264+12x=1800

12x=1536

x=128

(x+73):19=321

x+73=6099

x=6026

2x+3x+4x=18

9x=18

x=2

10<2x<20

=>5<x<10

x=6,7,8,9

\(264+12x=1800\)

\(\Leftrightarrow12x=1536\)

\(\Leftrightarrow x=128\)

==============

\(\left(x+73\right):19=321\)

\(\Leftrightarrow x+73=6099\)

\(\Leftrightarrow x=6026\)

===============

\(2x+3x+4x=18\)

\(\Leftrightarrow x.\left(2+3+4\right)=18\)

\(\Leftrightarrow x.9=18\)

\(\Leftrightarrow x=2\)

================

\(10< 2x< 20\)

..................................

\(2x=12\Leftrightarrow x=6\)

\(2x=14\Leftrightarrow x=7\)

\(2x=16\Leftrightarrow x=8\)

\(2x=18\Leftrightarrow x=9\)

\(x\in\left\{6;7;8;9\right\}\)

bn hỏi 1 lần thôi đừng đăng nhiều chật lắm

12x = 1800 - 264

12x = 1536

x = 1536 : 12

x = 128

( x + 73 ) : 19 = 321

( x + 73 ) = 321 x 19

 x + 73 = 6099

x = 6099 - 73

x = 6026

2x + 3x + 4x = 18 

x . ( 2 + 3 + 4 ) = 18

x .          9          = 18

x = 18 : 9

x = 2

10 < 2x < 20

x = 6 ; 7 ; 8 ; 9

Bài 1:

\(a,=6x^2+6x\\ b,=15x^3-10x^2+5x\\ c,=6x^3+12x^2\\ d,=15x^4+20x^3-5x^2\\ e,=2x^2+3x-2x-3=2x^2+x-3\\ f,=3x^2-5x+6x-10=3x^2+x-10\)

Bài 2:

\(a,\Leftrightarrow3x^2+3x-3x^2=6\\ \Leftrightarrow3x=6\Leftrightarrow x=2\\ b,\Leftrightarrow6x^2+3x-6x^2+9x-2x-3=10\\ \Leftrightarrow10x=13\Leftrightarrow x=\dfrac{13}{10}\)

`a)4x(x+1)+(3-2x)(3+2x)=15`

`<=>4x^2+4x+9-4x^2=15`

`<=>4x=6`

`<=>x=3/2`

Vậy `S={3/2}`

`b)3x(x-20012)-x+20012=0`

`<=>3x(x-20012)-(x-20012)=0`

`<=>(x-20012)(3x-1)=0`

`<=>` $\left[\begin{matrix} x=20012\\ x=\dfrac{1}{3}\end{matrix}\right.$

Vậy `S={1/3;20012}`

a) 4x(x + 1) + (3 – 2x)(3 + 2x) = 15

⇔4x² + 4x + (9 – 4x²) = 15

⇔ 4x² + 4x + 9 – 4x² = 15

⇔4x = 15 – 9

⇔x=1,5

b)3x(x – 2001²) – x + 2001² = 0

⇔3x(x – 2001²) – (x – 2001²) = 0

⇔(x – 2001²)(3x – 1) = 0

⇔x – 2001² = 0 hay 3x – 1 = 0

⇔x = 2001² hoặc x = \(\dfrac{1}{2}\)

a) Ta có: \(6x\left(x-5\right)+3x\left(7-2x\right)=18\)

\(\Leftrightarrow6x^2-30x+21x-6x^2=18\)

\(\Leftrightarrow-9x=18\)

hay x=-2

Vậy: S={-2}

b) Ta có: \(2x\left(3x+1\right)+\left(4-2x\right)\cdot3x=7\)

\(\Leftrightarrow6x^2+2x+12x-6x^2=7\)

\(\Leftrightarrow14x=7\)

hay \(x=\dfrac{1}{2}\)

Vậy: \(S=\left\{\dfrac{1}{2}\right\}\)

c) Ta có: \(0.5x\left(0.4-4x\right)+\left(2x+5\right)\cdot x=-6.5\)

\(\Leftrightarrow0.2x-2x^2+2x^2+5x=-6.5\)

\(\Leftrightarrow5.2x=-6.5\)

hay \(x=-\dfrac{5}{4}\)

Vậy: \(S=\left\{-\dfrac{5}{4}\right\}\)

d) Ta có: \(\left(x+3\right)\left(x+2\right)-\left(x-2\right)\left(x+5\right)=6\)

\(\Leftrightarrow x^2+5x+6-\left(x^2+3x-10\right)=6\)

\(\Leftrightarrow x^2+5x+6-x^2-3x+10=6\)

\(\Leftrightarrow2x+16=6\)

\(\Leftrightarrow2x=-10\)

hay x=-5

Vậy: S={-5}

e) Ta có: \(3\left(2x-1\right)\left(3x-1\right)-\left(2x-3\right)\left(9x-1\right)=0\)

\(\Leftrightarrow3\left(6x^2-5x+1\right)-\left(18x^2-29x+3\right)=0\)

\(\Leftrightarrow18x^2-15x+3-18x^2+29x-3=0\)

\(\Leftrightarrow14x=0\)

hay x=0

Vậy: S={0}

a: Ta có: \(\left(8x^2-4x\right):\left(-4x\right)-\left(x+2\right)=8\)

\(\Leftrightarrow-2x+1-x-2=8\)

\(\Leftrightarrow-3x=9\)

hay x=-3

b: Ta có: \(\left(2x^4-3x^3+x^2\right):\left(-\dfrac{1}{2}x^2\right)+4\left(x-1\right)^2=0\)

\(\Leftrightarrow-4x^2+6x-2+4x^2-8x+4=0\)

\(\Leftrightarrow-2x=-2\)

hay x=1

a) \(\text{264 + 12x = 1800}\)

\(\Rightarrow12x=1800-264\)

\(\Rightarrow12x=1536\)

\(\Rightarrow x=1536:12\)

\(\Rightarrow x=128\)

b) \(\text{( x + 73 ) : 19 = 321}\Rightarrow x+73=6099\Rightarrow x=6026\)

c) 2x + 3x + 4x = 18

=> x.(2+3+4)=18

=> x.9 = 18

=> x=18 : 2

=> x= 2

d) 10 < 2x <  20   ( x thuộc N )  

Ta có : số lớn hơn hoặc bằng 10 và bé hơn hoặc bằng 20 là :

10;11;12;13;14;15;16;17;18;19;20

=>  ... tiếp đi nha bạn tự làm đc mà

ko làm đc hỏi mk

a: Ta có: \(x\left(2x-3\right)-\left(2x-1\right)\left(x+5\right)=17\)

\(\Leftrightarrow2x^2-3x-2x^2-10x+x+5=17\)

\(\Leftrightarrow-12x=12\)

hay x=-1