Tìm x biết:
a) x = 2/65 + 4/39
b) 1/150 - x = -4/25
Những câu hỏi liên quan
bài 2: Thực hiện phép tính:a)(–4).(–18).(–25).(–2)b) (–29) – [16 + 3.(51 – 49)]Bài 3: Tìm x, biết:a) x + 80 65 b) 100 – 2x 82c) 90 : x 45d) 156 – 2x 82e) 2x : 25 1f) x – 27 –40g) 7x – 13 50h) x : 5 –40i) 200 – (2x + 6) 43j) 89 – (73 – x) 20k) 25 + 3(x – 8) 106
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bài 2: Thực hiện phép tính:
a)(–4).(–18).(–25).(–2)
b) (–29) – [16 + 3.(51 – 49)]
Bài 3: Tìm x, biết:
a) x + 80 = 65
b) 100 – 2x = 82
c) 90 : x = 45
d) 156 – 2x = 82
e) 2x : 25 = 1
f) x – 27 = –40
g) 7x – 13 = 50
h) x : 5 = –40
i) 200 – (2x + 6) = 43
j) 89 – (73 – x) = 20
k) 25 + 3(x – 8) = 106
Bài 3:
a: x=-15
b: =>2x=18
hay x=9
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Tìm x biết:
a, 2^x -15= 2^4+1
b, x+1/65+x+2/64=x+3/63+x+4/61
`a,`\(2^x -15= 2^4+1\)
`-> 2^x-15=17`
`-> 2^x=17+15`
`-> 2^x=32`
`-> 2^x=2^5`
`-> x=5`
`b,` Có phải đề là \(\dfrac{x+1}{65}+\dfrac{x+2}{64}=\dfrac{x+3}{63}+\dfrac{x+4}{62}\) ?
`=>`\(\dfrac{x+1}{65}+1+\dfrac{x+2}{64}+1=\dfrac{x+3}{63}+1+\dfrac{x+4}{62}+1\)
`=>`\(\dfrac{x+1+65}{65}+\dfrac{x+2+64}{64}-\dfrac{x+3+63}{63}-\dfrac{x+4+62}{62}=0\)
`=>`\(\dfrac{x+66}{65}+\dfrac{x+66}{64}-\dfrac{x+66}{63}-\dfrac{x+66}{62}=0\)
`=>`\(\left(x+66\right)\left(\dfrac{1}{65}+\dfrac{1}{64}-\dfrac{1}{63}-\dfrac{1}{62}\right)=0\)
Mà `1/65+1/64-1/63-1/62 \ne 0`
`-> x+66=0`
`-> x=-66`
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Tìm x biết:
a, 2^x -15= 2^4+1
b, x+1/65+x+2/64=x+3/63+x+4/61
a: =>2^x=2^4+16=32
=>x=5
b: Sửa đề: \(\dfrac{x+1}{65}+\dfrac{x+2}{64}=\dfrac{x+3}{63}+\dfrac{x+4}{62}\)
=>\(\left(\dfrac{x+1}{65}+1\right)+\left(\dfrac{x+2}{64}+1\right)=\left(\dfrac{x+3}{63}+1\right)+\left(\dfrac{x+4}{62}+1\right)\)
=>x+66=0
=>x=-66
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Tìm x,biết:
a,(1/2 + 4/7) : x =_ 3/4
b, 0,5 . x - 1 3/4 = 25 phần trắm
a, \(\left(\dfrac{1}{2}+\dfrac{4}{7}\right):x=\dfrac{-3}{4}\)
\(\dfrac{15}{14}:x=\dfrac{-3}{4}\)
=> x= \(\dfrac{-7}{10}\)
b, 0,5:x-\(1\dfrac{3}{4}\)= 25%
0,5:x-\(\dfrac{7}{4}=\dfrac{1}{4}\)
0,5:x = 2
=> x = \(\dfrac{1}{4}\)
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Bài 3. Tìm số tự nhiên x, biết:a) 150 – x - 9b) 4(x – 3) 48c) 71 – (33 + x) 26d) 2(x – 51) 2.23 + 20e) 450 : (x – 19) 50f) 135 – 5(x + 4) 35g) (15 – 6x). 35 36h) 32(x + 4) – 52 5.22i) 4 – ( 7 – x) 2x – ( 13 – 4)k) ( 7 – x) – ( 25 + 7 ) - 25l) 7x – x 521 : 519 + 3.22 – 70m) 2x+1 – 2 14o) 4x + 4x+1 320p) ( 2x +1)3 125q) (x - 2)2 ( x – 2)5
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Bài 3. Tìm số tự nhiên x, biết:
a) 150 – x = - 9 b) 4(x – 3) = 48 c) 71 – (33 + x) = 26 d) 2(x – 51) = 2.23 + 20 e) 450 : (x – 19) = 50 f) 135 – 5(x + 4) = 35 g) (15 – 6x). 35 = 36 | h) 32(x + 4) – 52 = 5.22 i) 4 – ( 7 – x) = 2x – ( 13 – 4) k) ( 7 – x) – ( 25 + 7 ) = - 25 l) 7x – x = 521 : 519 + 3.22 – 70 m) 2x+1 – 2 = 14 o) 4x + 4x+1 = 320 p) ( 2x +1)3 = 125 q) (x - 2)2 = ( x – 2)5 |
a) 150- x = -9
x = 150 -(-9)
x=150+9
x=159
b)4 (x-3)=48
x-3=48÷4
x-3=12
x=12+3
x=15
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6 tháng 11 2021 lúc 15:00
Tìm x biết:
a) \(2^x+2^{x+4}=544\)
b) \(\left(\dfrac{2}{5}-3x\right)^2-\dfrac{1}{5}=\dfrac{4}{25}\)
\(a,\Leftrightarrow2^x\left(1+2^4\right)=544\\ \Leftrightarrow2^x=\dfrac{544}{17}=32=2^5\\ \Leftrightarrow x=5\\ b,\Leftrightarrow\left(\dfrac{2}{5}-3x\right)^2=\dfrac{9}{25}\Leftrightarrow\left[{}\begin{matrix}\dfrac{2}{5}-3x=\dfrac{3}{5}\\3x-\dfrac{2}{5}=\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=-\dfrac{1}{5}\\3x=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{15}\\x=\dfrac{1}{3}\end{matrix}\right.\)
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Bài 2: (2 điểm) Tìm x, biết:
a) (3x + 4)2 – (3x – 1)(3x + 1) = 49
b) x2 – 4x + 4 = 9(x – 2)
c) x2 – 25 = 3x - 15
d) (x – 1)3 + 3(x + 1)2 = (x2 – 2x + 4)(x + 2)
a) \(\Rightarrow9x^2+24x+16-9x^2+1=49\)
\(\Rightarrow24x=32\Rightarrow x=\dfrac{4}{3}\)
b) \(\Rightarrow x^2-13x+22=0\)
\(\Rightarrow\left(x-11\right)\left(x-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=11\\x=2\end{matrix}\right.\)
c) \(\Rightarrow x^2-3x-10=0\)
\(\Rightarrow\left(x-5\right)\left(x+2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=5\\x=-2\end{matrix}\right.\)
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Tìm x biết:
a) -3/4 = x/20
b) - (-6)/12 - x = 9/48
c)3/5 - ( 2 và 1/5 - x) 2= 6/25
Câu 3: (1 diểm) Tìm x:
a) (x + 3)^2 - x(x - 4) = 39
b) x(x - 9) + 2x -18 = 0
a)=> x2 + 6x + 9 - x2 + 4x = 39 => 10x = 30 => x = 3
b) => x(x - 9) + 2(x -9) = 0 => (x+2)(x-9) = 0
+)th1: x + 2 = 0 => x = -2
+)th2: x - 9 =0 => x = 9
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