a) (\(\frac{-1}{2}\))3- (\(\frac{3}{4}\))3x(-2)2
b) 2x(-1)5+(\(\frac{3}{4}\))2-\(\frac{3}{8}\)
c) \(\frac{2^{19}x27^3+15x4^9x9^4}{6^9x2^{10}+12^{10}}\)
Những câu hỏi liên quan
Tính :
\(\frac{2^{19}x27^3+15x4^9x9^4}{6^9x2^{10}+12^{10}}\)
^Mk cần câu TL rõ ràng nhé
=\(\frac{2^{19}.\left(3^3\right)^3+3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(2^2.3\right)^{10}}\)
=\(\frac{2^{19}.3^9+5.2^{18}.3.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)
\(=\frac{2^{19}.3^9+2^{18}.3^9.5}{2^{19}.3^9+2^{20}.3^{10}}\)
=\(\frac{2^{18}.3^9\left(2+5\right)}{2^{19}.3^9\left(1+2.3\right)}\)
\(=\frac{2^{18}.3^9.7}{2^{19}.3^9.7}=\frac{1}{2}\)
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Tính giá trị của các biểu thức sau:
a) \(A=\frac{5x2^{13}x4^{11}-16^9}{\left(3x2^{17}\right)^2}\)
b) \(B=\frac{2^{19}x27^3+15x4^9x9^4}{6^9x2^{10}+12^{10}}\)
a)\(A=\frac{5.2^{13}.2^{22}-2^{36}}{\left(3.2^{17}\right)^2}\)
\(A=\frac{5.2^{35}-2^{36}}{3^2.2^{34}}\)
\(A=\frac{2^{35}\left(5-2\right)}{3^2.2^{34}}\)
\(A=\frac{2.3}{3^2}=\frac{2}{3}\)
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b) \(B=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
\(B=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)
\(B=\frac{2^{18}.3^9\left(2+5\right)}{2^{19}.3^9\left(2+3\right)}\)
\(B=\frac{7}{2.5}=\frac{7}{10}\)
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Bài 1. Giải các phương trình sau
1) frac{3x+2}{2}-frac{3x+1}{6}frac{5}{3}-2x
2) frac{x-3}{5}6-frac{1-2x}{3}
3) 2left(x+frac{3}{5}right)5-left(frac{13}{5}+xright)
4) frac{2x+3}{3}frac{5-4x}{2}
5) frac{5x+3}{12}frac{1+2x}{9}
6) x-frac{x+1}{3}frac{2x+1}{5}
7) frac{3left(x-3right)}{4}+frac{4x-10,5}{10}frac{3left(x+1right)}{5}+6
8) frac{2left(3x+1right)+1}{4}-5frac{2
left(3x-1right)}{5}-frac{3x+2}{10}
9) frac{x+1}{3}+frac{3left(2x+1right)}{4}frac{2x+3left(x+1right)}{6}+frac{7+12x}{12}
10...
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Bài 1. Giải các phương trình sau
1) \(\frac{3x+2}{2}-\frac{3x+1}{6}=\frac{5}{3}-2x\)
2) \(\frac{x-3}{5}=6-\frac{1-2x}{3}\)
3) \(2\left(x+\frac{3}{5}\right)=5-\left(\frac{13}{5}+x\right)\)
4) \(\frac{2x+3}{3}=\frac{5-4x}{2}\)
5) \(\frac{5x+3}{12}=\frac{1+2x}{9}\)
6) \(x-\frac{x+1}{3}=\frac{2x+1}{5}\)
7) \(\frac{3\left(x-3\right)}{4}+\frac{4x-10,5}{10}=\frac{3\left(x+1\right)}{5}+6\)
8) \(\frac{2\left(3x+1\right)+1}{4}-5=\frac{2 \left(3x-1\right)}{5}-\frac{3x+2}{10}\)
9) \(\frac{x+1}{3}+\frac{3\left(2x+1\right)}{4}=\frac{2x+3\left(x+1\right)}{6}+\frac{7+12x}{12}\)
10) \(\frac{2x-1}{3}-\frac{5x+2}{7}=x+13\)
Giải phương trình:
1. frac{2x+3}{4}-frac{5x+3}{6}frac{3-4x}{12}
2. frac{3.left(2x+1right)}{4}-1frac{15x-1}{10}
3. frac{2x-1}{5}-frac{x-2}{3}frac{x+7}{15}
4. frac{x+3}{2}-frac{x-1}{3}frac{x+5}{6}+1
5. frac{x-4}{5}-frac{3x-2}{10}-xfrac{2x-5}{3}-frac{7x+2}{6}
6. frac{left(x+2right)left(x+10right)}{3}-frac{left(x+4right)left(x+10right)}{12}frac{left(x-2right)left(x+4right)}{4}
7. frac{left(x+2right)^2}{8}-2left(2x-1right)25+frac{left(x-2right)^2}{8}
8.frac{7x^2-14x-5}{5}frac{left(2x+1right)^...
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Giải phương trình:
1. \(\frac{2x+3}{4}-\frac{5x+3}{6}=\frac{3-4x}{12}\)
2. \(\frac{3.\left(2x+1\right)}{4}-1=\frac{15x-1}{10}\)
3. \(\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{15}\)
4. \(\frac{x+3}{2}-\frac{x-1}{3}=\frac{x+5}{6}+1\)
5. \(\frac{x-4}{5}-\frac{3x-2}{10}-x=\frac{2x-5}{3}-\frac{7x+2}{6}\)
6. \(\frac{\left(x+2\right)\left(x+10\right)}{3}-\frac{\left(x+4\right)\left(x+10\right)}{12}=\frac{\left(x-2\right)\left(x+4\right)}{4}\)
7. \(\frac{\left(x+2\right)^2}{8}-2\left(2x-1\right)=25+\frac{\left(x-2\right)^2}{8}\)
8.\(\frac{7x^2-14x-5}{5}=\frac{\left(2x+1\right)^2}{5}-\frac{\left(x-1\right)^2}{3}\)
9. \(\frac{\left(2x-3\right)\left(2x+3\right)}{8}=\frac{\left(x-4\right)^2}{6}+\frac{\left(x-2\right)^2}{3}\)
10. \(\frac{x+1}{35}+\frac{x+3}{33}=\frac{x+5}{31}+\frac{x+7}{29}\)
1.
\(\frac{2x+3}{4}-\frac{5x+3}{6}=\frac{3-4x}{12}\)
\(MC:12\)
Quy đồng :
\(\Rightarrow\frac{3.\left(2x+3\right)}{12}-\left(\frac{2.\left(5x+3\right)}{12}\right)=\frac{3x-4}{12}\)
\(\frac{6x+9}{12}-\left(\frac{10x+6}{12}\right)=\frac{3x-4}{12}\)
\(\Leftrightarrow6x+9-\left(10x+6\right)=3x-4\)
\(\Leftrightarrow6x+9-3x=-4-9+16\)
\(\Leftrightarrow-7x=3\)
\(\Leftrightarrow x=\frac{-3}{7}\)
2.\(\frac{3.\left(2x+1\right)}{4}-1=\frac{15x-1}{10}\)
\(MC:20\)
Quy đồng :
\(\frac{15.\left(2x+1\right)}{20}-\frac{20}{20}=\frac{2.\left(15x-1\right)}{20}\)
\(\Leftrightarrow15\left(2x+1\right)-20=2\left(15x-1\right)\)
\(\Leftrightarrow30x+15-20=15x-2\)
\(\Leftrightarrow15x=3\)
\(\Leftrightarrow x=\frac{3}{15}=\frac{1}{5}\)
Rút gọn: a)\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}.12^{10}}\)
b)\(\frac{\left(-\frac{1}{2}\right)^3-\left(\frac{3}{4}\right)^3.\left(-2\right)^2}{2.\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)
Tìm x
a)\(3^{x+1}=9^x\)
b)\(2^{3x+2}=4^{x+5}\)
c)\(3^{2x-1}=243\)
Câu 3: Giải các phương trình sau bằng cách đưa về dạng ax+b0
1. a, frac{5x-2}{3}frac{5-3x}{2}; b, frac{10x+3}{12}1+frac{6+8x}{9}
c, 2left(x+frac{3}{5}right)5-left(frac{13}{5}+xright); d, frac{7}{8}x-5left(x-9right)frac{20x+1,5}{6}
e, frac{7x-1}{6}+2xfrac{16-x}{5}; f, 4 (0,5-1,5x)frac{5x-6}{3}
g, frac{3x+2}{2}-frac{3x+1}{6}frac{5}{3}+2x; h, frac{x+4}{5}.x+4frac{x}{3}-frac{x-2}{2}
i, frac{4x+3}{5}-frac{6x-2}{7}fr...
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Câu 3: Giải các phương trình sau bằng cách đưa về dạng ax+b=0
1. a, \(\frac{5x-2}{3}=\frac{5-3x}{2}\); b, \(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
c, \(2\left(x+\frac{3}{5}\right)=5-\left(\frac{13}{5}+x\right)\); d, \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
e, \(\frac{7x-1}{6}+2x=\frac{16-x}{5}\); f, 4 (0,5-1,5x)=\(\frac{5x-6}{3}\)
g, \(\frac{3x+2}{2}-\frac{3x+1}{6}=\frac{5}{3}+2x\); h, \(\frac{x+4}{5}.x+4=\frac{x}{3}-\frac{x-2}{2}\)
i, \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\); k, \(\frac{5x+2}{6}-\frac{8x-1}{3}=\frac{4x+2}{5}-5\)
m, \(\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{15}\); n, \(\frac{1}{4}\left(x+3\right)=3-\frac{1}{2}\left(x+1\right).\frac{1}{3}\left(x+2\right)\)
p, \(\frac{x}{3}-\frac{2x+1}{6}=\frac{x}{6}-x\); q, \(\frac{2+x}{5}-0,5x=\frac{1-2x}{4}+0,25\)
r, \(\frac{3x-11}{11}-\frac{x}{3}=\frac{3x-5}{7}-\frac{5x-3}{9}\); s, \(\frac{9x-0,7}{4}-\frac{5x-1,5}{7}=\frac{7x-1,1}{6}-\frac{5\left(0,4-2x\right)}{6}\)
t, \(\frac{2x-8}{6}.\frac{3x+1}{4}=\frac{9x-2}{8}+\frac{3x-1}{12}\); u, \(\frac{x+5}{4}-\frac{2x-3}{3}=\frac{6x-1}{3}+\frac{2x-1}{12}\)
v, \(\frac{5x-1}{10}+\frac{2x+3}{6}=\frac{x-8}{15}-\frac{x}{30}\); w, \(\frac{2x-\frac{4-3x}{5}}{15}=\frac{7x\frac{x-3}{2}}{5}-x+1\)
Đây là những bài cơ bản mà bạn!
\(\frac{5x-2}{3}=\frac{5-3x}{2}\)
\(< =>\frac{\left(5x-2\right).2}{6}=\frac{\left(5-3x\right).3}{6}\)
\(< =>\left(5x-2\right).2=\left(5-3x\right).3\)
\(< =>10x-4=15-9x\)
\(< =>10x+9x=15+4\)
\(< =>19x=19< =>x=1\)
\(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
\(< =>\frac{\left(10x+3\right).3}{36}=\frac{36}{36}+\frac{\left(6+8x\right).4}{36}\)
\(< =>\left(10x+3\right).3=36+\left(6+8x\right).4\)
\(< =>30x+9=36+24+32x\)
\(< =>32x-30x=9-36-24\)
\(< =>2x=9-60=-51< =>x=-\frac{51}{2}\)
Xem thêm câu trả lời
\(a,\frac{x-3}{2}+\frac{4x+1}{3}=\frac{2x-7}{6}\)
\(b,\frac{x-4}{5}+\frac{3x-2}{10}-x=\frac{2x-5}{3}-\frac{7x+5}{6}\)
\(c,\frac{2\left(x-3\right)}{4}+\frac{x-5}{3}=\frac{13x+4}{12}\)
bài 1 giải phương trình
a) (2x+3)^2-3(x-4)(x+4)left(x-2right)^2+1
b)(3x-2) (9x^2+6x+4)-(3x-1) (9x^2+3x+1)x-4
c)x (x-1) -(x-3) (x+4)5x
d) (2x+1)(2x-1)4x(x-7)-3x
bài 2 giải phương trình
a)frac{x}{10}-left(frac{x}{30}+frac{2x}{45}right)frac{4}{5}
b)frac{10x-5}{18}+frac{x+3}{12}frac{7x+3}{6}+frac{12-x}{9}
c)frac{10x+3}{8}frac{7-8x}{12}
d)frac{x+4}{5}-x-5frac{x+3}{3}-frac{x-2}{2}
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bài 1 giải phương trình
a) (2x+3)\(^2\)-3(x-4)(x+4)=\(\left(x-2\right)^2\)+1
b)(3x-2) (9x\(^2\)+6x+4)-(3x-1) (9x\(^2\)+3x+1)=x-4
c)x (x-1) -(x-3) (x+4)=5x
d) (2x+1)(2x-1)=4x(x-7)-3x
bài 2 giải phương trình
a)\(\frac{x}{10}-\left(\frac{x}{30}+\frac{2x}{45}\right)=\frac{4}{5}\)
b)\(\frac{10x-5}{18}+\frac{x+3}{12}=\frac{7x+3}{6}+\frac{12-x}{9}\)
c)\(\frac{10x+3}{8}=\frac{7-8x}{12}\)
d)\(\frac{x+4}{5}-x-5=\frac{x+3}{3}-\frac{x-2}{2}\)
Giải các pt sau :
1/ ( 3x – 2 )( 4x +5 ) = 0
2/ 5(2x – 3) – 4( 5x -7 ) = 19 - 2( x +11)
3/ ( x2 – 2x + 1 ) – 4 = 0
4/ ( x - 1) 2 + ( x+ 3) 2 = 2 ( x -2 ) (x +1 ) + 38
5/ \(\frac{4x+3}{2}-2+3x=\frac{2x-1}{10}+\frac{19x+2}{5}-1\)
6/ \(\frac{2x+4}{5}+\frac{2x-12,4}{6}-\frac{x+3}{10}=4\)
Giúp mình với mọi người ơi !!!
1,(3x-2)(4x+5)=0
\(\Leftrightarrow\left\{{}\begin{matrix}3x-2=0\\4x+5=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}3x=2\\4x=-5\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{2}{3}\\x=\frac{-5}{4}\end{matrix}\right.\)
Vậy phương trình có tập nghiệm là ...
2,\(5\left(2x-3\right)-4\left(5x-7\right)=19-2\left(x+11\right)\)
\(\Leftrightarrow10x-15-20x+28=19-2x-22\)
\(\Leftrightarrow10x-20x+2x=15-28+19-22\)
\(\Leftrightarrow-8x=-16\)
=> x= 2
vậy..
3,\(\left(x^2-2x+1\right)-4=0\)
\(\Leftrightarrow\left(x^2-2.x.\frac{1}{2}+\frac{1}{4}-\frac{1}{4}+1\right)-4=0\)
\(\Leftrightarrow\left(x^2-2.x.\frac{1}{2}+\frac{1}{4}\right)+\frac{3}{4}-4=0\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)^2-\frac{13}{4}=0\) ( vô nghiệm )
(vì \(\left(x-\frac{1}{2}\right)^2\ge0\Rightarrow\left(x-\frac{1}{2}\right)^2-\frac{13}{4}\ge0\) )
từ đó suy ra phương trình vô nghiệm
5,\(\frac{4x+3}{2}-2+3x=\frac{2x-1}{10}+\frac{19x+2}{5}-1\)
\(\Leftrightarrow\frac{5\left(4x+3\right)}{10}-\frac{10\left(2-3x\right)}{10}=\frac{2x-1}{10}+\frac{2\left(19x+2\right)}{10}-\frac{10}{10}\)
\(\Leftrightarrow\frac{20x+15}{10}-\frac{20-30x}{10}=\frac{2x-1}{10}+\frac{38x+4}{10}-\frac{10}{10}\)
\(\Rightarrow20x+15-20+30x=2x-1+38x+4-10\)
\(\Leftrightarrow20x+30x-2x-38x=-15+20-1+4-10\)
\(\Leftrightarrow10x=-2\)
\(\Leftrightarrow x=-5\)
Vậy ....
p/s : thực ra mk cx chỉ ms học th nên giải bài tập về phương trình vẫn còn nhiều chỗ sai nữa,có gì mong mn giúp đỡ :)
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