a) \(\dfrac{6}{13}:\left(\dfrac{1}{2}-x\right)=\dfrac{15}{39}\)

\(\dfrac{1}{2}-x=\dfrac{6}{13}:\dfrac{15}{39}\)

\(\dfrac{1}{2}-x=\dfrac{6}{5}\)

\(x=\dfrac{1}{2}-\dfrac{6}{5}\)

\(x=-\dfrac{7}{10}\)

b) \(3\times\left(\dfrac{x}{4}+\dfrac{x}{28}+\dfrac{x}{70}+\dfrac{x}{130}\right)=\dfrac{60}{13}\)

\(3\times x\times\left(\dfrac{1}{4}+\dfrac{1}{28}+\dfrac{1}{70}+\dfrac{1}{130}\right)=\dfrac{60}{13}\)

\(x\times\left(\dfrac{3}{1\times4}+\dfrac{3}{4\times7}+\dfrac{3}{7\times10}+\dfrac{3}{7\times13}\right)=\dfrac{60}{13}\)

\(x\times\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}\right)=\dfrac{60}{13}\)

\(x\times\left(1-\dfrac{1}{13}\right)=\dfrac{60}{13}\)

\(x\times\dfrac{12}{13}=\dfrac{60}{13}\)

\(x=\dfrac{60}{13}:\dfrac{12}{13}\)

\(x=5\)

Lời giải:
$200-18:(42:3\times x-13)-28=154$

$200-28-18:(42:3\times x-13)=154$

$172-18:(42:3\times x-13)=154$

$18:(42:3\times x-13)=172-154=18$

$42:3\times x-13=18:18=1$

$14\times x-13=1$

$14\times x=13+1=14$

$x=14:14=1$

\(200-18:\left(42:3\times x-13\right)-28=154\)

\(200-18:\left(42:3\times x-13\right)=182\)

\(18:\left(42:3\times x-13\right)=200-182\)

\(18:\left(42:3\times x-13\right)=18\)

\(42:3\times x-13=18:18\)

\(42:3\times x-13=1\)

\(42:3\times x=1+13\)

\(42:3\times x=14\)

\(14\times x=14\)

\(x=14:14\)

\(x=1\)

Ta có: \(200-18:\left(42:3x-13\right)-28=154\)

\(\Leftrightarrow172-18:\left(42:3x-13\right)=154\)

\(\Leftrightarrow18:\left(42:3x-13\right)=18\)

\(\Leftrightarrow42:3x-13=1\)

\(\Leftrightarrow42:3x=14\)

\(\Leftrightarrow3x=3\)

hay x=1

a) Ta có : ( x + 1 ).( 3 - x ) > 0

Th1 : \(\hept{\begin{cases}x+1>0\\3-x>0\end{cases}\Rightarrow\hept{\begin{cases}x>-1\\x>3\end{cases}\Rightarrow}x>3}\)

Th2 : \(\hept{\begin{cases}x+1< 0\\3-x< 0\end{cases}\Rightarrow\hept{\begin{cases}x< -1\\x< 3\end{cases}\Rightarrow}x< -1}\)

sao ko ai làm giúp mk vậy

(13 - x) x 28 = 28

13 - x = 28 : 28

13 - x = 1

x = 13 - 1

x = 12

( 13 - x ) . 28 = 28 

<=> 13 - x     = 28 : 28 

<=>       x     = 13 - 1 

<=>      x      = 12 

^^ Học tốt nhá!!! 

\(\left(13-x\right).28=28\)

\(13-x=28:28\)

\(13-x=1\)

\(x=13-1\)

\(x=12\)

hoặc Phương Annie tìm trên đây nha:

Giải toán trên mạng - Giúp tôi giải toán - Hỏi đáp, thảo luận về toán học - Học toán với OnlineMath

\(2x+3=15\\ \Rightarrow2x=15-3=12\\ \Rightarrow x=\dfrac{12}{2}=6\\ ---\\ 28-3x=13\\ \Rightarrow3x=28-13=15\\ \Rightarrow x=\dfrac{15}{3}=5\\ ---\\ \left(x-1954\right).5=50\\ \Rightarrow x-1954=50:5=10\\ \Rightarrow x=10+1954=1964\\ ---\\ x-152:2=46\\ \Rightarrow x-76=46\\ \Rightarrow x=46+76=122\)

a, 2\(x\) + 3 = 15

     2\(x\)       = 12

        \(x\)      = 6

b, 28 - 3\(x\) = 13

           3\(x\) = 28 - 13

           3\(x\)  = 15

             \(x\)   = 5

a) 

\(2x+3=15\)

\(2x=15-3\)

\(2x=12\)

\(x=12:2\)

\(x=6\)

b) \(28-3x=13\)

\(3x=28-13\)

\(3x=15\)

\(x=15:3\)

\(x=5\)

c) \(\left(x-1954\right).5=50\)

\(x-1954=50:5\)

\(x-1954=10\)

\(x=10+1954\)

\(x-1964\)

d) \(x-152:2=46\)

\(x-152=46.2\)

\(x-152=92\)

\(x=92+152\)

\(x=244\)

a,-6x=-96

x=16

b,\(|x|\)=2

x=2 hoặc x=-2

c,28+2x=48

2x=20

x=10

/ là phân số nha

11/13-(5/42-x)=(15/28-11/13)

11/13-(5/42-x)=-37/182

(5/42-x)=11/13+37/182

(5/42-x)=191/182

x=5/42-191/182

x=-254/273

vậy x=-254/273

bạn ấn vào chữ M nằm ngang ở dưới câu hỏi khi bạn trả lời là sẽ ấn được phân số nhé 

còn gửi câu trả lời cũng tương tự 

\(b,x+\frac{1}{3}=\frac{2}{5}-\left(-\frac{1}{3}\right)\)

\(< =>x+\frac{1}{3}=\frac{2}{5}+\frac{1}{3}\)

\(< =>x=\frac{1}{3}-\frac{1}{3}+\frac{2}{5}=\frac{2}{5}\)

\(c,\frac{2}{3}x+\frac{5}{7}=\frac{3}{10}\)

\(< =>\frac{2}{3}x=\frac{3}{10}-\frac{5}{7}=-\frac{29}{70}\)

\(< =>x=\frac{-29}{70}:\frac{2}{3}=-\frac{7}{140}\)

\(d,\frac{3}{7}-x=\frac{1}{4}-\left(-\frac{3}{5}\right)\)

\(< =>\frac{3}{7}-\frac{1}{4}-\frac{3}{5}=x\)

\(< =>x=-\frac{59}{140}\)

\(e,-\frac{21}{12}x+\frac{1}{3}=-\frac{2}{3}\)

\(< =>-\frac{21}{12}x=-\frac{2}{3}-\frac{1}{3}=-1\)

\(< =>x=\frac{12}{21}\)

a: =>3(x+4)=115

=>x+4=115/3

hay x=103/3

b: =>\(8^3\cdot\left(12x-64\right)=4\cdot8^4\)

\(\Leftrightarrow12x-64=32\)

=>12x=96

hay x=8

c: \(\Leftrightarrow\left(4x+28\right)\cdot23+55=175\)

=>(4x+28)x23=120

=>4x+28=120/23

=>4x=-524/23

hay x=-131/23