Đặt \(A=\frac{4}{12}+\frac{4}{20}+\frac{4}{30}+...+\frac{4}{306}\)

\(=4.\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{306}\right)\)

\(=4.\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{17.18}\right)\)

\(=4.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{17}-\frac{1}{18}\right)\)

\(=4.\left(\frac{1}{3}-\frac{1}{18}\right)\)

\(=4.\frac{5}{18}=\frac{10}{9}\)

Vậy A=\(\frac{10}{9}\)

\(\frac{4}{12}+\frac{4}{20}+\frac{4}{30}+.......+\frac{4}{306}\)

\(=\frac{4}{3.4}+\frac{4}{4.5}+\frac{4}{5.6}+.....+\frac{4}{17.18}\)

\(=4\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+.......+\frac{1}{17.18}\right)\)

\(=4\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+......+\frac{1}{17}-\frac{1}{18}\right)\)

\(=4\left(\frac{1}{3}-\frac{1}{18}\right)\)

\(=4.\frac{5}{18}\)

\(=\frac{10}{9}\)

= 4(1/12 + 1/20 + 4/30 +...+1/306)ư

=4(1/3 x 4 + 1/4 x 5 + 1/5 x 6 +...+ 1/17 x 18)

=4(1/3 - 1/4 + 1/4 - 1/5 +...+1/17 - 1/18)

=4[(1/4 - 1/4) + (1/5 - 1/5) +...+ (1/3 - 1/18)]

=4[0 + 0 +...+ (1/3 - 1/18)]

=4(1/3 - 1/18)

=4 x 5/18

=10/9

BT1 :thực hành phép tính

4/3+-11/31+3/10-20/31-2/5 = 7/30

7/12-1/-16+3/4 = 67/48

2/11.-5/4+-9/11.5/4+ 1 và 3/4 = -1/4 * và 3/4 là sao bạn *

-9/27-25/75 = -2/3

Bài 1:

\(\frac{4}{12}+\frac{4}{20}+\frac{4}{30}+...+\frac{4}{306}\)

\(=4\cdot\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{306}\right)\)

\(=4\cdot\left(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+...+\frac{1}{17\cdot18}\right)\)

\(=4\cdot\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{17}-\frac{1}{18}\right)\)

\(=4\cdot\left(\frac{1}{3}-\frac{1}{18}\right)\)

\(=4\cdot\left(\frac{6}{18}-\frac{1}{18}\right)\)

\(=4\cdot\frac{5}{18}\)

\(=\frac{10}{9}\)

Bài 2  :

\(\left(3x-4\right)-\left(6x+7\right)=8\)

\(3x-4-6x-7=8\)

\(\left(3x-6x\right)-\left(4+7\right)=8\)

\(-3x-11=8\)

\(-3x=8+11\)

\(-3x=19\)

\(x=19:\left(-3\right)\)

\(x=\frac{-19}{3}\)

Vậy  \(x=\frac{-19}{3}\)

b ) \(\left(\frac{4}{5}x+3\right):\left(-4\right)=\frac{1}{2}\)

\(\frac{4}{5}x+3=\frac{1}{2}\cdot\left(-4\right)\)

\(\frac{4}{5}x+3=-2\)

\(\frac{4}{5}x=\left(-2\right)-3\)

\(\frac{4}{5}x=-5\)

\(x=\left(-5\right):\frac{4}{5}\)

\(x=\left(-5\right)\cdot\frac{4}{5}\)

\(x=-4\)

Vậy   \(x=-4\)

k nha !

\(\frac{4}{12}\)+\(\frac{4}{20}\)+...+\(\frac{4}{306}\)=\(\frac{4}{3.4}\)+\(\frac{4}{4.5}\)+...+\(\frac{4}{17.18}\)=4(\(\frac{1}{3}\)-\(\frac{1}{4}\)+\(\frac{1}{4}\)-\(\frac{1}{5}\)+...+\(\frac{1}{17}\)-\(\frac{1}{18}\))

                                                                                                  =4(\(\frac{1}{3}\)-\(\frac{1}{8}\))=4.\(\frac{5}{24}\)=\(\frac{5}{6}\)

Cảm ơn 2 bạn đã giúp mình nha😜😝🙏🙏🙏🙏

gúp mink vs

\(\dfrac{5}{12}\)

\(\dfrac{1}{12}\)

\(\dfrac{24}{7}\)

\(\dfrac{1}{6}\)

4/24+1/4=5/12

37/12-3=1/12

4x6/7=24/7

3/8:9/4=1/6

Bài 2:

a: 5/7-3/7x=1

=>3/7x=-2/7

hay x=-2/3

b: \(x+\dfrac{2}{3}=\dfrac{-1}{12}\cdot\dfrac{-4}{5}=\dfrac{1}{15}\)

=>x=1/15-2/3=-9/15=-3/5

c: \(x-4=\dfrac{-14}{35}:\dfrac{7}{5}=\dfrac{-14}{35}\cdot\dfrac{5}{7}=\dfrac{-70}{245}=\dfrac{-2}{7}\)

=>x=4-2/7=26/7

D

D

Đáp án là:D

D

D

D

A

A

A

a: =5/4-3/4=2/4=1/2

b: =30/45-18/45=12/45=4/15

c: =10/12-9/12=1/12

d: =4/3-1/4=16/12-3/12=13/12