Al → Al₂O₃ ⟶ AlCl₃ ⟶ Al(OH)₃ ⟶ Al₂O₃ ⟶ AlCl₃
Al - Al2O3 - Al - AlCl3 - Al(OH)3 - Al2(SO4)3
4Al+3O2--t--> 2Al2O3
2Al2O3 ------(DPNC criolit)----> 4Al +3O2
2Al+6HCl=> 2AlCl3+3H2
AlCl3+3NaOH=> 3NaCl+Al(OH)3
2Al(OH)3+3H2SO4=> Al2(SO4)3+6H2O
Cần gấp ạ tks
Chọn hệ số để cân bằng phản ứng sau:
1/ Al +O² ---> Al² O³
2/ K + O²---> K²O
3/ Al(OH)³ t° ---> Al² O³ + H²O
4/ Al²O³ + HCl ---> AlCl³+ H²O
5/ Al + HCl ---> AlCl³ + H²↑
6/ FeO + HCl ---> FeCl² + H²O
7/ Fe²O³ + H²SO⁴ ---> Fe²(SO⁴)³ + H²O
8/ NaOH + H²SO⁴ ----> Na²SO⁴ + H²O
9/ Ca(OH)² + FeCl³ ---> CaCl² + Fe(OH)³↓
10/ BaCl² + H²SO⁴ ---> BaSO⁴ ↓ + HCl
1/ 4Al+3O2->2Al2O3
2/ 4K+O2->2K2O
3/ 2Al(OH)3-->Al2O3+3H2O
4/ Al2O3+6HCl->2AlCl3+3H2O
5/ 2Al+6HCl->2AlCl3+3H2
6/ FeO+2HCl->FeCl2+H2O
7/ Fe2O3+3H2SO4->Fe2(SO4)3+3H2O
8/ 2NaOH+H2SO4->Na2SO+2H2O
9/ 3Ca(OH)2+2FeCl3->3CaCl2+2Fe(OH)3
10/ BaCl2+H2SO4->BaSO4+2HCl
------------------------------<3-----------------------------------
a)AlCl3--> Al(OH)3--> Al2O3--> Al
b)Al--> Al2O3--> Al(OH)3-->Al2O3, giúp mik đi mn
AlCl3 + 3NaOH -> Al(OH)3 + 3NaCl
2Al(OH)3 -> Al2O3 + 3H2O
2Al2O3 \(\underrightarrow{đpnc}\) 4Al + 3O2
b;
4Al + 3O2 -> 2Al2O3
Al2O3 + 2NaOH + 2CO2 + 3H2O -> 2Al(OH)3 + 2NaHCO3
2Al(OH)3 -> Al2O3 + 3H2O
2Al2O3\(\xrightarrow[criolit]{đpnc}\)4Al+3O2
Viết PTHH thực hiện dãy chuyển hóa: Al --> Al2O3 --> AlCl3 --> Al(OH)3 --> Al2O5- ->Al
4Al+3O2-->2Al2O2
Al2O3+6HCl---->2AlCl3+3H2O
AlCl3+3NaOH---->Al(OH)3+3NaCl
2Al(OH)3-->Al2O3+3H2O
Al2O3+3H2--->2Al+3H2O
Viết các PTHH biểu diễn các chuyển đổi sau đây: a. Al (1) AlCl₃ (2) Al(OH)₃ (3) Al₂(SO₄)₃ (4) AlCl₃ b. Fe (1) FeCl₃ (2) Fe(OH)₃ (3) Fe(So₄)₃ (4) FeCl₃
a)
(1) $2Al + 6HCl \to 2AlCl_3 + 3H_2$
(2) $AlCl_3 + 3KOH \to Al(OH)_3 + 3KCl$
(3) $2Al +3 H_2SO_4 \to Al_2(SO_4)_3 +3 H_2$
(4) $Al_2(SO_4)_3 + 3BaCl_2 \to 3BaSO_4 + 2AlCl_3$
b)
(1) $2Fe + 3Cl_2 \xrightarrow{t^o} 2FeCl_3$
(2) $FeCl_3 + 3KOH \to Fe(OH)_3 + 3KCl$
(3) $2Fe(OH)_3 + 3H_2SO_4 \to Fe_2(SO_4)_3 + 6H_2O$
(4) $Fe_2(SO_4)_3 + 3BaCl_2 \to 2FeCl_3 + 3BaSO_4$
hãy cân bằng các phương trình hóa học sau :
1. Al(OH)3 --------> Al2O3+ H2O
2. Al2O3 + HCl ---------> AlCl3 + H2O
3. Al + HCl --------> AlCl3 + H2⬆️
4. FeO + HCl --------> FeCl2 + H2O
1. 2Al(OH)3 ------> Al2O3+ 3H2O
2. Al2O3 + 6HCl ---------> 2AlCl3 + 3H2O
3. 2Al + 6HCl --------> 2AlCl3 + 3H2
4. FeO + 2HCl --------> FeCl2 +H2O
1) 2Al(OH)3 \(\underrightarrow{to}\) Al2O3 + 3H2O
2) Al2O3 + 6HCl → 2AlCl3 + 3H2O
3) 2Al + 6HCl → 2AlCl3 + 3H2
4) FeO + 2HCl → FeCl2 + H2O
1)2Al(OH)3-->Al2O3+3H2O
2)Al2O3+6HCl-->2AlCl3+3H2
3)2Al+6HCl-->2AlCl3+3H2
4)FeO+2HCl-->FeCl2+H2O
AlCl3 <-- Al --> Al2O3 --> Al2(SO4)3 --> Al(OH)3 --> Al(NO3)3
2AlCl3 --->2Al +3Cl2
4Al+3O2----.2Al2O3
Al2O3+3H2SO4---->Al2(SO4)3+3H2O
Al2(SO4)3+3Mg(OH)2---->3MgSO4+ 2Al(OH)3
Al(OH)3+ HNO3----> Al(NO3)3+ 2H2O
+, \(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
+, 4Al + 3O2 → 2Al2O3
+, Al2O3 + 3H2SO4 → Al2(SO4)3 + 3H2O
+, Al2(SO4)3 + 3Ba(OH)2 → 2Al(OH)3 + 3BaSO4
+, Al(OH)3 + 3HNO3 → Al(NO3)3 + 3H2O
- Good luck! ^^
Cu -->CuO --> CuSO4 --> CuCl2 --> Cu(NO3)2 --> Cu(OH)2 --> CuO --> Cu
Al --> Al2O3 --> AlCl3 --> Al(OH)3 --> Al2O3 --> Al --> NaAlO2
1.
2Cu + O2 -(to) → 2 CuO
CuO + H2SO4 → CuSO4 + H2O
CuSO4 + BaCl2 → CuCl2 + BaSO4↓
CuCl2 + 2AgNO3 → Cu(NO3)2 + 2AgCl↓
Cu(NO3)2 + NaOH → Cu(OH)2↓ + 2NaNO3
Cu(OH)2 → CuO + H2O
CuO + CO → Cu + CO2
2.
4Al + 3O2 → 2Al2O3
Al2O3 + 6HCl → 2AlCl3 + 3H2↑
AlCl3 + 3NaOH(vừa đủ) → Al(OH)3 + 3NaCl
2Al(OH)3 → Al2O3 + 3H2O
2Al2O3-(đpnc) → 4Al + 3O2↑
2Al + 2NaOH + 2H2O → 2NaAlO2 + 3H2↑
cân bằng PTHH sau
1) Al (OH)3 -> Al2O3 + HO2
2) Al2 O3 + HCl - > AlCl3+ HO2
1) 4Al(OH)3 \(\rightarrow\) 2Al2O3 + 6H2O
2) Al2O3 + 6HCl \(\rightarrow\) 2AlCl3+ 3H2O
1) 2Al(OH)3 → Al2O3 +3H2O
2) Al2O3 + 6HCl → 2AlCl3+ 3H2O
1. \(2Al\left(OH\right)_3\rightarrow Al_2O_3+3H_2O\)
2. \(Al_2O_3+6HCl\rightarrow2AlCl_3\downarrow+3H_2O\)
?CuO + HCl ➜ CuCl2
Al2(SO4)3 + ?BaCl2 ➜ ?AlCl3 + ?
?Al(OH)3 ➜ Al2O3 + ?
CuO +2 HCl ➜ CuCl2+2H2O
Al2(SO4)3 + 3BaCl2 ➜ 2AlCl3 + 3BaSO4
2Al(OH)3 ➜ Al2O3 + 3H2O
\\tham khảo nhé//
CuO + 2HCl ➜ CuCl2 + H2O
Al2(SO4)3 + 3BaCl2 ➜ 2AlCl3 + 3BaSO4↓
2Al(OH)3 ➜ Al2O3 + 3H2O