Bài 1: Thực hiện các phép tính sau:

\(a)\)Chưa rỏ đề

\(b)\)\(5025\div5-25\div5\)

\(=\)\(1005-5\)

\(=\)\(1000\)

\(c)\)\(218-180\div2\div9\)

\(=\)\(218-10\)

\(=\)\(208\)

\(d)\)\(\left(328-8\right)\div32\)

\(=\)\(320\div32\)

\(=\)\(10\)

Bài 1:

a) ( Tôi không nhìn rõ đầu bài )

b) 5025  :  5  -  25  :  5

=  ( 5025  -  25 )  :  5

=        5000   :   5

=       1000

c)   218  -  180  :  2  :  9

=     218   -    180  :  (  2  .  9 )

=      218    -    180   :  18

=       218    -    10

=       208

d)   (  328  -  8  )  :  32

=      320   :   32

=     10 

Bài 2: Thực hiện phép tính:

\(a)\)\(27.75+25.27-150\)

\(=\)\(27.\left(75+25\right)-150\)

\(=\)\(27.100-150\)

\(=\)\(2700-150\)

\(=\)\(2550\)

\(b)\)\(12\div\left\{400\div\left[500-\left(125+25.7\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-\left(125+175\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-300\right]\right\}\)

\(=\)\(12\div\left\{400\div200\right\}\)

\(=\)\(12\div2\)

\(=\)\(6\)

\(c)\)\(13.17-256\div16+14\div7-1\)

\(=\)\(221-16+2-1\)

\(=\)\(206\)

\(d)\)\(18\div3+182+3.\left(51\div17\right)\)

\(=\)\(6+182+3.3\)

\(=\)\(6+182+9\)

\(=\)\(197\)

a)  80 - (4.5² - 3.2³ )

= 80 - ( 4 . 25 - 3. 8 ) 

= 80 - ( 100 - 24 )

= 80 - 76 = 4 

b) 5⁶ : 5⁴ + 2³ . 2² - 1²⁰¹⁷ 

= 5² + 2⁵ - 1 

= 25 + 32 - 1 

= 57 -1 = 56 

a) 80 - (4.5² - 3.2³)

= 80 - (4.25 - 3.8)

= 80 - (100 - 24)

= 80 - 76

= 4

b) 5⁶ : 5⁴ + 2³ . 2² - 1²⁰¹⁷

= 5² + 2⁵ - 1

= 25 + 32 - 1

= 56

Chúc bạn học tốt!! ^^

a) `27 .75 + 25.27 -150`

`=27 xx (75 + 25)-150`

`=27 xx 100-150`

`=2700-150`

`=2550`

b) `142-[50-(2^3 .10-2^3 .5)]`

`=142-[50-2^3 .(10-5)]`

`=142-(50-8 .5)`

`=142-(50-40)`

`=142-10`

`=132`

c) `375:{32-[4+(5.3^2-42)]}-14`

`=375:{32-[4+(45-42)]}-14`

`=375:[32-(4+3)]-14`

`=375: 25 -14`

`=15-14`

`=1`

a. 27 . 75 + 25 . 27 - 150

= 27. (75 + 25) - 150

= 27 . 100 - 150

= 2700 - 150

= 2550

b. 142 - [50 - (2³.10 - 2³.5)]

= 142 - [50 - (8 . 10 - 8 . 5)]

= 142 - {50 - [8 . (10 - 5)]} 

= 142 - (50 - 40)

= 142 - 10

= 132

c. 375 : {32 – [ 4 + (5. 3² – 42)]} – 14

= 375 : {32 – [ 4 + (5. 9 – 42)]} – 14

= 375 : {32 – [ 4 + (45 – 42)]} – 14

= 375 : {32 – [ 4 + 3]} – 14

= 375 : {32 –7} – 14

= 375 : 25 - 14

= 15 - 14

= 1

Sửa đề: \(C=1+3^1+3^2+...+3^{100}\)

b) Ta có: \(C=1+3^1+3^2+...+3^{100}\)

\(\Leftrightarrow3\cdot C=3+3^2+...+3^{101}\)

\(\Leftrightarrow C-3\cdot C=1+3+3^2+...+3^{100}-3-3^2-...-3^{100}-3^{101}\)

\(\Leftrightarrow-2\cdot C=1-3^{101}\)

hay \(C=\dfrac{3^{101}-1}{2}\)

b) Ta có: C=1+31+32+...+3100C=1+31+32+...+3100

⇔3⋅C=3+32+...+3101⇔3⋅C=3+32+...+3101

⇔C−3⋅C=1+3+32+...+3100−3−32−...−3100−3101⇔C−3⋅C=1+3+32+...+3100−3−32−...−3100−3101

⇔−2⋅C=1−3101

a) \(\text{2}\sqrt{\text{18}}-9\sqrt{50}+3\sqrt{8}\)

= \(\text{6}\sqrt{\text{2}}-45\sqrt{2}+6\sqrt{2}\)

= \(-33\sqrt{2}\)

b) = \(7-2.\sqrt{7}.\sqrt{3}+3+7.2\sqrt{21}\)

= \(10-2\sqrt{21}+14\sqrt{21}\)

= \(10+12\sqrt{21}\)

\(1,\\ a,=\left[x^3\left(x-2\right)-4x\left(x-2\right)\right]:\left(x^2-4\right)\\ =x\left(x^2-4\right)\left(x-2\right):\left(x^2-4\right)=x\left(x-2\right)\\ b,=\left(2014-14\right)^2=2000^2=4000000\\ 2,\\ A=2015\cdot2013\cdot\left(2014^2+1\right)\\ A=\left(2014^2-1\right)\left(2014^2+1\right)\\ A=2014^4-1< B=2014^4\)

Đề bài lỗi rồi bạn, bạn xem lại nhé!

Bài 1. 

a) \(\left(3+4i\right)+\left(-1+5i\right)=\left(3-1\right)+\left(4i+5i\right)=2+9i\)

b) \(\left(3-4i\right)-\left(1-5i\right)=\left(3-1\right)-\left(4i-5i\right)=2+i\)

c)\(\left(-3+4i\right)+\left(1-4i\right)=\left(-3+1\right)+\left(4i-4i\right)=-2\)

d) \(\left(3-5i\right)-\left(4+i\right)=\left(3-4\right)-\left(5i+i\right)=-1-6i\)

Bài 2. 

a) \(\left(3+4i\right)\left(-1+5i\right)=3.\left(-1\right)+4i.\left(-1\right)+3.5i+4i.5i\)

\(=-3-4i+15i-20=-23+11i\)

b) \(\left(3-5i\right)-\left(4+i\right)=\left(3-4\right)-\left(5i+i\right)=-1-6i\)