Tìm x
96 - 3 ( X + 1 ) = 42
Tìm x
96 - 3 . ( x + 1 ) = 42
96 - 3(x + 1) = 42
<=> 96 - 3x - 3 = 42
<=> 96 - 3 - 42 = 3x
<=> 3x = 51
<=> x = 17
\(96-3\left(x+1\right)=42\)
\(3\left(x+1\right)=96-42=54\)
\(x+1=54:3=18\)
\(x=18-1=17\)
tính
B = 3/1x6 + 3/6x11 + ... + 1/91 x96
Sửa đề: 3/91*96
\(B=\dfrac{3}{1\cdot6}+\dfrac{3}{6\cdot11}+...+\dfrac{3}{91\cdot96}\)
=3/5(5/1*6+5/6*11+...+5/91*96)
=3/5(1-1/6+1/6-1/11+...+1/91-1/96)
=3/5*95/96=57/96=19/32
tìm x
96=2x
Tìm x:a,42-42(x+1)=0. b ,(2x+4)-(x+3)=0
) Cho đa thức :
P(x) = x99 – 100.x98 + 100.x97 – 100.x96 + …+ 100.x – 1
Tính P(99) ?
tìm x
2.(x-1)=4/3
(x-1)^2=4
2.|x+1|=3
a) 2.(x-1)=4/3
<=> (X-1)= 4/3 :2 = 2/3
<=> X= 2/3+1=5/3
b) (x-1)^2= 4
<=> X-1=2 hoặc x-1=-2
<=> X= 3 hoặc x= -1
c) 2.|x+1|=3
<=> Ix+1| = 3/2
<=> X+1= 3/2 hoặc x+1= -3/2
<=> X= 1/2 hoặc x= -5/2
a) Ta có: \(2\left(x-1\right)=\dfrac{4}{3}\)
\(\Leftrightarrow x-1=\dfrac{4}{3}:2=\dfrac{4}{6}=\dfrac{2}{3}\)
hay \(x=\dfrac{5}{3}\)
Vậy: \(x=\dfrac{5}{3}\)
b) Ta có: \(\left(x-1\right)^2=4\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
Vậy: \(x\in\left\{3;-1\right\}\)
a) 2.(x-1)=4/3
<=> (X-1)= 4/3 :2 = 2/3
<=> X= 2/3+1=5/3
b) (x-1)^2= 4
=> X-1=2 hoặc x-1=-2
=> X= 3 hoặc x= -1
c) 2.|x+1|=3
=> Ix+1| = 3/2
=> X+1= 3/2 hoặc x+1= -3/2
=> X= 1/2 hoặc x= -5/2
96 - 3 ( x + 1) = 42. Tìm x
96 - 3(x+1)= 42
3(x+1) = 96 - 42 = 54
x + 1 = 54 : 3 = 18
x = 18 - 1 = 17
96-3.(x+1)=42
96-3.(x+1)=16
93 .(x+1)=16
(x+1)= 93-16
(x+1)=77
x = 77-1
x = 76
Tìm x biết
c)96 - 3.(x + 1) = 42
c)96 - 3.(x + 1) = 42
3.(x + 1)= 96 - 42
3.(x + 1) = 54
x + 1= 54:3
x + 1= 18
x = 18 - 1
x = 17
Tìm x,biết
\(\left(x+3\right)^3-x\left(3x+1\right)^2+\left(2x+1\right)\left(4x^2-2x+1\right)-3x^2=42\) 42
tìm x
96-3(x+1)=42
96-3(x+1)=42
3(x+1)=96-42
3(x+1)=54
x+1 = 54 : 3
x+1 = 18
x = 18 - 1
x = 17
96 - 3(x + 1) = 42
\(\Rightarrow\)3x + 3 = 54
\(\Rightarrow\)3x = 51
\(\Rightarrow\)x = 17