(3x-24) x 73 = 219
 3x - 24        = 3
 3x               = 27
   x               = 9
Vậy x = 9

(3x - 24)73 = 3.73

=> 3x - 24 = 3

=> x = 9

( 3x - 24 ) x 73 = 3 x 73

( 3x - 24 ) x 73 = 219

            3x - 24 = 219 : 73 

            3x - 24 = 3

                   3x = 3 + 24

                   3x = 27

                     x = 27 : 3

                     x = 9

45,65 x73 + 11 x91,3 + 45,65 x5

= 3332,45 + 1004,3 + 228,25

=4336,75 + 228,25

= 4565

45.65x73+11x91.3+45.65x5=4565

10000-47x72-47x28

=10000-47x72-47x47-28

=47x(10000-72-28)

=47x0

=0

MIK CHỈ GIẢI DƯỢC PHẦM ĐẦU THUI 
SORRY NHÉ

          = 47 x  (1000 - 72 - 28 )

          = 47 x 0 

          = 0

1000 - 47 . 72 - 47 .28

= 47 . ( 1000 - 72 -28 )

= 47 .0

=0

3457 - 27 . 48 - 48 .73 + 6543

=3457 - 48 . (27 + 73 ) + 6543

= 3457 - 4800 + 6543

= 5200

\(3x-24+3x^2=0\\ \Leftrightarrow x^2+x-8=0 \)

\(\Delta=1^2-4.\left(-8\right)=1+32=33\)

\(\Rightarrow\left\{{}\begin{matrix}x_1=\dfrac{-1-\sqrt{33}}{2}\\x_2=\dfrac{-1+\sqrt{33}}{2}\end{matrix}\right.\)

\(\Leftrightarrow x^2+x-8=0\)

\(\Leftrightarrow x^2+x+\dfrac{1}{4}-\dfrac{33}{4}=0\)

\(\Leftrightarrow\left(x+\dfrac{1}{2}\right)^2=\dfrac{33}{4}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{\sqrt{33}}{2}\\x+\dfrac{1}{2}=-\dfrac{\sqrt{33}}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\sqrt{33}-1}{2}\\x=\dfrac{-\sqrt{33}-1}{2}\end{matrix}\right.\)

\(3^{x+2}-3^x=72\)

\(\Rightarrow3^x\cdot\left(3^2-1\right)=72\)

\(\Rightarrow3^x\cdot\left(9-1\right)=72\)

\(\Rightarrow3^x\cdot8=72\)

\(\Rightarrow3^x=\dfrac{72}{8}\)

\(\Rightarrow3^x=9\)

\(\Rightarrow3^x=3^2\)

\(\Rightarrow x=2\)

_____

Xem lại đề 

\(5x-\left(24-2x\right)=\left(-24\right)+20+3x\)

\(5x+\left(-24\right)+2x=\left(-24\right)+20+3x\)

\(7x+\left(-24\right)=\left(-24\right)+20+3x\)

\(7x=20+3x\)

\(\left(7-3\right)x=20\)

\(4x=20\)

\(x=20:4\)

\(x=5\)

5x- (24 - 2x) = -24 + 20 + 3x

5x- 24 + 2x = -4 + 3x

5x + 2x - 3x = 24 - 4

4x = 20

x = 20 \(\div\)4

x = 5

Vậy x = 5

Ta có: \(5x-\left(24-2x\right)=-24+20+3x\)

\(\Leftrightarrow5x-24+2x=-24+20+3x\)

\(\Leftrightarrow5x+2x-3x=24-24+20\)

\(\Leftrightarrow4x=20\)

\(\Leftrightarrow x=\dfrac{20}{4}=5\)

Vậy: \(x=5\)

_Chúc bạn học tốt_

3^x+2 - 3^x =24

..............

➙ x =1

vậy x=1 

3^x+2- 3^x= 24

(=)3^x*3²-3^x=24

(=)3^x*3²-3^x*1=24

     3^x*(3²-1)=24

     3^x*(9-1)=24

     3^x*8=24

     3^x=24/8=3

=)x=1

=)