( 26 + 53 ) + ( 42 - 26 - 55 - 53 )

(26 + 53) +( 42 -26- 55 - 53)

=-13

( 26 + 53 ) + ( 42 - 26 - 55 - 53 )

= ( 26 - 26 ) + ( 53 - 53 ) + 42 + 55

= 0 + 0 + 42 + 55

= 97

(26+53)+(42-26-55-53)=

=26+53+42-26-55-53

=(26-26)+(53-53)+(55-55)+42

=0+0+0+42

=42

 (26 + 53 ) +(42 -26-55-53)

=79 + ( 16 -55 - 53 )

=79 + (-39-53)

=79 -39 - 53

=40 - 53 = -13

( 26 + 53 ) + ( 42 -26 - 55 - 53 )

= 79 + ( 16 - 55 - 53 )

= 79 + ( -39 - 53 )

= 79 + ( -92 )

= -13.

\(\left(26+53\right)+\left(42-26-55-53\right)\)

\(=26+53+42-26-55-53\)

\(=\left(26-26\right)+\left(53-53\right)+\left(42-55\right)\)

\(=0+0+\left(-13\right)\)

\(=-13\)

a) 28 + 55 = 83

45 + 49 = 94

37 + 53 = 90

b) 61 - 18 = 43

53 - 26 = 27

92 - 84 = 8

\(\begin{array}{*{20}{c}}{a)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{28}\\{55}\end{array}}\\\hline{\,\,\,\,83}\end{array}\)                    \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{45}\\{49}\end{array}}\\\hline{\,\,\,\,94}\end{array}\)                            \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{37}\\{53}\end{array}}\\\hline{\,\,\,\,90}\end{array}\)

\(\begin{array}{*{20}{c}}{b)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{61}\\{18}\end{array}}\\\hline{\,\,\,43}\end{array}\)                    \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{53}\\{26}\end{array}}\\\hline{\,\,\,27}\end{array}\)                           \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{92}\\{84}\end{array}}\\\hline{\,\,\,08}\end{array}\)

Bài 1:

1: =15+37+52-37-17=52-2=50

2: =38-42+14-25+27+15=62-42+29=20+29=49

Bài 1: Bỏ ngoặc rồi tính

3) (21-32) - (-12+32)=21-32-(-12)-32=21-32+12-32=-31

4) (12+21) - (23-21+10)=12+21-23+21-10=21

5) (57-725) - (605-53)=57-725-605+53=-1220

6) (55+45+15) - (15-55+45)=55+45+15-15+55-45=55+55=110

Bài 2: Tính các tổng sau một cách hợp lí

1) (-37) + 14 + 26 + 37=(-37+37)+(14+26)=0+40=40

2) (-24) +6 + 10 + 24=(-24+24)+(6+10)=0+16=16

3) 15 + 23 + (-25) + (-23)=(15-25)+(23-23)=-10+0=-10

4) 60 + 33 + (-50) + (-33)=(60-50)+(33-33)=10+0=10

5) (-16) + (-209) + (-14) + 209=(-16-14)+(-209+209)=-30+0=-30

6) (-12) + (-13) + 36 + (-11)=(-11-12-13)+36=-36+36=0

=15+37+52-37-17 =(37-37)+52+15-17 =0+52+15-17 =67-17 =50

(38 – 42 + 14) – (25 – 27 – 15) =38-42+14-25+27+15 =27 c. -(21 – 32) – (-12 + 32) =-21+32+12-32 =-9 d. -(12 + 21 – 23) - (23 – 21 + 10) =-12-21+23-23+21-10 =-22 e. (57 – 725) – (605 – 53) =57-725-605+53 =-1220 f. (55 + 45 + 15) – (15 – 55 + 45) =55+45+15-15+55-45 =110

1,S=1-2+3-4+...+25-26

  S=[1-2]+[3-4]+...+[25-26]

  S=[-1]+[-1]+...+[-1]

  S=[-1]*13

  S= -13

2,S=1-3+5-7+...-53+55

  S=[1-3]+[5-7]+...+[51-53]+55

  S=[-2]+[-2]+...+[-2]+55

  S=[-2]*27+55

  S=[-54]+55

  S=1

\(B=1+22+24+26+28+...+2200\)

\(=1+\dfrac{\left(2200+22\right).\left[\left(2200-22\right):2+1\right]}{2}\)

\(=1+\dfrac{2222.1090}{2}\)

\(=1+1210990\)

\(=1210991\)

\(C=5+53+55+57+...+5101\)

\(=5+\dfrac{\left(5101+53\right).\left[\left(5101-53\right):2+1\right]}{2}\)

\(=5+\dfrac{5154.2525}{2}\)

\(=5+6506925\)

\(=6506930\)