Chuỗi 1:

\(\left(1\right)CaCO_3\rightarrow\left(t^o\right)CaO+CO_2\\ \left(2\right)CaO+3C\rightarrow\left(2000^oC,lò.điện\right)CaC_2+CO\uparrow\\ \left(3\right)CaC_2+2H_2O\rightarrow C_2H_2+Ca\left(OH\right)_2\\ \left(4\right)C_2H_2+H_2\rightarrow\left(Ni,t^o\right)C_2H_4\\ \left(5\right)C_2H_4+H_2O\rightarrow\left(t^o,H^+\right)C_2H_5OH\\ \left(6\right)C_2H_5OH+2NaOH+CH_3COOH\rightarrow CH_3COONa+C_2H_5ONa+2H_2O\)

\(2C_4H_{10}+5O_2\underrightarrow{t^o}4CH_3COOH+2H_2O\)

\(CH_3COOH+C_2H_5OH\xrightarrow[H_2SO_4đặc]{t^o}CH_3COOC_2H_5+H_2O\)

CH₃COOC₂H₅ + NaOH \(\rightarrow\) CH₃COONa + C₂H₅OH

\(C_2H_5OH+3O_2\underrightarrow{t^o}2CO_2+3H_2O\)

CaC₂ + 2H₂O\(\rightarrow\) C₂H₂ + Ca(OH)₂

\(C_2H_2+H_2\underrightarrow{t^o}C_2H_4\)

\(C_2H_4+H_2O\underrightarrow{axit}C_2H_5OH\)

\(C_2H_5OH+3O_2\underrightarrow{t^o}2CO_2+3H_2O\)

CO₂ + 2NaOH \(\rightarrow\) Na₂CO₃ + H₂O

2CH₃COOH + Na₂CO₃ \(\rightarrow\) 2CH₃COONa + CO₂ + H₂O

\(a,-\left(-C_6H_{10}O_5-\right)-_n+nH_2O\rightarrow nC_6H_{12}O_6\\ C_6H_{12}O_6\underrightarrow{\text{men rượu}}2C_2H_5OH+2CO_2\uparrow\\ C_2H_5OH+O_2\underrightarrow{\text{men giấm}}CH_3COOH+H_2O\\ CH_3COOH+C_2H_5OH\xrightarrow[H_2SO_{4\left(đ\right)}]{t^o}CH_3COOC_2H_5+H_2O\)

\(b,C_{12}H_{22}O_{11}+H_2O\xrightarrow[t^o]{H^+}C_6H_{12}O_6+C_6H_{12}O_6\)

Mấy pthh sau giống ở trên á bạn

a) CaC2 + 2H2O --> Ca(OH)2 + C2H2

C2H2 + H2 -Ni-> C2H4

C2H4 + H2O --> C2H5OH

C2H5OH + O2 -mg-> CH3COOH + H2O

CH3COOH + C2H5OH <-H2SO4đ,to-> CH3COOC2H5 + H2O

b) (-C6H10O5-)n + nH2O -axit-> nC6H12O6

C6H12O6 -mr-> 2C2H5OH + 2CO2

C2H5OH + O2 -mg-> CH3COOH + H2O

CH3COOH + C2H5OH <-H2SO4đ,to-> CH3COOC2H5 + H2O

CH3COOC2H5 + NaOH -to-> CH3COONa + C2H5OH

a/ CaC2 + 2H2O => Ca(OH)2 + C2H2

C2H2 + H2 => (Pd,t^o) C2H4

C2H4 + H2O => (140^oC,H2SO4đ) C2H5OH

C2H5OH + O2 => (men giấm) CH3COOH + H2O

CH3COOH + C2H5OH => (H2SO4đ,t^o,pứ hai chiều) CH3COOC2H5 + H2O: pứ este hóa

B/ (-C6H10O5-)n + nH2O => (axit,t^o) nC6H12O6

C6H12O6 => (men rượu,t^o) 2CO2 + 2C2H5OH

C2H5OH + O2 => (men giấm) CH3COOH + H2O

CH3COOH + C2H5OH => (H2SO4đ,t^o) CH3COOC2H5 + H2O : pứ hai chiều

CH3COOC2H5 + NaOH => (t^o) CH3COONa + C2H5OH

$C_2H_4 + H_2O \xrightarrow{t^o,H^+} C_2H_5OH$
$C_2H_5OH + CH_3COOH \buildrel{{H_2SO_4}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$
$CH_3COOC_2H_5 + H_2O \buildrel{{H_2SO_4}}\over\rightleftharpoons CH_3COOH + C_2H_5OH$

$2CH_3COOH + Mg \to (CH_3COO)_2Mg + H_2$
$(CH_3COO)_2Mg + Ca(OH)_2 \to (CH_3COO)_2Ca + Mg(OH)_2$

$(CH_3COO)_2Ca + K_2CO_3 \to 2CH_3COOK + CaCO_3$

$C_6H_{12}O_6 \xrightarrow{t^o,men\ rượu} 2CO_2 + 2C_2H_5OH$

$C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O$

$C_2H_5OH + CH_3COOH \buildrel{{H_2SO_4}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$
$CH_3COOC_2H_5 + H_2O \buildrel{{H_2SO_4}}\over\rightleftharpoons CH_3COOH + C_2H_5OH$

$2CH_3COOH + CuO \to (CH_3COO)_2Cu + H_2O$

$(CH_3COO)_2Cu + NaOH \to 2CH_3COONa + Cu(OH)_2$

\(\left(1\right)\) \(C_6H_{12}+3H_2O\underrightarrow{axit}3C_2H_5OH\)

\(\left(2\right)\) \(C_2H_5OH+O_2\underrightarrow{mengiấm}CH_3COOH+H_2O\)

\(\left(3\right)\) \(CH_3COOH+C_2H_5OH⇌^{H_2SO_4đ,t^o}CH_3COOC_2H_5+H_2O\)

\(\left(4\right)\) \(CH_3COOC_2H_5+NaOH\rightarrow CH_3COONa+C_2H_5OH\)

 C2H5OH + O2 → CH3COOH + H2O

CH3COOH + C2H5OH → CH3COOC2H5 +H2O

CH3COOC2H5 + NaOH → C2H5OH + CH3COONa

C2H4 + H2O - 170⁰C , H2SO4-> C2H5OH 

C2H5OH + O2 -men giấm-> CH3COOH + H2O 

CH3COOH + C2H5OH <-H2SO4đ, to-> CH3COOC2H5 + H2O 

CH3COOC2H5 + NaOH => CH3COONa + C2H5OH 

C2H4 + H20 →(xúc tác H2SO4) C2H5OH

C2H5OH + O2 →(xúc tác men giấm) CH3COOH + H20

CH3COOH + C2H5OH → CH3COOC2H5 + H20

 CH3COOC2H5 + NaOH →(to) CH3COONa + C2H5OH

(1) C2H4 + H2O -xt H2SO4, t^o cao ----> C2H5OH

(2) C2H5OH + O2 ---men giấm ----> CH3COOH + H2O

(3) CH3COOH + C2H5OH \(⇌\) CH3COOC2H5 + H2O (xt: H⁺ và nhiệt độ)

(4) CH3COOC2H5 + NaOH -> CH3COONa + C2H5OH

C₂H₆ \(\underrightarrow{t^o}\) C₂H₄

C₂H₄ + H₂O \(\underrightarrow{axit}\) C₂H₅OH

C₂H₅OH + O₂ \(\underrightarrow{mengiam}\)CH₃COOH

CH₃COOH + C₂H₅OH → CH₃COOC₂H₅ + H₂O

NaOH + CH₃COOC₂H₅ → C₂H₅OH + CH₃COONa