a) 32 : (3.x - 2) = 8

3x - 2 = 32 : 8

3x - 2 = 4

3x = 4 + 2

3x = 6

x = 6 : 3

x = 2

b) 75 : (x - 18) = 25

x - 18 = 75 : 25

x - 18 = 3

x = 3 + 18

x = 21

c) (15 - 6.x) . 243 = 729

15 - 6x = 729 : 243

15 - 6x = 3

6x = 15 - 3

6x = 12

x = 12 : 6

x = 2

d) 4.(x - 12) + 9 = 17

4(x - 12) = 17 - 9

4(x - 12) = 8

x - 12 = 8 : 4

x - 12 = 2

x = 2 + 12

x = 14

e) 20 - 2.(x + 4) = 4

2(x + 4) = 20 - 4

2(x + 4) = 16

x + 4 = 16 : 2

x + 4 = 8

x = 8 : 2

x = 4

`32: ( 3xx x -2)=8`

`3xx x-2=32:8`

`3xx x-2=4`

`3 xx x=4+2`

`3xx x=6`

`x=6:3`

`x=2`

__

`75 : (x-18) =25`

`x-18=75:25`

`x-18= 3`

`x=3+18`

`x=21`

__

`(15-6 xx x ) xx 243 =729`

`15-6 xx x = 729 : 243`

`15-6 xx x = 3`

`6 xx x=15-3`

`6 xx x=12`

`x=12:6`

`x=2`

__

`4 xx (x-12)+9=17`

`4 xx (x-12)=17-9`

`4 xx (x-12)= 8`

`x-12=8:4`

`x-12=2`

`x=2+12`

`x=14`

__

`20-2xx(x+4)=4`

`2xx(x+4)=20-4`

`2xx(x+4)=16`

`x+4=16:2`

`x+4=8`

`x=8-4`

`x=4`

\(a,32:\left(3\times X-2\right)=8\\ 3\times X-2=32:8=4\\ 3\times X=4+2=6\\ X=\dfrac{6}{3}=2\\ Vậy:X=2\\ ---\\ b,75:\left(X-18\right)=25\\ X-18=75:25=3\\ X=3+18=21\\ Vậy:X=21\\ ---\\ c,\left(15-6\times X\right)\times243=729\\ 15-6\times X=729:243=3\\ 6\times X=15-3=12\\ X=\dfrac{12}{6}=2\\ Vậy:X=2\\ ---\\ d,4\times\left(X-12\right)+9=17\\ 4\times\left(X-12\right)=17-9=8\\ X-12=8:4=2\\ X=2+12=14\\ Vậy:X=14\\ ---\\ e,20-2\times\left(X+4+4\right)=4\\ 2\times\left(X+4\right)=20-4=16\\ X+4=16:2=8\\ X=8-4=4\\ Vậy:X=4\)

a, -1

b, -9

a: \(x+6\dfrac{1}{8}=8\)

=>\(x+\dfrac{49}{8}=\dfrac{64}{8}\)

=>\(x=\dfrac{64}{8}-\dfrac{49}{8}=\dfrac{15}{8}\)

b: \(\dfrac{11}{2}\cdot x=\dfrac{1}{5}:\dfrac{1}{3}\)

=>\(x\cdot\dfrac{11}{2}=\dfrac{1}{5}\cdot3=\dfrac{3}{5}\)

=>\(x=\dfrac{3}{5}:\dfrac{11}{2}=\dfrac{3}{5}\cdot\dfrac{2}{11}=\dfrac{6}{55}\)

c: \(x\cdot\dfrac{3}{5}+\dfrac{2}{5}\cdot x=\dfrac{4}{9}+\dfrac{1}{3}\)

=>\(x\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=\dfrac{4}{9}+\dfrac{3}{9}\)

=>\(x\cdot1=\dfrac{7}{9}\)

=>\(x=\dfrac{7}{9}\)

\(x:\dfrac{13}{16}=\dfrac{5}{-8}\\ x=\dfrac{5}{-8}.\dfrac{13}{16}=\dfrac{65}{-128}\)

\(x.\dfrac{-1}{2}=\dfrac{-4}{5}\\ x=\dfrac{-4}{5}:\dfrac{-1}{2}=\dfrac{8}{5}\)

\(a,121-\left(115+x\right)=3x-\left(25-9-5x\right)-8\\ 121-115-x=3x-25+9+5x-8\\ 6-x=8x-24\\ 8x+x=-24-6\\ 9x=-30\\ x=-\dfrac{30}{9}=-\dfrac{10}{3}\\ ----\\ b,2^{x+2}.3^{x+1}.5^x=10800\\ \left(2.3.5\right)^x.2^2.3=10800\\ 30^x.12=10800\\ 30^x=\dfrac{10800}{12}=900=30^2\\ Vậy:x=2\)

`4.(3-x)^10=9(3-x)^8`

`=>(3-x)^{8}(4(3-x)^2-9)=0`

`=>` $\left[ \begin{array}{l}3-x=0\\(3-x)^2=\dfrac{9}{4}\end{array} \right.$

`=>` $\left[ \begin{array}{l}x=3\\3-x=\dfrac{3}{2}\\3-x=-\dfrac{3}{2}\end{array} \right.$

`=>` $\left[ \begin{array}{l}x=3\\x=\dfrac{3}{2}\\x=\dfrac{9}{2}\end{array} \right.$

Vậy `x=3` hoặc `x=3/2` hoặc `x=9/2`

`b,(x-1)^{x+3}=(x-1)^{x+1}`

`=>(x-1)^{x+1}[(x-1)^2-1]=0`

`=>` $\left[ \begin{array}{l}x-=1\\x-=-1\end{array} \right.$

`=>` $\left[ \begin{array}{l}x=2\\x=1\\x=0\end{array} \right.$

Vậy `x=0` hoặc `x=1` hoặc `x=2`

a) 4(3 - x)¹⁰ = 9(3 - x)⁸

=> (x - 3)⁸.[4(x - 3)² - 9) = 0

<=> (x - 3)⁸.(2x - 6 - 3)(2x - 6 + 3) = 0

<=> (x - 3)⁸(2x - 9)(2x - 3) = 0

<=> \(\left[{}\begin{matrix}x-3=0\\2x-9=0\\2x-3=0\end{matrix}\right.\)

<=> \(\left[{}\begin{matrix}x=3\\x=\dfrac{9}{2}\\x=\dfrac{3}{2}\end{matrix}\right.\)

Vậy S = {3;9/2; 3/2}

b) (x - 1)^{x + 3} = (x - 1)^{x  + 1}

<=> (x - 1)^{x + 1}.[(x - 3)² - 1) = 0

<=>(x - 1)^{x + 1}.(x - 3 - 1)(x - 3 + 1) = 0

<=> (x - 1)^{x + 1}.(x - 4)(x - 2) = 0

<=> \(\left[{}\begin{matrix}x-1=0\\x-4=0\\x-2=0\end{matrix}\right.\)

<=> \(\left[{}\begin{matrix}x=1\\x=4\\x=2\end{matrix}\right.\)

b) Ta có: \(\left(x-1\right)^{x+3}=\left(x-1\right)^{x+1}\)

\(\Leftrightarrow\left(x-1\right)^{x+3}-\left(x-1\right)^{x+1}=0\)

\(\Leftrightarrow\left(x-1\right)^{x+1}\left[\left(x-1\right)^2-1\right]=0\)

\(\Leftrightarrow\left[{}\begin{matrix}\left(x-1\right)^{x+1}=0\\\left(x-1\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-1=0\\\left(x-1\right)^2=1\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x-1=1\\x-1=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\\x=0\end{matrix}\right.\)

Vậy: S={0;1;2}

a, 3 + x = 8

          x = 8 - 3

          x = 5

b, x + 4 = 0

    x       = 0 - 4

    x       = - 4

c x + 8 = 3

   x       = 3 - 8

   x       = -5

d 2 + x = -10

         x = -10 - 2

         x = - 12

a, -x/4 = -9/x

=> -x.x = 4.(-9)

=> -x² = -36

=> x² = 36

=> x = + 4

vậy_

b, x/4 = 18/x + 1

=> x(x + 1) = 4.18

=> x(x + 1) = 72

=> x(x + 1) = 8.9

=> x = 8

vậy_

a)\(\frac{-x}{4}=\frac{-9}{x}\)

\(\Rightarrow-x\times x=-9\times4\)

\(\Rightarrow-x^2=-36\)

\(\Rightarrow x=6\)

`a) x - 24/8 = 8`

    `x           = 8 + 24/8`

    `x           = 11`

`b) 76/18 - x × 17/3 = 4/9`

                `x × 17/3 = 76/18 - 4/9`

                `x × 17/3 = 34/9`

                `x            = 34/9 : 17/3`

                `x            = 2/3`

a, X = 8 + 24/8

X = 11

b, X x 17/3 = 76/18 - 4/9

X x 17/3 = 34/9

X = 34/9 : 17/3

X = 2/3