Tính nhanh:
a) \(38.42\) b) \({102^2}\) c) \({198^2}\) d) \({75^2} - {25^2}\)
Tính nhanh:
a) \(82.78\) b) \(87.93\) c) \({125^2} - {25^2}\)
a) \(82\cdot78\)
\(=\left(80+2\right)\cdot\left(80-2\right)\)
\(=80^2-2^2\)
\(=6400-4\)
\(=6396\)
b) \(87\cdot93\)
\(=\left(90-3\right)\left(90+3\right)\)
\(=90^2-3^2\)
\(=8100-9\)
\(=8091\)
c) \(125^2-25^2\)
\(=\left(125-25\right)\left(125+25\right)\)
\(=100\cdot150\)
\(=15000\)
1. Tính nhanh:
a) 32 + 89 + 68 b) 64 + 112 + 236 c) 1350 + 360 + 650 + 40
2. Tính nhanh:
a) 25 . 64 . 4 b) 25 . 5 . 4 . 2 c) 25 . 50 . 4 . 20
d) 32 . 47 + 32 . 53 e) 15 . 145 – 15 . 45 + 500
3. Tìm số tự nhiên x, biết:
a) 23 . (42 – x) = 23 b) 15 . (x – 3) = 30
4. Tìm số tự nhiên x, biết:
a) 119 – x = 97 c) (15 . x) : 60 = 3
b) x : 15 = 0 d) 241 + (107 – x) = 260
5. Tìm số tự nhiên x, biết:
a) x – 57 = 63 c) 7 . x : 28 = 5
b) 119 – x = 97 d) 1751 : x = 103
6. Bạn Bo cần mua tem loại 800 đồng với số tiền hiện có là 2500 đồng. Bạn Bo có thể mua tối đa bao nhiêu tem:
Bài 3:
a: Ta có: \(23\left(42-x\right)=23\)
\(\Leftrightarrow42-x=1\)
hay x=41
b: Ta có: 15(x-3)=30
nên x-3=2
hay x=5
Bài 1:
a: 32+89+68=100+89=189
b: 64+112+236=300+112=412
c: \(1350+360+650+40=2000+400=2400\)
tính nhanh
a) 60-26.75-13.25
b)45.78+38.42-25.78-18.42
c)72.9*99+72+0.9
d)3.4*4+1.7*8+3.4*2
a 60 - 26,75 - 13,25
= 60 - ( 26,75 + 13,25 )
= 60 - 40
= 20
b ) 45,78 + 38,42 - 25,78 - 18,42
= ( 45,78 - 25,78 ) + ( 38,42 - 18,42 )
= 20 + 20
= 40
a,60-26.75-13.25
=60-26.3.25-13.25
=60-78.25-13.25
=60-25.(78+13)
=60-2275
=-2215
Tính nhanh
A.996+44
B.37+198
C.4×55×25×2×5
D.97×36+64×97
E.125+360+75+40
G.10^12÷10^10
a, = 996 + 4 + 40 = 1000 + 40 = 1040
b, = 198 + 2 + 35 = 200 + 35 = 235
c, = ( 4 *25 )*(2 * 5)*55=100 * 10 * 55 = 55000
d, = 97*(36+64) = 97 * 100 = 9700
e, = (125+75)+(360+40)= 200 + 400 = 600
g, =10^2=100
a) \(996+44\)
\(=1040\)
b) \(37+198\)
\(=230\)
\(a,996+44=1040\)
\(d,97.36+64.97=97.\left(36+64\right)=97.100=9700\)
\(b,37+198=235\)
\(c,4.55.25.2.5=220.50.5=11000.5=55000\)
\(e,125+360+75+40=485+115=600\)
\(g,10^{12}:10^{10}=10^2=100\)
Bài 1: Thực hiện phép tính:
a, 1,3 + 2,5 – 4,7 + 5,6 – 4,3
b, - 5,7 + 4,2 – 8,2 + 11,7
c, 25.(- 0,8).4.(-0,5).0,224
Bài 2: Tìm x, biết:
a, | b, |
c, | d, |
Bài 3: Tính nhanh:
a, -13,45 – 7,98 – 8,55
b, 9,72 + 8,38 + 3,62
c,
d, 31,71 – 7,41.15 – 2,59.15
Bài 1: Thực hiện phép tính:
\(\text{a, 1,3 + 2,5 – 4,7 + 5,6 – 4,3=}0,4\)
\(\text{b, - 5,7 + 4,2 – 8,2 + 11,7}=2\\ \)
\(\text{c, 25.(- 0,8).4.(-0,5).0,224}=8,96\)
Bài 3: Tính nhanh:
\(\text{a, -13,45 – 7,98 – 8,55}=-29,98\)
\(\text{b, 9,72 + 8,38 + 3,62}=21,72\)
\(c,\)\(\)\(\left| {45,37} \right| - \left| { - 29,73} \right| + \left( { - 12,27} \right)\)\(=45,37-29,73-12,27=3,38\)
\(\text{d, 31,71 – 7,41.15 – 2,59.15}=-118,29\)
Bài 1:
a) \(1,3+2,5-4,7+5,6-4,3\)
\(=\left(1,3+2,5+5,6\right)+\left(-4,7-4,3\right)\)
\(=9,4+\left(-9\right)\)
\(=0,4\)
b) \(-5,7+4,2-8,2+11,7\)
\(=\left(-5,7+11,7\right)+\left(4,2-8.2\right)\)
\(=6+\left(-4\right)\)
\(=2\)
c) \(25.\left(-0,8\right).4.\left(-0,5\right).0,224\)
\(=\left(25.4\right).\left(-0,8.-0,5\right).0,224\)
\(=100.0,4.0,224\)
\(=40.0,224\)
\(=8,96\)
Bài 1. Rút gọn biểu thức:
b) A=(u-v)3+3uv(u+v)
c) C=6(c-d)(c+d)+2(c-d)2-(c-d)3
Bài 2. Tính nhanh:
a) 1013 b) 2993 c) 993
Bài 2.
a) 1013 = (100+1)3 = 1003+3.1002.1+3.100.12+13
= 1000000+30000+300+1 = 1030301
b) 2993 = (300-1)3 = 3003-3.3002.1+3.300.12-13
= 27000000 - 270000 + 900 -1 = 26730899
c) 993 = (100-1)3 = 1003-3.1002.1+3.100.12-1
= 1000000 - 30000 + 300 -1 = 970299
\(1,\\ b,A=\left(u-v\right)^3+3uv\left(u+v\right)\\ A=u^3-3u^2v+3uv^2-v^3+3u^2v+3uv^2=u^3-v^3\\ c,6\left(c-d\right)\left(c+d\right)+2\left(c-d\right)^2-\left(c-d\right)^3\\ =6c^2-6d^2+2c^2-4cd+2d^2-c^3+3c^2d-3cd^2+d^3\\ =8c^2-c^3-4d^2-4cd+3c^2d-3cd^2+d^3\)
\(2,\\ a,101^3=\left(100+1\right)^3\\ =100^3+3\cdot10000\cdot1+3\cdot100\cdot1+1\\ =1000000+30000+300+1=1030301\\ b,299^3=\left(300-1\right)^3\\ =300^3-3\cdot90000\cdot1+3\cdot300\cdot1-1\\ =27000000-270000+900-1\\ =26730899\\ c,99^3=\left(100-1\right)^3\\ =100^3-3\cdot10000\cdot1+3\cdot100\cdot1-1\\ =1000000-30000+300-1=970299\)
Bài 1:
a.
$A=u^3-3u^2v+3uv^2-v^3+3uv^2+3u^2v$
$=u^3+6uv^2-v^3$
c.
$C=(c-d)[6(c+d)+2(c-d)-(c-d)^2]$
$=(c-d)[8c+4d-(c^2-2cd+d^2)]=(c-d)(-c^2+2cd-d^2+8c+4d)$
bài5
a, 20 - [30 - (5 - 1)2 ]
b, 71 + 50 : [5 + 3. (57 - 6.7)]
c, 4.{270 : [50 - (25 + 45 : 5)]}
d. 411 - [(107 + 3) : 5 - 22 ]
e, 450 - 5. [32. (75 : 73 - 41) - 12] + 18
f, 102 - 150 : [18 - 2. (10 - 8)2 ] + 10180
a: \(20-\left[30-\left(5-1\right)^2\right]\)
\(=20-\left[30-4^2\right]\)
\(=20-14=6\)
b: \(71+\dfrac{50}{5+3\left(57-6\cdot7\right)}\)
\(=71+\dfrac{50}{5+3\cdot\left(57-42\right)}\)
\(=71+\dfrac{50}{5+3\cdot15}=71+\dfrac{50}{50}=72\)
c: \(4\cdot\left\{270:\left[50-\left(2^5+45:5\right)\right]\right\}\)
\(=4\cdot\left\{270:\left[50-32-9\right]\right\}\)
\(=4\cdot\left\{\dfrac{270}{50-41}\right\}=4\cdot\dfrac{270}{9}=4\cdot30=120\)
d: \(411-\left[\dfrac{\left(107+3\right)}{5}-2^2\right]\)
\(=411-\left[\dfrac{110}{5}-4\right]\)
=410-22+4
=410-18
=392
e: \(450-5\left[3^2\left(7^5:7^3-41\right)-12\right]+18\)
\(=450-5\left[9\cdot\left(7^2-41\right)-12\right]+18\)
\(=450-5\cdot\left[9\cdot8-12\right]+18\)
=468-5*60
=468-300
=168
f:
\(102-150:\left[18-2\cdot\left(10-8\right)^2\right]+1018^0\)
\(=102-150:\left[18-2\cdot4\right]+1\)
\(=103-\dfrac{150}{18-8}=103-15=88\)
Bài 1. Rút gọn biểu thức:
a) A=(a+b)3-(a-b)3
b) A=(u-v)3+3uv(u+v)
c) C=6(c-d)(c+d)+2(c-d)2-(c-d)3
Bài 2. Tính nhanh:
a) 1013 b) 2993 c) 993
a. A = (a + b)3 - (a - b)3
A = \(\left[\left(a+b\right)-\left(a-b\right)\right]\left[\left(a+b\right)^2+\left(a+b\right)\left(a-b\right)+\left(a-b\right)^2\right]\)
A = (a + b - a + b)\(\left[a^2+2ab+b^2+a^2-b^2+a^2-2ab+b^2\right]\)
A = 2b(a2 + a2 + a2 + 2ab - 2ab + b2 - b2 + b2)
A = 2b(3a2 + b2)
A = 6a2b + 2b3
Tính nhanh:
a) (1/2 : 50% - 1/4 : 25% + 1/8 : 12,5 - 1/10 : 10%) : 1 + 2 + 3 + ... 2006 + 2007 + 2008)
c) 8,1 : 0,6 x 1875 + 1,5 x 625 x 9
a: \(=\dfrac{\left(\dfrac{1}{2}:\dfrac{1}{2}-\dfrac{1}{4}:\dfrac{1}{4}+\dfrac{1}{8}:\dfrac{1}{8}-\dfrac{1}{10}:\dfrac{1}{10}\right)}{1+2+3+...+2008}\)
=0
c: =8,1*5/3*1875+13,5*625
=13,5(1875+625)
=13,5*2500
=33750