(x-7)^x+1-(x-7)^x+11=0

=>x-7=0

=>x=7

(8x-1)²ⁿ⁺¹=5²ⁿ⁺¹

=>8x-1=5

=>8x=6

=>x=3/4

Tick Đúng Nha

\(\left(8x-1\right)^{2n+1}=5^{2n+1}\)

\(\Leftrightarrow8x-1=5\)

\(\Leftrightarrow x=\frac{3}{4}\)

\(\left(8x-1\right)^{2n+1}=5^{2n+1}\)

\(\Rightarrow8x-1=5\)

\(\Rightarrow8x=6\)

\(\Rightarrow x=\frac{3}{4}\)

Vậy \(x=\frac{3}{4}\)

b) \(\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6\)

\(\Rightarrow\left(x-\dfrac{2}{9}\right)^3=\left[\left(\dfrac{2}{3}\right)^2\right]^3=\left(\dfrac{4}{9}\right)^3\)

\(\Rightarrow x-\dfrac{2}{9}=\dfrac{4}{9}\)

\(\Rightarrow x=\dfrac{2}{3}\)

Thui làm hộ cho:

\(\left(8x-1\right)^{2n-1}:5=5^{2n}\)

\(\left(8x-1\right)^{2n-1}=5^{2n}.5\)

mà àm cho khỏi nhân 5 hay chia 5 vậy

\(\left(8x-1\right)^{2n+1}=5^{2n+1}\)

\(8x-1=5\)

\(8x=6\)

\(x=\dfrac{3}{4}\)

=.= hok tốt!!

a: \(=24x^{2m-1+3-2m}y^{6-3m}-\dfrac{24}{7}y^{3n-7+6-3n}\cdot x^{3-2m}+8x^{3-2m+2m}\cdot y^{6-3n+3m}-24x^{3-2m}y^{6-2n+2}\)

\(=24x^2y^{6-3m}-\dfrac{24}{7}x^{3-2m}\cdot y^{-1}+8x^3y^{-3n+3m+6}-24x^{3-2m}y^{-2n+8}\)

b: \(=2x^{2n+1-2n}-6x^{2n+2-2n}+3x^{2n-1+1-2n}-9x^{2n-1+2-2n}\)

\(=2x-6x^2+3-9x\)

\(=-6x^2-7x+3\)

 nếu n E N thì 2n+1 là số lẻ lúc đó  ta có:

(8x-1)²ⁿ⁺¹  = 5²ⁿ⁺¹

<=> 8x - 1 = 5

<=> 8n = 6

<=> n = 6/8 = 3/4

Lớp 5 đã học giải pt rồi á em?