\(Cu\underrightarrow{1}CuO\underrightarrow{2}CuSO_4\underrightarrow{3}CuCl_2\underrightarrow{4}Cu\left(OH\right)_2\underrightarrow{5}CuO\underrightarrow{6}Cu\)

(1) \(2Cu+O_2\underrightarrow{t^o}2CuO\)

(2) \(CuO+H_2SO_4\rightarrow CuSO_4+H_2O\)

(3) \(CuSO_4+BaCl_2\rightarrow CuCl_2+BaSO_4\)

(4) \(CuCl_2+2NaOH\rightarrow Cu\left(OH\right)_2+2NaCl\)

(5) \(Cu\left(OH\right)_2\underrightarrow{t^o}CuO+H_2O\)

(6) \(CuO+H_2\underrightarrow{t^o}Cu+H_2O\)

 Chúc bạn học tốt

Cu+o2 ra Cuo

Cuo+H2So4 ra Cuso4 +H2o

Cuso4+Bacl ra Cucl2+BaSo4

CuCl2+Naoh ra Cu(oh)2+Nacl

Cu(oh)2 ra Cuo+H2o

Cuo ra Cu+o2

`a) CuSO_4 + 2NaOH \to Na_2SO_4 + Cu(OH)_2` $Cu(OH)_2 \xrightarrow{t^0} CuO + H_2O$ `b)` `n_{CuSO_4}={160.0,1}/{160}=0,1 mol` Theo pt: `n_{NaOH}=2.n_{CuSO_4}=2.0,1=0,2 mol` `=> V_{ddNaOH}=0,2l` `c)` Theo pt: `n_{Na_2SO_4}=n_{CuSO_4}=0,1 mol` `=> m_{Na_2SO_4}=0,1.142=14,2g` Theo pt: `n_{CuO}=n_{Cu(OH)_2}=n_{CuSO_4}=0,1 mol` `=> m_B=0,1.80=8g`

$Cu(OH)_2 \xrightarrow{t^o} CuO + H_2O$
$CuO + 2HCl \to CuCl_2 + H_2o$

$CuCl_2 + 2AgNO_3 \to Cu(NO_3)_2 + 2AgCl$
$Cu(NO_3)_2 + 2KOH \to Cu(OH)_2 + 2KNO_3$

2Cu + O₂ ---> 2CuO

CuO + HCl ---> CuCl₂ + H₂O

CuCl₂ + Ba(OH)₂ ---> Cu(OH)₂ + BaCl₂

Cu(OH)₂ ---t^o--> CuO + H₂O

CuO + SO₃ ---> CuSO₄

CuSO₄ + Pb(NO₃)₂ --->Cu(NO₃)₂ + PbSO₄

em tham khảo nha

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Cu + Cl₂→ CuCl₂

CuCl₂ + 2NaOH → Cu(OH)₂ +2 NaCl

Cu(OH)₂ \(\underrightarrow{t^°}\) CuO + H₂O 

CuO +H₂SO₄ →CuSO₄ +H₂O

CuSO₄ +BaCl₂ → BaSO₄ + CuCl₂

(1) 2Cu + O₂ ---t^o---> 2CuO

(2) CuO + 2HCl ---> CuCl₂ + H₂O

(3) CuCl₂ + 2NaOH ---> Cu(OH)₂ + 2NaCl

(4) \(Cu\left(OH\right)_2\overset{t^o}{--->}CuO+H_2O\)

(1) 4 NO2 +  O2 + 2 H2O -> 4 HNO3

(2)  Cu + 2 AgNO3 -> Cu(NO3)2 + 2 Ag

(3) Cu(NO3)2 +2 NaOH -> 2 NaNO3 + Cu(OH)2

(4) Cu(OH)2 + 2 HNO3 -> Cu(NO3)2 + 2 H2O

(5) 2 Cu(NO3)2 -to-> 2 CuO + 4 NO2 + O2

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