kh hiểu bn ơi

`4x=2+xx+1x<=>4x=2+3x<=>4x-3x=2<=>1x=2<=>x=2`

\(x^3-2x^2+x-2=0\\ \Leftrightarrow x^2\left(x-2\right)+\left(x-2\right)=0\\ \Leftrightarrow\left(x^2+1\right)\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x^2+1=0\\x-2=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x^2=-1\left(vô.lí\right)\\x=2\end{matrix}\right.\\ Vậy:x=2\\ ---\\ 2x\left(3x-5\right)=10-6x\\ \Leftrightarrow6x^2-10x-10+6x=0\\ \Leftrightarrow6x^2-4x-10=0\\ \Leftrightarrow6x^2+6x-10x-10=0\\ \Leftrightarrow6x\left(x+1\right)-10\left(x+1\right)=0\\ \Leftrightarrow\left(6x-10\right)\left(x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}6x-10=0\\x+1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=-1\end{matrix}\right.\)

\(4-x=2\left(x-4\right)^2\\ \Leftrightarrow4-x=2\left(x^2-8x+16\right)\\ \Leftrightarrow2x^2-16x+32+x-4=0\\ \Leftrightarrow2x^2-15x+28=0\\ \Leftrightarrow2x^2-8x-7x+28=0\\ \Leftrightarrow2x\left(x-4\right)-7\left(x-4\right)=0\\ \Leftrightarrow\left(2x-7\right)\left(x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}2x-7=0\\x-4=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=4\end{matrix}\right.\\ ---\\ 4-6x+x\left(3x-2\right)=0\\ \Leftrightarrow4-6x+3x^2-2x=0\\ \Leftrightarrow3x^2-8x+4=0\\ \Leftrightarrow3x^2-6x-2x+4=0\\ \Leftrightarrow3x\left(x-2\right)-2\left(x-2\right)=0\\ \Leftrightarrow\left(3x-2\right)\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}3x-2=0\\x-2=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=2\end{matrix}\right.\)

a. (x80x - 801).12 = 0

⇔ x80 x (- 801) = 0

⇔ -64080x = 801

⇔ x = 0

(mấy câu tiếp mik ko hiểu lắm bn viết lại rõ đề rồi mik giải tiếp)

a) 2x² - 3x - 2 = 0.

<=> (2x + 1)(x - 2) = 0

<=> 2x + 1 = 0 hoặc x - 2 = 0

<=> x = -1/2 hoặc x = 2

b) 3x² - 7x - 10 = 0.

<=> (x + 1)(3x - 10) = 0

<=> x = -1 hoặc x = 10/3

c) 2x² - 5x + 3 = 0.

<=> (x - 1)(2x - 3) = 0

<=> x = 1 hoặc x = 3/2

\(x^2+7x+10=0\)

\(\left(x^2+2x\right)+\left(5x+10\right)=0\)

\(x\left(x+2\right)+5\left(x+2\right)=0\)

\(\left(x+2\right)\left(x+5\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+2=0\\x+5=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-2\\x=-5\end{cases}}\)

Vậy \(\orbr{\begin{cases}x=-2\\x=-5\end{cases}}\)

a. (80x - 801) . 12 = 0

<=> 80x - 801 = 0

<=> 80x = 801

<=> x = \(\dfrac{801}{80}\)

(Mấy câu tiếp mik ko hiểu đề, bn viết lại để dễ hiểu hơn nhé)

c: Ta có: \(\overline{xxx}=16\)

\(\Leftrightarrow100x+10x+1=16\)

\(\Leftrightarrow101x=16\)

hay \(x=\dfrac{16}{101}\)

a) \(7x-10=5x-6\)

\(7x-5x=-6+10\)

\(2x=4\)

\(x=2\)

b) \(3x\left(x-2\right)+x-2=0\)

\(\left(x-2\right)\left(3x+1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-2=0\\3x+1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=-\frac{1}{3}\end{cases}}\)

c) \(2x^2+7x-4=0\)

\(2x^2-x+8x-4=0\)

\(x\left(2x-1\right)+2\left(2x-1\right)=0\)

\(\left(2x-1\right)\left(x+2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}2x-1=0\\x+2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=-2\end{cases}}\)

7x-10=5x-6<=>7x-5x=-6+10<=>2x=4=>x=2

3x(x-2)+x-2=0<=>(x-2)(3x+1)=0<=>x-2=0=>x=2    HAY 3x+1=0=>x=-1/3

2x²+7x-4=0.

Câu cuối xem có lộn đề không nha bạn ơi!!!

a) 7x - 10 = 5x - 6

<=> 7x - 5x = -6 + 10

<=> 2x = 4

<=> x = 2

b) 3x( x - 2 ) + x - 2 = 0

<=> 3x( x - 2 ) + 1( x - 2 ) = 0

<=> ( x - 2 )( 3x + 1 ) = 0

<=> \(\orbr{\begin{cases}x-2=0\\3x+1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-\frac{1}{3}\end{cases}}\)

c) 2x² + 7x - 4 = 0

<=> 2x² + 8x - x - 4 = 0

<=> 2x( x + 4 ) - 1( x + 4 ) = 0

<=> ( x + 4 )( 2x - 1 ) = 0

<=> \(\orbr{\begin{cases}x+4=0\\2x-1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-4\\x=\frac{1}{2}\end{cases}}\)

\(x^2-7x+10=0\)

\(\left(x^2-2x\right)-\left(5x-10\right)=0\)

\(x.\left(x-2\right)-5\left(x-2\right)=0\)

\(\left(x-2\right)\left(x-5\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-2=0\\x-5=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=5\end{cases}}}\)

Vậy \(\orbr{\begin{cases}x=2\\x=5\end{cases}}\)

Tham khảo nhé~

\(x^2-7x+10=0\)

\(\Leftrightarrow x^2-5x-2x+10=0\)

\(\Leftrightarrow x\left(x-5\right)-2\left(x-5\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(x-5\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x-5=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=5\end{cases}}}\)

\(x^2-7x+10=0\)

\(\Rightarrow x^2-2x+5x+10=0\)

\(\Rightarrow x(x-2)-5(x-2)=0\)

\(\Rightarrow(x-5)(x-2)=0\)

\(\Rightarrow\hept{\begin{cases}x-5=0\\x-2=0\end{cases}\Rightarrow\hept{\begin{cases}x=5\\x=2\end{cases}}}\)\((\)tmđk\()\)

Chúc bạn học tốt :>

x² -7x + 10 = 0

=> x² - 2x - 5x + 10 = 0

=> x(x - 2) - 5(x - 2) = 0

=> (x - 5)(x - 2) = 0

=> \(\left[\begin{array}{nghiempt}x-5=0\\x-2=0\end{array}\right.\)   => \(\left[\begin{array}{nghiempt}x=5\\x=2\end{array}\right.\)

Vậy x = 2 hoặc x = 5

x² - 7x + 10 = 0

=> x² - 2x - 5x + 10 = 0

=> ( x² - 2x ) - ( 5x - 10 ) = 0

=> x( x - 2 ) - 5( x - 2 ) = 0

=> ( x - 2 ) . ( x - 5 ) = 0

Ta có:    x - 2 = 0

           => x = 2

hoặc      x - 5 = 0

            => x = 5

Vậy x = 2 hoặc x = 5

x² - 7x + 10 = 0

\(\Rightarrow\) (x - \(\frac{7}{2}\))² - \(\frac{9}{4}\) = 0

\(\Rightarrow\) (x - \(\frac{7}{2}\))² = \(\frac{9}{4}\)

\(\Rightarrow\) x - \(\frac{7}{2}\) = \(\frac{3}{2}\)

\(\Rightarrow\) x = 5