Question

tìm x
2.(x-1)=4/3
(x-1)^2=4
2.|x+1|=3 

Answer 1

a) 2.(x-1)=4/3

<=> (X-1)= 4/3 :2 = 2/3

<=> X= 2/3+1=5/3

b) (x-1)^2= 4

<=> X-1=2 hoặc x-1=-2

<=> X= 3 hoặc x= -1

c) 2.|x+1|=3

<=> Ix+1| = 3/2

<=> X+1= 3/2 hoặc x+1= -3/2

<=> X= 1/2 hoặc x= -5/2

Answer 2

a) Ta có: \(2\left(x-1\right)=\dfrac{4}{3}\)

\(\Leftrightarrow x-1=\dfrac{4}{3}:2=\dfrac{4}{6}=\dfrac{2}{3}\)

hay \(x=\dfrac{5}{3}\)

Vậy: \(x=\dfrac{5}{3}\)

b) Ta có: \(\left(x-1\right)^2=4\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

Vậy: \(x\in\left\{3;-1\right\}\)

Answer 3

a) 2.(x-1)=4/3

<=> (X-1)= 4/3 :2 = 2/3

<=> X= 2/3+1=5/3

b) (x-1)^2= 4

=> X-1=2 hoặc x-1=-2

=> X= 3 hoặc x= -1

c) 2.|x+1|=3

=> Ix+1| = 3/2

=> X+1= 3/2 hoặc x+1= -3/2

=> X= 1/2 hoặc x= -5/2