Question

C6H12 ---> C2H5OH ---> CH3COOH --->CH3COOC2H5---> CH3COONA

Answer 1

\(\left(1\right)\) \(C_6H_{12}+3H_2O\underrightarrow{axit}3C_2H_5OH\)

\(\left(2\right)\) \(C_2H_5OH+O_2\underrightarrow{mengiấm}CH_3COOH+H_2O\)

\(\left(3\right)\) \(CH_3COOH+C_2H_5OH⇌^{H_2SO_4đ,t^o}CH_3COOC_2H_5+H_2O\)

\(\left(4\right)\) \(CH_3COOC_2H_5+NaOH\rightarrow CH_3COONa+C_2H_5OH\)

Answer 2

 C2H5OH + O2 → CH3COOH + H2O

CH3COOH + C2H5OH → CH3COOC2H5 +H2O

CH3COOC2H5 + NaOH → C2H5OH + CH3COONa