\(x:\left[\dfrac{8}{5}\cdot\left(\dfrac{2}{3}\right)^2-\dfrac{2}{5}\right]=\dfrac{15}{7}+\dfrac{6}{5}\left[\left(2\dfrac{1}{7}\right)^2-\dfrac{50}{49}\right]\)

\(\Leftrightarrow x:\left[\dfrac{32}{45}-\dfrac{18}{45}\right]=\dfrac{15}{7}+\dfrac{6}{5}\cdot\left(\dfrac{225}{49}-\dfrac{50}{49}\right)\)

\(\Leftrightarrow x:\dfrac{14}{45}=\dfrac{15}{7}+\dfrac{6}{5}\cdot\dfrac{25}{7}\)

\(\Leftrightarrow x:\dfrac{14}{45}=\dfrac{45}{7}\)

\(\Leftrightarrow x=2\)

\(A=\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{50}}\)

\(3.A=1+\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{49}}\)

\(2A=3A-A=1-\dfrac{1}{3^{49}}\)

\(\Rightarrow A=\dfrac{1-\dfrac{1}{3^{50}}}{2}\)

\(B=\dfrac{5}{3}+\dfrac{5}{3^2}+...+\dfrac{5}{3^{50}}=5\left(\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{50}}\right)\)

Căn cứ vào câu A thì các trong ngặc bằng \(\dfrac{1-\dfrac{1}{3^{50}}}{2}\)

suy ra \(B=\dfrac{5\left(1-\dfrac{1}{3^{50}}\right)}{2}\)

tick mik nha

hoi kho day

`c)1/(2sqrt2)-3/2sqrt{4,5}+2/5sqrt{50}`

`=1/(2sqrt2)-3/2sqrt{9/2}+2/5sqrt{25.2}`

`=1/(2sqrt2)-9/(2sqrt2)+2sqrt2`

`=2sqrt2-8/(2sqrt2)`

`=2sqrt2-sqrt2=sqrt2`

`d)4/(3+sqrt5)-8/(1+sqrt5)+15/sqrt5`

`=(4(3-sqrt5))/(9-5)-(8(sqrt5-1))/(5-1)+3sqrt5`

`=3-sqrt5-2(sqrt5-1)+3sqrt5`

`=3+3sqrt5-3sqrt5+2=5`

\(a,=\dfrac{13}{50}\cdot\dfrac{50}{13}\cdot\left(-\dfrac{31}{2}\right)\cdot\dfrac{169}{2}=-\dfrac{5239}{2}\\ b,=\dfrac{-\dfrac{49}{100}\cdot\left(-125\right)}{-\dfrac{343}{27}\cdot\dfrac{81}{16}\cdot\left(-1\right)}=\dfrac{\dfrac{245}{4}}{\dfrac{1029}{16}}=\dfrac{245}{4}\cdot\dfrac{16}{1029}=\dfrac{20}{21}\)

a) \(\dfrac{13}{50}.\left(-15.5\right):\dfrac{13}{50}.84\dfrac{1}{2}=\dfrac{13}{50}.-75:\dfrac{13}{50}.\dfrac{169}{2}=-\dfrac{75.169}{2}=-\dfrac{12675}{2}\)

b) \(\dfrac{\left(-0,7\right)^2.\left(-5\right)^3}{\left(-2\dfrac{1}{3}\right)^3.\left(1\dfrac{1}{2}\right)^4.\left(-1\right)^5}=\dfrac{0,49.\left(-125\right)}{-\dfrac{343}{27}.\dfrac{81}{16}.\left(-1\right)}=-\dfrac{\dfrac{245}{4}}{\dfrac{1029}{16}}=\dfrac{20}{21}\)

\(A=12\dfrac{2}{5}.\left(\dfrac{-7}{3}\right)-3\dfrac{2}{5}.\left(\dfrac{-7}{3}\right)\)

\(A=\dfrac{62}{5}.\left(\dfrac{-7}{3}\right)-\dfrac{17}{5}.\left(\dfrac{-7}{3}\right)\)

\(A=\left(\dfrac{-7}{3}\right).\left(\dfrac{62}{5}-\dfrac{17}{5}\right)\)

\(A=\left(\dfrac{-7}{3}\right).\dfrac{45}{5}\)

\(A=-21\)

\(B=\left(\dfrac{2}{3}\right)^3:\left(\dfrac{2}{3}\right)^2+\left(-1\dfrac{1}{2}\right):150\%\)

\(B=\left(\dfrac{2}{3}\right)^1-\dfrac{3}{2}:1,5\)

\(B=\dfrac{2}{3}-\dfrac{3}{2}:\dfrac{3}{2}\)

\(B=\dfrac{2}{3}-1\)

\(B=-\dfrac{1}{3}\)

A = \(12\dfrac{2}{5}\) . (\(\dfrac{-7}{3}\)) - \(3\dfrac{2}{5}\) . (\(\dfrac{-7}{3}\))

A = (\(\dfrac{-7}{3}\)) . ( \(12\dfrac{2}{5}\) - \(3\dfrac{2}{5}\) )

A = (\(\dfrac{-7}{3}\)) . ( \(\dfrac{62}{5}\) - \(\dfrac{17}{5}\) )

A = (\(\dfrac{-7}{3}\)) . 9

A = \(\dfrac{-7.9}{3}\)

A = \(\dfrac{-63}{3}\) = -21

B = \(\left(\dfrac{2}{3}\right)^3\) : \(\left(\dfrac{2}{3}\right)^2\) + \(\left(-1\dfrac{1}{2}\right)\) : 150 %

B = \(\left(\dfrac{2}{3}\right)^{3-2}\) + \(\dfrac{-3}{2}\) : \(\dfrac{3}{2}\)

B = \(\dfrac{2}{3}\) + -1

B = \(\dfrac{-1}{3}\)

Bài 3

a,26/100+0,009+41/100+0,24

0,26+0,09+0,41+0,24

(0,26+0,24)+(0,09+0,41)

0,5+0,5

=1

b,9+1/4+6+2/7+7+3/5+8+2/3+2/5+1/3+5/7+3/4

(9+6+7+8)+(2/7+5/7)+(1/4+3/4)+(3/5+2/5)+(2/3+1/3)

30+1+1+1+1

=34

Bài 4,5 khó quá mik ko bít lamf^^))

Bài 5: vì \(\dfrac{3}{11}\) = \(\dfrac{3\times5}{11\times5}\) = \(\dfrac{15}{55}\)

Vậy Khi giữ nguyên tử số thì số cần thêm vào mẫu số là: 

              55 - 39 = 16

Đáp số: 16 

Bài 4: a, \(\dfrac{2008}{2009}\) < 1; \(\dfrac{10}{9}\) > 1

           \(\dfrac{2008}{2009}\) < \(\dfrac{10}{9}\)

         b, \(\dfrac{1}{a+1}\) và \(\dfrac{1}{a-1}\)

Ta có: a + 1 > a - 1 ⇒ \(\dfrac{1}{a+1}\) < \(\dfrac{1}{a-1}\)

`(50% . x+5 1/4) . (-2/3) = 2 5/6`

`(1/2 x + 21/4) . (-2/3) = 17/6`

`1/2 x + 21/4 = -17/4`

`1/2 x = -19/2`

`x=-19`

\(^{^{tham}}\) \(^{^{khảo}}\)

\(\left(50\%.+5\dfrac{1}{4}\right).\left(-\dfrac{2}{3}\right)=2\dfrac{5}{6}\)

\(\left(\dfrac{1}{2}x+\dfrac{21}{2}\right).\left(-\dfrac{2}{3}\right)=\dfrac{17}{6}\)
\(\dfrac{1}{2}x+\dfrac{21}{4}=-\dfrac{17}{4}\)

\(\dfrac{1}{2}x=-\dfrac{19}{2}\)

\(x=-19\)

\(\left(50\%.x+5\dfrac{1}{4}\right).\dfrac{-2}{3}=2\dfrac{5}{6}\) 

                 \(\dfrac{1}{2}.x+\dfrac{21}{4}=\dfrac{17}{6}:\dfrac{-2}{3}\) 

                 \(\dfrac{1}{2}.x+\dfrac{21}{4}=\dfrac{-17}{4}\) 

                           \(\dfrac{1}{2}.x=\dfrac{-17}{4}-\dfrac{21}{4}\) 

                           \(\dfrac{1}{2}.x=\dfrac{-19}{2}\) 

                                \(x=\dfrac{-19}{2}:\dfrac{1}{2}\) 

                                \(x=-19\)

a: =>x-3/4=1/6-1/2=1/6-3/6=-2/6=-1/3

=>x=-1/3+3/4=-4/12+9/12=5/12

b: =>x(1/2-5/6)=7/2

=>-1/3x=7/2

hay x=-21/2

c: (4-x)(3x+5)=0

=>4-x=0 hoặc 3x+5=0

=>x=4 hoặc x=-5/3

d: x/16=50/32

=>x/16=25/16

hay x=25

e: =>2x-3=-1/4-3/2=-1/4-6/4=-7/4

=>2x=-7/4+3=5/4

hay x=5/8