrrrrr

\(i=i'\)

\(\Rightarrow i'=30^o\)

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