537+912+463
813+47+187
35+45+55+65
74+84+16+26
Đặt tính rồi tính.
a) 28 + 55 45 + 49 37 + 53
b) 61 – 18 53 – 26 92 – 84
a) 28 + 55 = 83
45 + 49 = 94
37 + 53 = 90
b) 61 - 18 = 43
53 - 26 = 27
92 - 84 = 8
\(\begin{array}{*{20}{c}}{a)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{28}\\{55}\end{array}}\\\hline{\,\,\,\,83}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{45}\\{49}\end{array}}\\\hline{\,\,\,\,94}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{37}\\{53}\end{array}}\\\hline{\,\,\,\,90}\end{array}\)
\(\begin{array}{*{20}{c}}{b)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{61}\\{18}\end{array}}\\\hline{\,\,\,43}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{53}\\{26}\end{array}}\\\hline{\,\,\,27}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{92}\\{84}\end{array}}\\\hline{\,\,\,08}\end{array}\)
(x-24)/55+(x-26)/53=(x-34)/45+(x-32)/47=0
tính nhanh
23+45+77+55+16+84
nguyen van chuyen : mà phải hỏi bài này sao
= (23+77)+(45+55)+(16+84)=100+100+100=300
23 + 45 + 77 + 55 + 16 + 84
= (23 + 77) + (45 + 55) + (16 + 84)
= 100 + 100 + 100
= 300
tính bằng cách thuận tiện nhất
84+77+55+23+45+16
nguyễn thị thơm ơi, cách giải như thế này này:
84+77+55+23+45+16=(84+16)+(77+23)+(55+45)
=100+100+100
=300
Bài 4: Tính nhanh: a) 2004^2- 16
b) 892^2+ 892 . 216 + 108^2
c) 36^2 + 26^2 – 52 . 36
d) (10,2 . 9,8 – 9,8 . 0,2) + (10,22 –10,2 . 0,2 )
e) 20,03 . 45 + 20,03 . 47 + 20,03 . 8
g) 15,75 . 175 – 15, 75 . 55 – 15, 75 . 20
h/ A=57^2+114.43+43^2
i/ B=5^4.3^4-(15^2-1).(15^2+1)
k) C=50^2-49^2+48^2-47^2+……+2^2-1^1
Bài 4: Tính nhanh: a) 2004^2- 16
b) 892^2+ 892 . 216 + 108^2
c) 36^2 + 26^2 – 52 . 36
d) (10,2 . 9,8 – 9,8 . 0,2) + (10,22 –10,2 . 0,2 )
e) 20,03 . 45 + 20,03 . 47 + 20,03 . 8
g) 15,75 . 175 – 15, 75 . 55 – 15, 75 . 20
h/ A=57^2+114.43+43^2
i/ B=5^4.3^4-(15^2-1).(15^2+1)
k) C=50^2-49^2+48^2-47^2+……+2^2-1^1
a: \(2004^2-16=2000\cdot2008=4016000\)
b: \(892^2+892\cdot216+108^2=1000^2=1000000\)
c: \(36^2-52\cdot36+26^2=10^2=100\)
1)(3x+20)
2)2(-4x+9)
3)2x(x-45)
4)-5x(2x+47)
5)x^2-912
`3x+20=0`
`=>3x=0-20`
`=>3x=-20`
`=>x=-20/3`
`---`
`2(-4x+9)=0`
`=>-4x+9=0`
`=>-4x=-9`
`=>x=9/4`
`---`
`2x(x-45)=0`
\(\Rightarrow\left[{}\begin{matrix}2x=0\\x-45=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=45\end{matrix}\right.\)
`---`
`-5x(2x+47)=0`
\(\Rightarrow\left[{}\begin{matrix}-5x=0\\2x+47=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{47}{2}\end{matrix}\right.\)
`----`
`x^2 -912=0`
`=>x^2=912`
`=>x∈∅`
1)
`3x+20=0`
`<=>3x=-20`
`<=>x=-20/3`
2)
`2(-4x+9)=0`
<=>-4x+9=0`
`<=>-4x=-9`
`<=>x=9/4`
3)
`2x(x-45)=0`
\(< =>\left[{}\begin{matrix}2x=0\\x-45=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x=45\end{matrix}\right.\)
4)
`-x(2x+47)=0`
\(< =>\left[{}\begin{matrix}-x=0\\2x+47=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x=-\dfrac{47}{2}\end{matrix}\right.\)
5)
`x^2 -912=0`
`<=>x^2=912`
câu 5 xem lại nhé
1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 10 * 11 * 12 * 13 * 14 * 15 * 16 * 17 * 18 * 19 * 20 * 21 * 22 * 23 * 24 * 25 * 26 * 27 * 28 * 29 * 30 * 31 * 32 * 33 * 34 * 35 * 36 * 37 * 38 * 39 * 40 * 41 * 42 * 43 * 44 * 45 * 46 * 47 * 48 * 49 * 50 * 51 * 52 * 53 * 54 * 55 * 56 * 57 * 58 * 59 * 60 * 61 * 62 * 63 * 64 * 65 * 66 * 67 * 68 * 69 * 70 * 71 * 72 * 73 * 74 * 75 * 76 * 77 * 78 * 79 * 80 * 81 * 82 * 83 * 84 * 85 * 86 * 87 * 88 * 89 * 90 * 91 * 92 * 93 * 94 * 95 * 96 * 97 * 98 * 99 * 100 bằng bao nhiêu?
\(\dfrac{x-45}{55}+\dfrac{x-47}{53}=\dfrac{x-55}{45}+\dfrac{x-53}{47}\)
giải phương trình trên
\(\dfrac{x-45}{55}+\dfrac{x-47}{53}=\dfrac{x-55}{45}+\dfrac{x-53}{47}\)
\(\Leftrightarrow\left(\dfrac{x-45}{55}-1\right)+\left(\dfrac{x-47}{53}-1\right)=\left(\dfrac{x-55}{45}-1\right)+\left(\dfrac{x-53}{47}-1\right)\)
\(\Leftrightarrow\dfrac{x-100}{55}+\dfrac{x-100}{53}=\dfrac{x-100}{45}+\dfrac{x-100}{47}\)
\(\Leftrightarrow\dfrac{x-100}{55}+\dfrac{x-100}{53}-\dfrac{x-100}{45}-\dfrac{x-100}{47}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{55}+\dfrac{1}{53}-\dfrac{1}{45}-\dfrac{1}{47}\right)=0\)
Do \(\dfrac{1}{55}+\dfrac{1}{53}-\dfrac{1}{45}-\dfrac{1}{47}\ne0\) nên x - 100 = 0 <=> x = 100
a) 27*45+27*55/2+4+6+...+16+18 b)26*108-26*12/32-28+24-20+16-12+8-4 c)48*700-24*45*20/45-40+35-30+25-20+15-10
\(\frac{48x700-24x45x20}{45-40+35-30+25-20+15-10}\)
\(=\frac{24x2x700-24x45x20}{5+5+5+5}\)
\(=\frac{24x1400-24x900}{20}\)
\(=\frac{24x\left(1400-900\right)}{20}\)
\(=\frac{24x500}{20}\)
\(=\frac{12000}{20}\)
\(=600\)
k nha
\(\frac{27x45+27x55}{2+4+6+...+16+18}\)
\(=\frac{27x\left(45+55\right)}{2+4+6+...+16+18}\)
\(=\frac{27x100}{2+4+6+...+16+18}\)
\(=\frac{2700}{\left(2+18\right)x9:2}\)
\(=\frac{2700}{90}\)
\(=30\)
k nha
\(\frac{26x108-26x12}{32-28+24-20+16-12+8-4}\)
\(=\frac{26x\left(108-12\right)}{4+4+4+4}\)
\(=\frac{26x96}{16}\)
\(=\frac{2496}{16}\)
\(=156\)
k nha