\(5x-\left(24-2x\right)=\left(-24\right)+20+3x\)
\(5x+\left(-24\right)+2x=\left(-24\right)+20+3x\)
\(7x+\left(-24\right)=\left(-24\right)+20+3x\)
\(7x=20+3x\)
\(\left(7-3\right)x=20\)
\(4x=20\)
\(x=20:4\)
\(x=5\)
5x- (24 - 2x) = -24 + 20 + 3x
5x- 24 + 2x = -4 + 3x
5x + 2x - 3x = 24 - 4
4x = 20
x = 20 \(\div\)4
x = 5
Vậy x = 5
Ta có: \(5x-\left(24-2x\right)=-24+20+3x\)
\(\Leftrightarrow5x-24+2x=-24+20+3x\)
\(\Leftrightarrow5x+2x-3x=24-24+20\)
\(\Leftrightarrow4x=20\)
\(\Leftrightarrow x=\dfrac{20}{4}=5\)
Vậy: \(x=5\)
_Chúc bạn học tốt_
5x - (24 -2x)= -24+20+3x
=>5x - 24 +2x = -4 +3x
(5x +2x)-24=-4 +3x
7x-24=-4+3x
=>4x-24=-4 (cả 2 vế cùng bớt 3x)
4x=-4+24=20
x=20:4=5
5x - (24 - 2x) = -24 + 20 +3x
\(\Rightarrow\)5x - 24 +2x = -24 + 20 + 3x
\(\Rightarrow \)5x - 3x + 2x = 24 -24 +20
\(\Rightarrow\)4x = 20 \(\Rightarrow \)x = 20:4= 5
Vậy x = 5