a) = 1760/1848

b) số lớn quá

máy tính còn ko tính  nổi

k minh nha

1760/1848

40204260024 / 40124012000 

ủng hộ mk nha bn

\(\frac{55x32}{33x56}=\frac{11x5x2x2x8}{11x3x2x7x8}=\frac{2}{3x7}=\frac{2}{21}\)

\(\frac{20042004x2006}{20062006x2004}=\frac{10001x2004x2006}{10001x2006x2004}=1\)

#

\(\frac{55\times32}{33\times56}=\frac{5\times4}{3\times7}=\frac{20}{21}.\)

\(\frac{20042004\times2006}{20062006\times2000}=\frac{1002\times1003}{1003\times1000}=\frac{501}{500}.\)

\(\dfrac{6}{13}.\dfrac{5}{7}+\dfrac{6}{13}.\dfrac{2}{7}+\dfrac{7}{13}=\dfrac{6}{13}.\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\dfrac{7}{13}=\dfrac{6}{13}.1+\dfrac{7}{13}=\dfrac{6}{13}+\dfrac{7}{13}=\dfrac{13}{13}=1\)

#Monster

\(\dfrac{6}{13}\).(\(\dfrac{2}{7}+\dfrac{5}{7}\))+\(\dfrac{7}{13}\)

\(\dfrac{6}{13}\).1+\(\dfrac{7}{13}\)

\(\dfrac{6}{13}\)+\(\dfrac{7}{13}\)

1

mik làm ở bài dưới rồi nha.

1: \(S=1+\dfrac{1}{3}+\dfrac{1}{9}+...+\dfrac{1}{3^9}\)

\(=\left(\dfrac{1}{3}\right)^0+\left(\dfrac{1}{3}\right)^1+...+\left(\dfrac{1}{3}\right)^9\)

u1=1; q=1/3

\(S_9=\dfrac{u1\cdot\left(1-q^9\right)}{1-q}=\dfrac{1\left(1-\left(\dfrac{1}{3}\right)^9\right)}{1-\dfrac{1}{3}}\)

\(=\dfrac{3}{2}\left(1-\dfrac{1}{3^9}\right)\)

2:

\(S=\left(\dfrac{1}{5}\right)^0+\left(\dfrac{1}{5}\right)^1+...+\left(\dfrac{1}{5}\right)^7\)

\(u1=1;q=\dfrac{1}{5}\)

\(S_7=\dfrac{1\cdot\left(1-q^7\right)}{1-q}=\dfrac{1-\left(\dfrac{1}{5}\right)^7}{1-\dfrac{1}{5}}=\dfrac{5}{4}\left(1-\dfrac{1}{5^7}\right)\)

1, Ta có \(\dfrac{\dfrac{1}{3}}{1}=\dfrac{1}{3};\dfrac{\dfrac{1}{9}}{\dfrac{1}{3}}=\dfrac{1}{3};...\)

-> Là cấp số nhân, q = 1/3 

Ta có \(S_9=1.\dfrac{1-\left(\dfrac{1}{3}\right)^9}{1-\left(\dfrac{1}{3}\right)}\approx1,5\)

b, Ta có \(\dfrac{\dfrac{1}{5}}{1}=\dfrac{1}{5};\dfrac{\dfrac{1}{25}}{\dfrac{1}{5}}=\dfrac{1}{5};...\)

-> Là cấp số nhân, q = 1/5 

\(S_7=\dfrac{1-\left(\dfrac{1}{5}\right)^7}{1-\dfrac{1}{5}}\approx1,25\)

S = \(\left(1+\dfrac{1}{3}+...+\dfrac{1}{2021}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{2020}\right)\)

= \(\left(1+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{2021}\right)-2.\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{2020}\right)\)

= \(\left(1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2021}\right)-\left(1+\dfrac{1}{2}+...+\dfrac{1}{1010}\right)\)

= \(\dfrac{1}{1011}+\dfrac{1}{1012}+...+\dfrac{1}{2021}\)

S=P nhé

a: =25/30+12/30=37/30

b: =24/20-15/20=9/20

c: =36/48=3/4

d: =8/17x1/6=8/102=4/51

a) \(\dfrac{25}{30}+\dfrac{12}{30}=\dfrac{37}{30}\)

b) \(\dfrac{24}{20}-\dfrac{15}{20}=\dfrac{9}{20}\)

c) \(\dfrac{36}{48}=\dfrac{3}{4}\)

d) \(\dfrac{8}{17}\times\dfrac{1}{6}=\dfrac{8}{102}=\dfrac{4}{51}\)

\(\dfrac{5}{6}+\dfrac{2}{5}=\dfrac{25}{30}+\dfrac{12}{30}=\dfrac{37}{30}\)

\(\dfrac{6}{5}-\dfrac{3}{4}=\dfrac{24}{20}-\dfrac{15}{20}=\dfrac{9}{20}\)

\(\dfrac{9}{16}\times\dfrac{4}{3}=\dfrac{36}{48}\)

\(\dfrac{8}{17}:6=\dfrac{8}{102}\)

= \(\dfrac{11}{15}\). \(\left(\dfrac{4}{11}+\dfrac{5}{11}+\dfrac{2}{11}\right)\)

= \(\dfrac{11}{15}\). 1

=\(\dfrac{11}{15}\)

\(=\dfrac{11}{15}\cdot\left(\dfrac{4}{11}+\dfrac{5}{11}+\dfrac{2}{11}\right)=\dfrac{11}{15}\cdot\dfrac{11}{11}=\dfrac{11}{15}\)

11/15 . ( 4/11 +5/11 + 2/11 )

= 11/15 . 1

= 11/15

a: \(=\dfrac{3}{4}+\dfrac{9}{5}\cdot\dfrac{2}{3}-1=\dfrac{3}{4}+\dfrac{6}{5}-1=\dfrac{19}{20}\)

b: \(=\dfrac{6}{7}\left(\dfrac{8}{13}+\dfrac{9}{13}-\dfrac{4}{13}\right)=\dfrac{6}{7}\cdot\dfrac{13}{13}=\dfrac{6}{7}\)

Thực hiện phép tính ( tính hợ lí nếu được)
a, \(\dfrac{3}{4}+\dfrac{9}{5}:\dfrac{3}{2}-1\)                                         b, \(\dfrac{6}{7}.\dfrac{8}{13}+\dfrac{6}{13}.\dfrac{9}{7}-\dfrac{4}{13}.\dfrac{6}{7}\)
= \(\dfrac{3}{4}+\dfrac{6}{5}-1\)                                                 = \(\dfrac{6}{7}.\left(\dfrac{8}{13}+\dfrac{9}{13}-\dfrac{4}{13}\right)\)
= \(\dfrac{15}{20}+\dfrac{24}{20}-\dfrac{20}{20}\)                                          = \(\dfrac{6}{7}.\left(\dfrac{17}{13}-\dfrac{4}{13}\right)\)
= \(\dfrac{39}{20}-\dfrac{20}{20}\)                                                    = \(\dfrac{6}{7}.1\)
= \(\dfrac{19}{20}\)                                                              = \(\dfrac{6}{7}\)

a: =-21/36-3/36=-24/36=-2/3

b: =43/12*1/2+5/24=43/24+5/24=2

c: =8/9+1/9=1

e: =1-1/4+1/4-1/7+...+1/97-1/100

=1-1/100=99/100