a) \(175-\left(42:x+95\right)=3\)

\(\Rightarrow42:x+95=172\)

\(\Rightarrow42:x=77\)

\(\Rightarrow x=42:77\)

\(\Rightarrow x=\dfrac{6}{11}\)

b) \(450:\left(75-13\cdot x\right)=10\)

\(\Rightarrow75-13\cdot x=450:10\)

\(\Rightarrow75-13\cdot x=45\)

\(\Rightarrow13\cdot x=75-45\)

\(\Rightarrow13\cdot x=30\)

\(\Rightarrow x=\dfrac{30}{13}\)

a: Ta có: \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)

\(\Leftrightarrow x^2+5x-10=x^2+3x-4\)

\(\Leftrightarrow2x=6\)

hay x=3

18,22 - 3 . x = 6,22

=> 3 . x = 18,22 - 6,22

=> 3 . x = 12

=> x = 12 : 3 

=> x = 4

\(18\times22-3\times x=6\times22\)

\(\Rightarrow18\times22-3\times x=132\)

\(\Rightarrow396-3\times x=132\)

\(\Rightarrow3\times x=396-132\)

\(\Rightarrow3\times x=264\)

\(\Rightarrow x=264\div3\)

\(\Rightarrow x=88\)

3.x laf sao

Ta có : 

\(\frac{4}{x}+\frac{y}{3}=\frac{5}{6}\)

\(\Leftrightarrow\)\(\frac{4}{x}=\frac{5}{6}-\frac{y}{3}\)

\(\Leftrightarrow\)\(\frac{4}{x}=\frac{5-2y}{6}\)

\(\Leftrightarrow\)\(x\left(5-2y\right)=24\)

Lập bảng xét \(Ư\left(24\right)\) ( tự lập ) 

Chúc bạn học tốt ~ 

( fx) + g(x) + (f(x) - g(x) = 6x^4 - 3x^2 - 5 + 4x^4 - 6x^3 + 7x^2 + 8x - 9 

                                   = 10x^4 +   4x^2  + 8x - 14 

=> 2fx = 2 (  5x^4  + 2 x^2 + 4x - 7)

=> f(x) = 5x^4 + 2x^2 + 4x - 7 

Tính tiếp g(x) nha 

Bài 1:
a) \(2\)\(\dfrac{2}{3}\)\(=\dfrac{8}{3}\)
b) \(1\)\(\dfrac{5}{7}=\dfrac{12}{7}\)

\(\dfrac{3}{2}x+\dfrac{3}{7}=-\dfrac{4}{5}\)

\(\Leftrightarrow\dfrac{3}{2}x=-\dfrac{43}{35}\)

\(\Leftrightarrow x=-\dfrac{86}{105}\)

Vậy \(x=-\dfrac{86}{105}\)

\(-\dfrac{11}{12}x+0,25=\dfrac{5}{6}\)

\(\Leftrightarrow-\dfrac{11}{12}x+\dfrac{1}{4}=\dfrac{5}{6}\)

\(\Leftrightarrow-\dfrac{11}{12}x=\dfrac{7}{12}\)

\(\Leftrightarrow x=-\dfrac{7}{11}\)

Vậy \(x=-\dfrac{7}{11}\)

\(\left(x-2\right)^2=1\)

\(\Leftrightarrow\left(x-2\right)^2-1=0\)

\(\Leftrightarrow\left(x-2-1\right)\left(x-2+1\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-1=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Vậy x = {3; 1}\(\left(2x-1\right)^3=-8\)

\(\Leftrightarrow2x-1=-2\)

\(\Leftrightarrow2x=-1\)

\(\Leftrightarrow x=-\dfrac{1}{2}\)

Vậy \(x=-\dfrac{1}{2}\)

       (x - 2)² = 1

<=>\(\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.< =>\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Vậy x = 3; 1

(2x - 1)³ = -8

<=> 2x - 1 = -2

<=> 2x = -1

<=> x = \(\dfrac{-1}{2}\)

Vậy x = \(\dfrac{-1}{2}\)

\(|\) 2,5 - x\(|\) = 1,3

1,6- \(|\)x - 0,2 \(|\)= 0

13^x = 169

\(\dfrac{-2}{x}\)=\(\dfrac{-x}{8\dfrac{ }{25}}\)

\(\dfrac{x}{-15}\)=\(\dfrac{-60}{x}\)

\(|\)x\(|\)+0,573=2

`(x - 2)/3 = (x + 1)/4`

`(x - 2) . 4 = (x + 1) . 3`

`<=> 4x - 8 = 3x + 3`

`<=> 4x - 3x = 3 + 8`

`<=> (4 - 3)x = 11`

`=> x = 11`

`=>` `x = 11`

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