chịu ko biết dc

Định lý bodu : f(x) = (x-a ). g(x)- f(a)

Nhan thay f(2 ) = 2.2 ^ 3+ 2^2-13.2+6 = 0

theo he qua suy ra f(x) chia het x -2. vay ta chia da thuc cho x -2 

ket qua la f(x ) = 2 x ^ 3+ x^2- 13x + 6 = (x- 2)(2x² + 5x - 3)

\(x\left(2x^2-3x+3\right)\)

\(2x^3-3x^2+3x-1\)

\(=2x^3-x^2-2x^2+x+2x-1\)

\(=x^2\left(2x-1\right)-x\left(2x-1\right)+\left(2x-1\right)\)

\(=\left(2x-1\right)\left(x^2-x+1\right)\)

Ta có: \(6x^4-13x^2+6\)

\(=6x^4-9x^2-4x^2+6\)

\(=3x^2\left(2x^2-3\right)-2\left(2x^2-3\right)\)

\(=\left(2x^2-3\right)\left(3x^2-2\right)\)

\(6x^4-13x^2+6=6x^4-4x^2-9x^2+6\)

                         \(=2x^2\left(3x^2-2\right)-3\left(3x^2-2\right)\)

                         \(=\left(2x^2-3\right)\left(3x^2-2\right)\)

Ta có:\(6x^4-13x^2+6\)

\(=6x^4-9x^2-4x^2+6\)

\(=3x^2\left(2x^2-3\right)-2\left(2x^2-3\right)\)

\(=\left(2x^2-3\right)\left(3x^2-2\right)\)

\(x^3-9x^2+x=x\left(x^2-9x+1\right)\)

\(x^3+13x^2+x=x\left(x^2+13x+1\right)\)

\(2x^3-2xy^2-8x^2+8xy=2x\left(x^2-y^2\right)-8x\left(x-y\right)=2x\left(x-y\right)\left(x+y\right)-8x\left(x-y\right)=2x\left(x-y\right)\left(x+y-4\right)\)

\(2x^3-2xy^2-8x^2+8xy\)

\(=2x\left(x^2-y^2\right)-8x\left(x-y\right)\)

\(=2x\left(x+y\right)\left(x-y\right)-8x\left(x-y\right)\)

\(=\left[2x\left(x+y\right)-8x\right]\left(x-y\right)\)

\(=2x\left(x+y-4\right)\left(x-y\right)\)

\(2x^3-2xy^2-8x^2+8xy\)

\(=2x\left(x^2-y^2\right)-8x\left(x-y\right)\)

\(=\left(x-y\right)\left[2x\left(x+y\right)-8x\right]\)

\(=2x\left(x-y\right)\left(x+y-4\right)\)

Lời giải:

$2x^2+3x-5=(2x^2-2x)+(5x-5)=2x(x-1)+5(x-1)=(x-1)(2x+5)$

\(5x^2-10x+2x-4\)

\(=5x\left(x-2\right)+2\left(x-2\right)\)

\(=\left(x-2\right)\left(5x+2\right)\)

giúp toi

=2(x-2) + 5x(x-2)

=(x-2)(2+5x)

\(=2\left(x^2-y^2\right)-3\left(x+y\right)=2\left(x-y\right)\left(x+y\right)-3\left(x+y\right)=\left(x+y\right)\left(2x-2y-3\right)\)

Hãy cho em lời giải trước 4h