Tìm x biết:
x-1/1/5x=60%
Tìm x,biết:
x(x+1)-(x-1)(x+2)=8
x(x+1)-(x-1)(x+2)=8
\(\Leftrightarrow\)\(x^2+x-x^2-2x+x+2=8\)
\(\Leftrightarrow0x=6\left(ptvn\right)\)
\(\Rightarrow S=\varnothing\)
Tìm x,biết:
x * 103 - x * 1 - x : 0,01=44,8
\(x\times103-x\times1-x:0,01=44,8\)
\(x\times103-x\times1-x:\dfrac{1}{100}=44,8\)
\(x\times103-x\times1-x\times100=44,8\)
\(x\times\left(103-1-100\right)=44,8\)
\(x\times2=44,8\)
\(x=44,8:2\)
\(x=22,4\)
= x x 103 - x x 1 - x x 100 = 44,8
\(x\left(103-1-100\right)=44,8\)
\(x\times2=44,8\)
\(x=22,4\)
= x x 103 - x x 1 - x x 100 = 44,8
x(103−1−100)=44,8�(103−1−100)=44,8
x×2=44,8�×2=44,8
x=22,4
Tìm x, biết:
x+(x+1)+(x+2)+...+(x+30)=1240
`x+(x+1)+(x+2)+...+(x+30)=1240`
`=> (x + x + x + ... + x) + (1 + 2 + 3 +... + 30) = 1240`
`=> 31x + 465 = 1240`
`=> 31 x = 1240 - 465`
`⇒ 31x = 775`
`⇒ x = 775 : 31`
`⇒ x = 25`
\(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\\ \left(x+x+...+x\right)+\left(1+2+...+30\right)=1240\\ 31x+465=1240\\ 31x=1240-465\\ 31x=775\\ x=775:31\\ x=25\)
\(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(\Leftrightarrow\left(x+x+...+x\right)+\left(1+2+...+30\right)=1240\)
\(\Leftrightarrow31x+465=1240\)
\(\Leftrightarrow x=25\)
tìm x biết:x+1/2+x+1/3+x+1/4+x+1/5=x+1/6
\(\Rightarrow x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}-x+\frac{1}{6}=0\)
\(\Rightarrow3x+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}\)
k cho minh
\(x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}=x+\frac{1}{6}\)
\(\Leftrightarrow x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}-x-\frac{1}{6}=0\)
\(\Leftrightarrow3x+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}-\frac{1}{6}=0\)
Tính ra nhé !
\(x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}=x+\frac{1}{6}\)
\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}\right)=x+\frac{1}{6}\)
\(\Rightarrow4x+\frac{77}{60}=x+\frac{1}{6}\)
\(\Rightarrow3x=\frac{1}{6}-\frac{77}{60}\)
\(\Rightarrow3x=-\frac{67}{60}\)
\(\Rightarrow x=-\frac{67}{60}\div3=\frac{-67}{60.3}=-\frac{67}{180}\)
Vậy x = .........
Tìm x,biết:
x +1 : 0, 75 =1, 4 : 0, 25
x + 1 : 0,75 = 1,4 : 0,25
<=> \(x+\dfrac{4}{3}=5,6\)
<=> \(x=\dfrac{64}{15}\)
tìm x biết:x(x-3)-x(x+1)=12
x(x-3)-x(x+1)=12
<=>x2-3x-x2-x=12
<=>-4x=12
<=>x=-3
Tìm X, biết:
X + (X + 1) + (X + 2) + (X + 3) + ...+ (X + 19) = 950
=>20x+190=950
=>20x=760
hay x=38
`20x+190=950`
`20x=760`
`x= 760: 20`
`x= 38`
20 x X = 950 - (1 + 2 + 3 + 4 + 5 + ... + 19)
20 x X = 950 - 190
20 x X = 760
X = 760 : 20
X = 38
Tìm x biết:x+(x-1)+(x-2)+.......+(x-50)=255
x+(x-1)+(x-2)+....+(x-50)=225
<=>x+x-1+x-2+...+x-50=225
<=>51x-1275=225
<=>51x=-1050
bạn nè, câu trả lời của Nguyễn Quốc Khánh là sai đó
tìm x biết:x-1/x+2=x-2/x+3
x³ - x² - x = 1/3
<=> x³ = x² + x + 1/3
<=> 3x³ = 3(x² + x + 1/3)
<=> 3x³ = 3x² + 3x + 1
<=> 3x³ + x³ = x³ + 3x² + 3x + 1
<=> 4x³ = (x + 1)³
<=> ³√(4x³) = ³√(x + 1)³
<=> ³√4.x = x + 1
<=> ³√4.x - x = 1
<=> x(³√4 - 1) = 1
<=> x = 1/(³√4 - 1)
Ta có \(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(\Rightarrow\left(x-1\right)\left(x+3\right)=\left(x+2\right)\left(x-2\right)\)
\(\Rightarrow x^2+2x-3=x^2-4\)
\(\Rightarrow x^2-x^2+2x=-4+3\)
\(\Rightarrow2x=-1\)
\(\Rightarrow x=-\frac{1}{2}\)
Vậy \(x=-\frac{1}{2}\)
Tìm x biết:X x (1/2+1/3+1/6)=425