(3x+2)3=11.121
giúp mik với mn ơi
(2x - 3) . 4,8 = ( 3x + 1 ) . (-2,4)
mn ơi, giúp mik vs nhanh hộ mik nha <3
\(\left(2x-3\right)\cdot4,8=\left(3x+1\right)\cdot\left(-2,4\right)\)
\(9,6x-14,4=-7,2x-2,4\)
\(9,6x+7,2x=14,4-2,4\)
\(16,8x=12\)
\(x=\dfrac{12}{16,8}=\dfrac{5}{7}\)
Chứng minh đẳng thức sau:
\(\frac{x^2+3x-4}{x-1}\)=\(x+4\) với \(x\)≠\(1\)
mn ơi giúp mik vs ạ
\(\dfrac{x^2+3x-4}{x-1}=\dfrac{x^2+4x-x-4}{\left(x-1\right)}=\dfrac{\left(x+4\right)\left(x-1\right)}{x-1}=x+4\)
Tìm đã thức M biết:
M-(2xy-4y^2+3x^2)=5xy+3/2x^2-6y^2=???
MN ơi giúp mik vs
Mik cảm ơn trước😘
\(M=5xy+\dfrac{3}{2}x^2-6y^2+2xy-4y^2+3x^2\)
\(M=\left(5xy+2xy\right)+\left(\dfrac{3}{2}x^2+3x^2\right)+\left(-6y^2-4y^2\right)\)
\(M=7xy+\dfrac{9}{2}y^2-10x^2\)
3x + 3x+2 = (-3)3 . (-10)
Mn giúp mik với ạ
\(3^x+3^{x+2}=\left(-3\right)^3.\left(-10\right)\\ \Leftrightarrow3^x+9.3^x=270\\ \Leftrightarrow10.3^x=270\\ \Leftrightarrow3^x=27\\ \Leftrightarrow3^x=3^3\\ \Leftrightarrow x=3\)
\(\Rightarrow3^x\left(1+3^2\right)=3^3\cdot10\\ \Rightarrow3^x\cdot10=3^3\cdot10\\ \Rightarrow x=3\)
(2¹⁷ + 17²) . (9¹⁵ - 3¹⁵) . (2⁴ - 4²)
= (2¹⁷ + 17²) . (9¹⁵ - 3¹⁵) . (16 - 16)
= (2¹⁷ + 17²) . (9¹⁵ - 3¹⁵) . 0
= 0
tìm x ;
X : 3 x 2 = 143
Mn ơi giúp mik với
\(x:3\times2=143\)
\(x:3=143:2\)
\(x:3=71,5\)
\(x=71,5\times3\)
\(x=214,5\)
1/2 x (x-2) + 1/3 (2-x) = x
MN ƠI GIÚP MIK CÂU NÀY VỚI AH
MIK CẢM ƠN!
\(\dfrac{1}{2}\left(x-2\right)+\dfrac{1}{3}\left(2-x\right)=x\\ \Leftrightarrow\dfrac{1}{2}\left(x-2\right)-\dfrac{1}{3}\left(x-2\right)=x\\ \Leftrightarrow\left(x-2\right).\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=x\\ \Leftrightarrow\left(x-2\right).\left(\dfrac{3-2}{6}\right)=x\\ \Leftrightarrow\left(x-2\right).\dfrac{1}{6}=x\\ \Leftrightarrow\dfrac{1}{6}x-\dfrac{1}{3}-x=0\\ \Leftrightarrow\left(\dfrac{1}{6}-1\right)x=\dfrac{1}{3}\\ \Leftrightarrow\left(\dfrac{1-6}{6}\right)x=\dfrac{1}{3}\\ \Leftrightarrow\dfrac{-5}{6}x=\dfrac{1}{3}\\ \Leftrightarrow x=\dfrac{1}{3}:\left(-\dfrac{5}{6}\right)\\ \Leftrightarrow x=-\dfrac{2}{5}\)
Vậy \(x=-\dfrac{2}{5}\)
y x 2 + y / (1/3) =20
Tìm y. Giúp mik với mn ơi!
y \(\times\) 2 +\(\dfrac{y}{\dfrac{1}{3}}\) = 20
\(y\times2+y\div\dfrac{1}{3}=20\)
\(y\times2+y\times3=20\)
\(y\times\left(2+3\right)=20\)
\(y\times5=20\)
\(y=20\div5\)
\(y=4\)
a)\(x=2\left(\sqrt{x-1}-\sqrt{x-2}\right)\)
b)\(\sqrt{5x^3+3x^2+3x-2}=\frac{1}{2}x^2+3x-\frac{1}{2}\)
mn ơi giúp mik vs ạ <3 !
a , \(x=2\left(\sqrt{x-1}-\sqrt{x-2}\right)\)
suy ra x =2
b, x=3
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