\(\dfrac{27^4.4^3}{9^5.8^2}\);\(\dfrac{3^{29}.4^{16}}{27^9.8^{11}}\)
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25 tháng 12 2021 lúc 13:09
1)\(\dfrac{27^4.4^3}{9^5.8^2}\)
2)\(\dfrac{8^5.3^{15}}{2^{14}.81^4}\)
\(1.\dfrac{27^4.4^3}{9^5.8^2}=\dfrac{3^{12}.2^6}{3^{10}.2^6}=3^2=9\)
\(2.\dfrac{8^5.3^{15}}{2^{14}.81^4}=\dfrac{2^{15}.3^{15}}{2^{14}.3^{16}}=\dfrac{2}{3}\)
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Ý 1:
\(\dfrac{27^4.4^3}{9^5.8^2}=\dfrac{\left(3^3\right)^4.\left(2^2\right)^3}{\left(3^2\right)^5.\left(2^3\right)^2}=\dfrac{3^{12}.2^6}{3^{10}.2^6}=3^2=9\)
Ý 2:
\(\dfrac{8^5.3^{15}}{2^{14}.81^4}=\dfrac{\left(2^3\right)^5.3^{15}}{2^{14}.\left(3^4\right)^4}=\dfrac{2^{15}.3^{15}}{2^{14}.3^{16}}=\dfrac{2^{14}.2.3^{15}}{2^{14}.3^{15}.3}=\dfrac{2}{3}\)
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Thực hiện các phép tính:
a)A=-4/5:6/5+3/4+1/2-(5/4:1/2)
b)B=2^5.8^4.4^3/16^6+2^3+(1/3)^2+(1/27)^0-3^5.(-25)^2/9^3.5^3
bài 1: thực hiện phép tính
a)\(\dfrac{2^5.8^4.4^3}{16^6}\)
b) \(\left(\dfrac{3}{5}-\dfrac{3}{4}\right).\left(\dfrac{2}{6}-\dfrac{1}{5}\right)^2\)
c)\(3.[\dfrac{-2}{5}]-\left(\dfrac{-1}{2}\right).4:\left(\dfrac{-1}{2}\right)^2\)
a: \(=\dfrac{2^5\cdot2^{12}\cdot2^6}{2^{24}}=\dfrac{1}{2}\)
b: \(=\dfrac{12-15}{20}\cdot\left(\dfrac{10-6}{30}\right)^2\)
\(=\dfrac{-3}{20}\cdot\left(\dfrac{2}{15}\right)^2=\dfrac{-3}{20}\cdot\dfrac{4}{225}=-\dfrac{1}{375}\)
c: \(=3\cdot\dfrac{2}{5}+2:\dfrac{1}{4}=1.2+8=9.2\)
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10 tháng 8 2023 lúc 14:09
9^4.4^5.25^3
-----------------
8^3 . 27^2 . 5^7
\(=\dfrac{3^8\cdot2^{10}\cdot5^6}{2^9\cdot3^6\cdot5^7}=3^2\cdot\dfrac{2}{5}=\dfrac{18}{5}\)
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\(\dfrac{9^4\cdot4^5\cdot25^3}{8^3\cdot27^2\cdot5^7}\)
\(=\dfrac{\left(3^2\right)^4\cdot\left(2^2\right)^5\cdot\left(5^2\right)^3}{\left(2^3\right)^3\cdot\left(3^3\right)^2\cdot5^7}\)
\(=\dfrac{3^8\cdot2^{10}\cdot5^6}{2^9\cdot3^6\cdot5^7}\)
\(=\dfrac{3^2\cdot2\cdot1}{1\cdot1\cdot5}\)
\(=\dfrac{18}{5}\)
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\(\dfrac{2^{10}.9^3}{6^5.8^2}\)
\(\frac{27^4\cdot4^3}{9^5.8^2}\)
\(\frac{27^4.4^3}{9^5.8^2}=\frac{\left(3^3\right)^4.\left(2^2\right)^3}{\left(3^2\right)^5.\left(2^3\right)^2}=\frac{3^{12}.2^6}{3^{10}.2^6}=3^2=9\)
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=\(\frac{3^{12}.2^6}{3^{15}.2^6}\)
=\(\frac{3^{12}}{3^{12}.3^3}\)
=\(\frac{1}{27}\)
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Tính giá trị biểu thức:
\(\frac{27^5.8^2-9^7.4^3}{6^6.9^2}\)
21 tháng 2 2022 lúc 17:01
dfrac{-1}{3}.dfrac{2}{5}dfrac{-3}{7}.dfrac{4}{15}dfrac{-9}{3}.dfrac{15}{27}dfrac{-5}{6}.( -12 )dfrac{-12}{4}.dfrac{8}{9}-3.dfrac{7}{6}dfrac{-15}{9}.dfrac{27}{5}-9.dfrac{4}{27}
Đọc tiếp
\(\dfrac{-1}{3}.\dfrac{2}{5}\)
\(\dfrac{-3}{7}.\dfrac{4}{15}\)
\(\dfrac{-9}{3}.\dfrac{15}{27}\)
\(\dfrac{-5}{6}.\)( -12 )
\(\dfrac{-12}{4}.\dfrac{8}{9}\)
\(-3.\dfrac{7}{6}\)
\(\dfrac{-15}{9}.\dfrac{27}{5}\)
\(-9.\dfrac{4}{27}\)
-2/15
-4/35
-5/3
10
-8/3
-7/2
-9
-4/3
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\(=\dfrac{-2}{15}\\ =\dfrac{-4}{35}\\ =-1\\ =10\\ =\dfrac{-8}{3}\\ =-7\\ =-9\\ =\dfrac{-4}{3}\)
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Xem thêm câu trả lời
\(\dfrac{3}{2.5}\)+\(\dfrac{3}{5.8}\)+\(\dfrac{3}{8.11}\)\(\dfrac{3}{11.14}\)+\(\dfrac{3}{14.17}\)<\(\dfrac{1}{2}\)
\(\dfrac{3}{2\cdot5}+\dfrac{3}{5\cdot8}+\dfrac{3}{8\cdot11}+\dfrac{3}{11\cdot14}+\dfrac{3}{14\cdot17}\)
= \(\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{17}\)
\(=\dfrac{1}{2}-\dfrac{1}{17}\)
\(=\dfrac{15}{34}\)
Vì \(\dfrac{15}{34}< \dfrac{1}{2}=>\dfrac{3}{2\cdot5}+\dfrac{3}{5\cdot8}+\dfrac{3}{8\cdot11}+\dfrac{3}{11\cdot14}+\dfrac{3}{14\cdot27}< \dfrac{1}{2}\)
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