\(\dfrac{x}{4}+\dfrac{x}{8}+x:2=\dfrac{21}{8}\\ x\times\left(\dfrac{1}{8}+\dfrac{1}{4}+\dfrac{1}{2}\right)=\dfrac{21}{8}\\ x\times\dfrac{7}{8}=\dfrac{21}{8}\\ x=3.\)

\(\dfrac{x}{4}\) + \(\dfrac{x}{8}\) + \(\dfrac{x}{2}\) = \(\dfrac{21}{8}\)

\(x\) \(\times\) ( \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{2}\)) = \(\dfrac{21}{8}\)

\(x\) \(\times\)  \(\dfrac{7}{8}\) = \(\dfrac{21}{8}\)

\(x\)          = \(\dfrac{21}{8}\) : \(\dfrac{7}{8}\)

\(x\)          = 3

\(\dfrac{x}{4}+\dfrac{x}{8}+\dfrac{x}{2}=\dfrac{21}{8}\)

\(\left(\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{2}\right).x=\dfrac{21}{8}\)

\(\left(\dfrac{2}{8}+\dfrac{1}{8}+\dfrac{4}{8}\right).x=\dfrac{21}{8}\)

\(\dfrac{7}{8}.x=\dfrac{21}{8}\)

\(x=\dfrac{21}{8}:\dfrac{7}{8}\)

\(x=\dfrac{21}{8}.\dfrac{8}{7}=3\)

a: =>3/8x6/3<x<20/21x21/4

=>3/4<x<5

hay \(x\in\left\{1;2;3;4\right\}\)

b: =>56/42<x<11/2

=>4/3<x<11/2

nên \(x\in\left\{2;3;4;5\right\}\)

a: =>3/8x6/3<x<20/21x21/4

=>3/4<x<5

hay \(x\in\left\{1;2;3;4\right\}\)

b: =>56/42<x<11/2

=>4/3<x<11/2

nên \(x\in\left\{2;3;4;5\right\}\)

a: \(=\dfrac{3}{5}:\dfrac{7}{5}=\dfrac{3}{5}\cdot\dfrac{5}{7}=\dfrac{3}{7}\)

b: \(=\dfrac{9}{17}\left(\dfrac{8}{5}-\dfrac{3}{5}\right)+\dfrac{8}{17}\)

=9/17+8/17=1

c: =>x-3/10=7/15*1/5=7/75

=>x=7/75+3/10=59/150

mn. giúp em nha 

\(a.\dfrac{6}{5}=\dfrac{18}{x}\Rightarrow x=\dfrac{18\cdot5}{6}=15\\ \text{Vậy}\text{ }x=15.\)

\(b.\dfrac{3}{4}=\dfrac{-21}{x}\Rightarrow x=\dfrac{-21\cdot4}{3}=28\\ \text{ }\text{ }\text{ }\text{ }\text{Vậy }x=28.\)

\(c.\dfrac{x}{4}=\dfrac{21}{28}\Rightarrow x=\dfrac{21\cdot4}{28}=3\\ \text{Vậy }x=3.\)

\(d.\dfrac{-8}{2x}=\dfrac{3}{-9}\Rightarrow x=\dfrac{-8\cdot\left(-9\right)}{3}:2=12\\ \text{Vậy }x=12.\)

\(e.\dfrac{-4}{11}=\dfrac{x}{22}=\dfrac{40}{z}\\ \Rightarrow x=\dfrac{-4\cdot22}{11}=-8\\ \Rightarrow z=\dfrac{22\cdot40}{-8}=-110\\ \text{Vậy }x=-8;z=-110.\)

\(f.\dfrac{-3}{4}=\dfrac{x}{20}=\dfrac{21}{y}\\ \Rightarrow x=\dfrac{-3\cdot20}{4}=-15\\ \Rightarrow y=\dfrac{21\cdot20}{-15}=-28\\ \text{Vậy }x=-15;y=-28.\)

\(g.\dfrac{-4}{8}=\dfrac{x}{-10}=\dfrac{-7}{y}=\dfrac{z}{-24}\\ \Rightarrow x=\dfrac{-4\cdot\left(-10\right)}{8}=5\\ \Rightarrow y=\dfrac{-7\cdot\left(-10\right)}{5}=14\\ \Rightarrow z=\dfrac{-7\cdot\left(-24\right)}{14}=12\\ \text{Vậy }x=5;y=14;z=12.\)

\(h.\dfrac{x}{4}=\dfrac{9}{x}\\ \Rightarrow x\cdot x=9\cdot4\\ \Rightarrow x\cdot x=36\\ \Rightarrow x\cdot x=6\cdot6\\ \text{Vậy }\text{cả hai }x=6.\)

a) Ta có: \(\dfrac{-11}{15}< \dfrac{x}{15}< \dfrac{-8}{15}\)

nên -11<x<-8

hay \(x\in\left\{-10;-9\right\}\)

b) Ta có: \(\dfrac{3}{7}< \dfrac{x}{21}< \dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{9}{21}< \dfrac{x}{21}< \dfrac{14}{21}\)

Suy ra: 9<x<14

hay \(x\in\left\{10;11;12;13\right\}\)

c) Ta có: \(\dfrac{-67}{21}< \dfrac{x}{168}< \dfrac{-3}{8}\)

nên \(\dfrac{-536}{168}< \dfrac{x}{168}< \dfrac{-63}{168}\)

Suy ra: -536<x<-63

hay \(x\in\left\{-535;-534;...;-64\right\}\)

\(\dfrac{26}{81}+\dfrac{4}{27}=\dfrac{26+12}{81}=\dfrac{38}{81}\)

\(\dfrac{5}{64}+\dfrac{7}{8}=\dfrac{5+56}{64}=\dfrac{61}{64}\)

\(\dfrac{26}{81}+\dfrac{4}{27}=\dfrac{26}{81}+\dfrac{4\times3}{27\times3}=\dfrac{26}{81}+\dfrac{12}{81}=\dfrac{38}{81}\)

\(\dfrac{5}{64}+\dfrac{7}{8}=\dfrac{5}{64}+\dfrac{7\times8}{8\times8}=\dfrac{5}{64}+\dfrac{56}{64}=\dfrac{61}{64}\)