Bài 1:

Ý 1)

\(a,Mg+H_2SO_4\rightarrow MgSO_4+H_2\\ b,\left(1\right)4K+O_2\rightarrow2K_2O\\ \left(2\right)K_2O+H_2O\rightarrow2KOH\\ \left(2\right)Bazo\rightarrow KL\left(K.có\right)\)

Ý 2)

\(a,Mg+FeSO_4\rightarrow MgSO_4+Fe\\ b,CuSO_4+Ba\left(OH\right)_2\rightarrow BaSO_4+Cu\left(OH\right)_2\\ Cu\left(OH\right)_2\rightarrow\left(t^o\right)CuO+H_2O\\ CuO+CO\rightarrow\left(t^o\right)Cu+CO_2\)

Bài 2:

\(a,\left(1\right)FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2+2NaCl\\ \left(2\right)Fe\left(OH\right)_2+H_2SO_4\rightarrow FeSO_4+2H_2O\\ \left(3\right)FeSO_4+Zn\rightarrow ZnSO_4+Fe\\ \left(4\right)3Fe+2O_2\rightarrow\left(t^o\right)Fe_3O_4\\ \left(4\right)Fe_3O_4+4CO\rightarrow\left(t^o\right)3Fe+4CO_2\)

Bài 2b)

\(\left(1\right)4Al+3O_2\rightarrow\left(t^o\right)2Al_2O_3\\ \left(2\right)Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ \left(3\right)AlCl_3+3KOH\rightarrow Al\left(OH\right)_3+3KCl\\ \left(4\right)2Al\left(OH\right)_3\rightarrow\left(t^o\right)Al_2O_3+3H_2O\\ \left(5\right)2Al_2O_3\rightarrow\left(t^o,criolit\right)4Al+3O_2\\ \left(6\right)2Al+2NaOH+2H_2O\rightarrow2NaAlO_2+3H_2\)

PTHH:

S+O₂\(\underrightarrow{t^o}\)SO₂

2SO₂+O₂\(\xrightarrow[V_2O_5]{t^o,p}\)SO₃

SO₃+H₂O-->H₂SO₄

H₂SO₄+2NaOH-->Na₂SO₄+2H₂O

Na₂SO₄+BaCl₂-->BaSO₄\(\downarrow\)+2NaCl

\(2Al+3S\underrightarrow{t^0}Al_2S_3\)

\(Fe+S\underrightarrow{t^0}FeS\)

\(Pb+S\underrightarrow{t^0}PbS\)

\(2Na+S\underrightarrow{t^0}Na_2S\)

a) 2 Al + 3 S -to-> Al2S3

b) Fe + S -to-> FeS

c) Pb + S -to-> PbS

d) 2 Na + S -to-> Na2S

a. S + Al → Al₂S₃.

b. Fe + S → FeS.

c. Pb + S → PbS.

d. Na + S → Na₂S.

                (Tất cả các phản ứng trên đều có nhiệt độ nha.)

Sửa đề: C₂H₃OH thành C₂H₅OH

\(C_2H_4+H_2O\overrightarrow{axit}C_2H_5OH\\ C_2H_5OH+O_2\underrightarrow{\text{men giấm}}CH_3COOH\\ C_2H_5OH+CH_3COOH\xrightarrow[H_2SO_4đặc]{t^o}CH_3COOC_2H_5+H_2O\)

ko có C2H3 đâu nhé

a.

\(1.2SO_2+O_2->2SO_3\)

\(2.H_2O+SO_3->H_2SO_4\)

\(3.CuO+H_2SO_4->CuSO_4+H_2O\)

\(4.Fe+CuSO_4->FeSO_4+Cu\)

\(5.FeSO_4+BaCl_2->BaSO_4+FeCl_2\)

a.

\(\left(1\right)2SO_2+O_2\xrightarrow[V_2O_5]{t^o}2SO_3\)

\(\left(2\right)SO_3+H_2O\xrightarrow[]{}H_2SO_4\)

\(\left(3\right)H_2SO_4+CuO\xrightarrow[]{}CuSO_4+H_2O\)

\(\left(4\right)Fe+CuSO_4\xrightarrow[]{}Cu\downarrow+FeSO_4\)

\(\left(5\right)FeSO_4+BaCl_2\xrightarrow[]{}BaSO_4\downarrow+FeCl_2\)

b.

\(\left(1\right)Fe_2O_3+3H_2SO_4\xrightarrow[]{}Fe_2\left(SO_4\right)_3+3H_2O\)

\(\left(2\right)Fe_2\left(SO_4\right)_3+6NaOH\xrightarrow[]{}2Fe\left(OH\right)_3+3Na_2SO_4\)

\(\left(3\right)Fe\left(OH\right)_3+3HCl\xrightarrow[]{}FeCl_3+3H_2O\)

\(\left(4\right)FeCl_3+3HNO_3\xrightarrow[]{}Fe\left(NO_3\right)_3+3HCl\)

b. 

\(Fe_2O_3+3H_2SO_4->Fe_2\left(SO_4\right)_3+3H_2O\)

\(Fe_2\left(SO_4\right)_3+3NaOH->Fe\left(OH\right)_3+3Na_2SO_4\)

\(Fe\left(OH\right)_3+HCl->FeCl_3+H_2O\)

\(FeCl_3+3AgNO_3->Fe\left(NO_3\right)_3+3AgCl\)

d

Hmmmmmmmmmm sao lại thấy C và D đúng nhỉ ?

D

(1) C + O 2   → t ° C O 2

(2) C O 2  + Ca OH 2  → CaC O 3  +  H 2 O

(3) CaC O 3  → CaO + C O 2

(4) CaO +  H 2 O → Ca OH 2

(5) Ca OH 2  + 2C O 2  → Ca HCO 3 2

(1) Fe 2 O 3  + 3 H 2  → 2Fe + 3 H 2 O

(2) 2Fe + 3 Cl 2  → 2Fe Cl 3

(3) Fe Cl 3  + 3NaOH → 3NaCl + Fe OH 3

(4) 2Fe OH 3  →  Fe 2 O 3  + 3 H 2 O

(5) Fe + HCl → Fe Cl 2  +  H 2

(6) Fe Cl 2  + 2NaOH → Fe OH 2  + 2NaCl