\(A=4^4\cdot9^5\)

\(=\left(2^2\right)^4\cdot\left(3^2\right)^5\)

\(=2^8\cdot3^{10}\)

Bài 2.23

2.24.

\(145=5.29\)

\(310=2.5.31\)

\(2020=2^2.5.101\)

Bài 2.24

\(A=4^4\cdot9^5=\left(2^2\right)^4\cdot\left(3^2\right)^5=2^8\cdot3^{10}\)

\(A=4^4\cdot9^5=2^8\cdot3^{10}\)

\(A=4^2\cdot6^3\)

\(A=\left(2^2\right)^2\cdot3^3\cdot2^3\)

\(A=2^4\cdot2^3\cdot3^3\)

\(A=2^{4+3}\cdot3^3\)

\(A=2^7\cdot3^3\)

TL

Bn cứ tự làm ik nhớ cho mik

Ht

Đã biết làm :

Ta có : A = 501 . 502 . 503 . ... . 1500 = \(\frac{1500!}{500!}=\left(1.4.7.....1498\right).\left(2.5.8.....1499\right).\frac{3.6.9.....1500}{1.2.3.....500}\)

=> A \(=\left(1.4.7.....1498\right).\left(2.5.8.....1499\right).\frac{3^{500}.\left(1.2.3.....500\right)}{1.2.3.....500}\)\(=\left(1.4.7.....1498\right).\left(2.5.8.....1499\right).3^{500}\)

Vậy A có 500 thừa số nguyên tố 3 khi tách A ra các thừa số nguyên tố

\(A=4^4\cdot9^5=\left(2^2\right)^4\cdot\left(3^2\right)^5=2^8\cdot3^{10}\)

\(A=4^4\cdot9^5\)

\(A=\left(2^2\right)^4\cdot\left(3^2\right)^5\)

\(A=2^{2\cdot4}\cdot3^{2\cdot5}\)

\(A=2^8\cdot3^{10}\)

=36 mũ 9 nhé