`x : 5/2 = 7/3`

`=> x= 7/3 xx 5/2`

`=>x= 35/6`

__

`23,7 xx 49 +23,7 xx 51`

`= 23,7 xx (49+51)`

`= 23,7 xx 100`

`=2370`

Lời giải:
a. 

$x=\frac{7}{3}\times \frac{5}{2}=\frac{35}{6}$

b.

$23,7\times 49+23,7\times 51=23,7\times (49+51)=23,7\times 100=2370$

x: 5/2=7/3`

`=> x = 7/3 xx 5/2`

`=> x=35/6`

Vậy `x = 35/6`

`23,7 xx 49 + 23,7 xx 51`

` =23,7 xx(49+51)`

`= 23,7 xx 100`

`=2370`

`3/7+2/5+4/7`

`=(3/7+4/7)+2/5`

`=1+2/5`

`=5/5+2/5`

`=7/5`

`20/34+4/9+7/17`

`=(20/34+7/17)+4/9`

`=(20/34+14/34)+4/9`

`=34/34+4/9`

`=1+4/9`

`=9/9+4/9`

`=13/9`

`48xx2+96+48xx6`

`=48xx2+48xx2+48xx6`

`=48xx(2+2+6)`

`=48xx10`

`=480`

câu thứ hai thì làm như này em nhé:

    \(\dfrac{20}{34}\) + \(\dfrac{4}{9}\) + \(\dfrac{7}{17}\)

= (\(\dfrac{20}{34}\) + \(\dfrac{7}{17}\)) + \(\dfrac{4}{9}\)

=  (\(\dfrac{10}{17}\) + \(\dfrac{7}{17}\)) + \(\dfrac{4}{9}\)

= 1 + \(\dfrac{4}{9}\)

= \(\dfrac{13}{9}\)

=3/5*\((\)2/7+4/7\()\)+2/5

=3/5*6/7+2/5

=18/35+2/5

=32/35

21/29

= 21/29 x (2/7 + 5/7)

= 21/29 x 1

= 21/29

= 21/29 x (2/7 + 5/7)

= 21/29 x 1

= 21/29

`2/5 xx 4/7 + 3/5 xx 4/7`

`= 4/7 xx (2/5 + 3/5)`

`= 4/7 xx 1`

`= 4/7`

\(\dfrac{2}{5}\times\dfrac{4}{7}+\dfrac{3}{5}\times\dfrac{4}{7}=\left(\dfrac{2}{5}+\dfrac{3}{5}\right)\times\dfrac{4}{7}=\dfrac{5}{5}\times\dfrac{4}{7}=1\times\dfrac{4}{7}=\dfrac{4}{7}\)

\(=\dfrac{4}{7}\times\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{4}{7}\)

\(=\dfrac{2}{5}\cdot\dfrac{7}{3}\cdot\dfrac{3}{7}\cdot\dfrac{5}{2}+2020=1+2020=2021\)

5/7 - 2/5 x 4/6 

= 5/7 - 2/5 x 2/3 

= 5/2 x 2/7 - 2/5 x 2/3 

= 5/2 x 2/7 + 5/2 x 2/3 

= 5/2 x 4/21

= 10/21

5/7 - 2/5 x4/6 

= 5/7 - 8/30

= 5/7 - 4/15

= (75- 28)/ 105

= 47/105

Tui rất cảm ơn b nhiều :))))

mik ko biet

A=\(\frac{2}{1}\cdot3+\frac{2}{3}\cdot5+\frac{2}{5}\cdot7+\frac{2}{7}\cdot9\)

A=\(\frac{3}{1}\cdot2+\frac{5}{3}\cdot2+\frac{7}{5}\cdot2+\frac{9}{7}\cdot2\)

A=\(2\cdot\left(3+\frac{5}{3}+\frac{7}{5}+\frac{9}{7}\right)\)

A=\(2\cdot\frac{772}{105}\)

A=\(\frac{1544}{105}\)

A=\(14\frac{74}{105}\)