\(x+\dfrac{518}{6}+60=313\\ x+\dfrac{518}{6}=313-60\\ x+\dfrac{518}{6}=253\\ x=253-\dfrac{518}{6}\\ x=\dfrac{1518}{6}-\dfrac{518}{6}\\ x=\dfrac{1000}{6}=\dfrac{500}{3}\)

Haizz

Sử dụng tính chất tỉ lệ thức, có thể biến đổi phương trình như sau

Chia cả hai vế cho cùng một số

Đơn giản biểu thức

Lời giải thu được

lớp 4 đã học hỗn số đâu

\(B=\left(17+\dfrac{1}{25}-16-\dfrac{11}{15}\right)\cdot\dfrac{75}{23}+\dfrac{75}{23}\cdot\dfrac{23}{75}\)

\(=\dfrac{23}{75}\cdot\dfrac{75}{23}+1=1+1=2\)

b: \(\Leftrightarrow\dfrac{20}{x}-\dfrac{20}{x+20}=\dfrac{1}{6}\)

=>\(\dfrac{20x+400-20x}{x\left(x+20\right)}=\dfrac{1}{6}\)

=>x*(x+20)=400*6=2400

=>x^2+20x-2400=0

=>(x+60)(x-40)=0

=>x=-60 hoặc x=40

c: \(\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}=\dfrac{8}{4x^2-1}\)

=>(2x+1)^2-(2x-1)^2=8

=>4x^2+4x+1-4x^2+4x-1=8

=>8x=8

=>x=1(nhận)

\(\dfrac{3}{2}+\dfrac{13}{6}+\dfrac{37}{12}+\dfrac{81}{20}+\dfrac{151}{30}+\dfrac{253}{42}+\dfrac{393}{56}+\dfrac{577}{72}+\dfrac{811}{90}\)

\(=\dfrac{459}{10}\)

\(\dfrac{3}{2}+\dfrac{13}{6}+\dfrac{37}{12}+\dfrac{81}{20}+\dfrac{151}{30}+\dfrac{253}{42}+\dfrac{393}{56}+\dfrac{577}{72}+\dfrac{811}{90}\)\(=\dfrac{2}{2}+\dfrac{1}{2}+\dfrac{12}{6}+\dfrac{1}{6}+\dfrac{36}{12}+\dfrac{1}{12}+\dfrac{80}{20}+\dfrac{1}{20}+\dfrac{150}{30}+\dfrac{1}{30}+\dfrac{252}{42}+\dfrac{1}{42}+\dfrac{392}{56}+\dfrac{1}{56}+\dfrac{576}{72}+\dfrac{1}{72}+\dfrac{810}{90}+\dfrac{1}{90}\)\(=1+\dfrac{1}{2}+2+\dfrac{1}{6}+3+\dfrac{1}{12}+4+\dfrac{1}{20}+5+\dfrac{1}{30}+6+\dfrac{1}{42}+7+\dfrac{1}{56}+8+\dfrac{1}{72}+9+\dfrac{1}{90}\)\(=\left(1+2+3+4+5+6+7+8+9\right)+\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\right)\)= 45 + \(\dfrac{9}{10}\)

= \(\dfrac{459}{10}\)

\(\dfrac{3}{2}+\dfrac{13}{6}+\dfrac{37}{12}+\dfrac{81}{20}+\dfrac{151}{30}+\dfrac{253}{42}+\dfrac{393}{56}+\dfrac{393}{56}+\dfrac{577}{72}+\dfrac{811}{90}\)

\(\dfrac{3780+5460+7770+10206+12684+15180+17685+20195+22708}{2520}\)=\(\dfrac{115668}{2520}=\dfrac{459}{10}\)

\(\Rightarrow x=\dfrac{60.\left(-6\right)}{30}=-12\)

\(\Rightarrow x=\dfrac{60.-6}{30}=-12\)

=>-6.60=30.x

=>-360=30.x

=>x=-360:30

=>x=-12

Câu 1; B

Câu 2: B