5 . \(x\) - 9 = 5 + 3 . \(x\)
(5\(x\) + 1)2 = \(\dfrac{36}{49}\)
2\(x - 1\) = 16
Những câu hỏi liên quan
\(5x-9=5+3x;2^3+0,5x=1,5;\left(5x+1\right)^2=\dfrac{36}{49};\left(\dfrac{-3}{81}\right)^x=-27;2^{x-1}=16\)
a: 5x-9=5+3x
=>5x-3x=5+9
=>2x=14
=>\(x=\frac{14}{2}=7\)
b: \(2^3+0,5x=1,5\)
=>0,5x+8=1,5
=>0,5x=1,5-8=-6,5
=>\(x=-6,5:0,5=-13\)
c: \(\left(5x+1\right)^2=\frac{36}{49}\)
=>\(\left[\begin{array}{l}5x+1=\frac67\\ 5x+1=-\frac67\end{array}\right.\Rightarrow\left[\begin{array}{l}5x=\frac67-1=\frac17\\ 5x=-\frac67-1=-\frac{13}{7}\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac17:5=\frac{1}{35}\\ x=-\frac{13}{7}:5=-\frac{13}{35}\end{array}\right.\)
d: \(\left(-\frac{3}{81}\right)^{x}=-27\)
=>\(\left(-\frac{1}{27}\right)^{x}=-27\)
=>\(x=-1\)
e: \(2^{x-1}=16\)
=>\(2^{x-1}=2^4\)
=>x-1=4
=>x=4+1=5(nhận)
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1: Tính : \(\dfrac{\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7.5^2+512}\) 2 . Tìm x biết :\(\left(5.x+1\right)^2=\dfrac{36}{49}\)
Bài 1:
\(\dfrac{\left(\dfrac{2}{5}\right)^7\cdot5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7\cdot5^2+512}\)
\(=\dfrac{\left(\dfrac{2}{5}\cdot5\right)^7+\left(\dfrac{9}{4}:\dfrac{3}{16}\right)^3}{2^7\cdot5^2+512}\)
\(=\dfrac{2^7+12^3}{2^7\cdot5^2+512}\)
\(=\dfrac{1856}{3712}\)
\(=0,5\)
Bài 2:
\(\left(5x+1\right)^2=\dfrac{36}{49}\)
\(\Rightarrow5x+1=\dfrac{6}{7}\)
\(\Rightarrow5x=\dfrac{-1}{7}\)
\(\Rightarrow x=\dfrac{-1}{35}\)
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tìm x
\([\dfrac{6:\dfrac{3}{5}-1\dfrac{1}{16}.\dfrac{16}{7}}{4\dfrac{1}{5}-\dfrac{10}{11}+5\dfrac{2}{11}}-\dfrac{\left(\dfrac{3}{20}+\dfrac{1}{2}-\dfrac{1}{5}\right).\dfrac{12}{49}}{3\dfrac{1}{3}+\dfrac{2}{9}}].x=2\dfrac{23}{96}\)
a,-12:(3/4-5/6)^2
,b,10.\(\sqrt{0.01}.\sqrt{\dfrac{16}{9}+3\sqrt{49}-\dfrac{1}{6}\sqrt{4}}\)
c,x/6=y/3=z/2 và x-2y+4z=8
d,|1/4+x|-1/3=2/5
a) \(\dfrac{x+3}{x-3}-\dfrac{x-3}{x+3}=\dfrac{36}{x^2-9}\)
b) \(\dfrac{2x-1}{x+4}-\dfrac{1-3x}{x-4}=5+\dfrac{96}{x^2-16}\)
c) \(\dfrac{x+3}{x+1}-\dfrac{x-1}{x}=\dfrac{3x^2+4x+1}{x\left(x+1\right)}\)
21 tháng 7 2023 lúc 7:14
bài 1 :tìm x,y biết
a) (5x+1)=\(\dfrac{36}{49}\) b) (x-2/9) = (2/3) c)(8x-1) 2x+1= 5^2 x+1
d) (x-3,5)^x+(y - 1/10)^4=0
`(5x+1)=36/49`
`<=> 5x = 36/49-1`
`<=> 5x = -13/49`.
`<=> x = -13/245.`
Vậy `x = -13/245`.
`b, x-2/9 = 2/3`.
`<=> x = 2/3 + 2/9`
`<=> x = 8/9`.
Vậy `x = 8/9`.
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c: (8x-1)^(2x+1)=5^(2x+1)
=>8x-1=5
=>8x=6
=>x=3/4
d: Sửa đề: (x-3,5)^2+(y-1/10)^4=0
=>x-3,5=0 và y-0,1=0
=>x=3,5 và y=0,1
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1. Tìm x, biết :
a) 27x : 3x 9
b) 25 : 5x 5
c) 2 : (x + 2)2 dfrac{1}{18}
d) (5x - 1)2 dfrac{36}{49}
e) left(dfrac{3}{4}right)^xdfrac{2^8}{3^4}
g) left(dfrac{-2}{5}right)^xdfrac{16}{625}
h) 5(x-2)(x+3)(-17)0
i) (x - 2)8(x - 2)6
k) (x + 1)7(x + 1)5
l) (3x - 1)2n+182n+1
Đọc tiếp
1. Tìm x, biết :
a) 27x : 3x = 9
b) 25 : 5x = 5
c) 2 : (x + 2)2 = \(\dfrac{1}{18}\)
d) (5x - 1)2 = \(\dfrac{36}{49}\)
e) \(\left(\dfrac{3}{4}\right)^x=\dfrac{2^8}{3^4}\)
g) \(\left(\dfrac{-2}{5}\right)^x=\dfrac{16}{625}\)
h) 5(x-2)(x+3)=(-17)0
i) (x - 2)8=(x - 2)6
k) (x + 1)7=(x + 1)5
l) (3x - 1)2n+1=82n+1
a) 27x : 3x = 9
(27 : 3)x = 9
9x = 91
x = 1
b) 25 : 5x =5
5x = 25 : 5
5x = 51
x = 1
c) 2 : (x + 2)2 = \(\dfrac{1}{18}\)
(x + 2)2 = 2 : \(\dfrac{1}{18}\)
(x + 2)2 = 36
\(\Rightarrow\left[{}\begin{matrix}x+2=6\\x+2=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4\\x=-8\end{matrix}\right.\)
d) (5x - 1)2 = \(\dfrac{36}{49}\)
(5x - 1)2 = \(\left(\dfrac{6}{7}\right)^2\)
Bạn làm tiếp nha, mình có việc bận :v
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Tính nhẩm:
7 x 8 = ..... 16 : 2 = ..... 36 : 6 = ..... 49 : 7 = .....
2 x 5 = ..... 72 : 8 = ..... 9 x 3 = ...... 63 : 7 = .....
6 x 4 = ..... 25 : 5 = ..... 4 x 8 = ...... 7 x 5 = ......
7 x 8 = 56 16 : 2 = 8 36 : 6 = 6 49 : 7 = 7
2 x 5 = 10 72 : 8 = 9 9 x 3 = 27 63 : 7 = 9
6 x 4 = 24 25 : 5 = 5 4 x 8 = 32 7 x 5 = 35
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7 x 8 = 56
2 x 5 = 10
6 x 4 = 24
16 : 2 = 8
72 : 8 = 9
25 : 5 = 5
36 : 6 = 6
9 x 3 = 27
4 x 8 = 32
49 : 7 = 7
63 : 7 = 9
7 x 5 = 35
Tìm x biết:
\(7^{2+x}+2\times7^{x-1}=345\)
\(81^{-2\times x}\times27^x=9^5\)
\(\left(\dfrac{1}{3}-\dfrac{1}{2}\right)^{x-1}=\dfrac{1}{36}\)
\(\dfrac{25}{5^x}=\dfrac{1}{125}\)
\(\dfrac{\left(-7\right)^{2\times x-1}}{49}=-343\)
a: \(\Leftrightarrow7^x\cdot49+7^x\cdot\dfrac{2}{7}=345\)
\(\Leftrightarrow7^x=7\)
hay x=1
c: \(\left(\dfrac{1}{3}-\dfrac{1}{2}\right)^{x-1}=\dfrac{1}{36}\)
\(\Leftrightarrow\left(-\dfrac{1}{6}\right)^{x-1}=\left(-\dfrac{1}{6}\right)^2\)
=>x-1=2
hay x=3
d: \(\dfrac{25}{5^x}=\dfrac{1}{125}\)
\(\Leftrightarrow5^x=5^2\cdot5^3=5^5\)
hay x=5
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