Bài 1:

H2 + O2 → H2O

N2O5 + H2O → HNO3

Bài 4:

Fe2(SO3)3: Sắt III sunfat 

Mg(OH)2: Magie hidroxit

H3PO4: axit photphoric

Ba(HSO4)2: Bari Bisunfat 

Bài 1 : 

\(a.2H_2+O_2\underrightarrow{^{t^0}}2H_2O\)

\(b.N_2O_5+H_2O\rightarrow2HNO_3\)

Bài 2 : 

\(n_{Al}=\dfrac{5.4}{27}=0.2\left(mol\right)\)

\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

\(0.2............0.3...........0.1..............0.3\)

\(m_{H_2SO_4}=0.3\cdot98=29.4\left(g\right)\)

\(m_{Al_2\left(SO_4\right)_3}=0.1\cdot342=34.2\left(g\right)\)

\(m_{H_2}=0.3\cdot2=0.6\left(g\right)\)

\(V_{H_2}=0.3\cdot22.4=6.72\left(l\right)\)

Bài 3 : 

\(n_{A\left(OH\right)_n}=0.2\cdot1=0.2\left(mol\right)\)

\(2A+2nH_2O\rightarrow2A\left(OH\right)_n+nH_2\)

\(0.2........................0.2\)

\(M_A=\dfrac{8}{0.2}=40\left(\dfrac{g}{mol}\right)\)

\(A:Canxi\:\)

Bài 4 : 

Fe₂(SO₄)₃ : Sắt (III) sunfat 

Mg(OH)₂ : Magie hidroxit

H₃PO₃: Axit photphoro

Ba(HSO₄)₂: Bari hidrosunfat

\(a)n_{H_2}=\dfrac{6,72}{22,4}=0,3mol\\ 2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\\ 0,2\leftarrow-0,3\leftarrow-0,1\leftarrow---0,3\)

\(a=m_{Al}=0,2.27=5,4g\\ b)m_{Al_2\left(SO_4\right)_3}=0,1.342=34,2g\\ c)C_{\%H_2SO_4}=\dfrac{0,3.98}{100}\cdot100=29,4\%\)

a)nH2​​=22,46,72​=0,3mol2Al+3H2​SO4​→Al2​(SO4​)3​+3H2​0,2←−0,3←−0,1←−−−0,3

�=���=0,2.27=5,4��)���2(��4)3=0,1.342=34,2��)�%�2��4=0,3.98100⋅100=29,4%a=mAl​=0,2.27=5,4gb)mAl2​(SO4​)3​​=0,1.342=34,2gc)C%H2​SO4​​=1000,3.98​⋅100=29,4%

3 Fe + 2 O2 -to-> Fe3O4

-> P.ứ hóa hợp

2KMnO4 -to-> 2 KMnO4 + MnO2 + O2

-> P.ứ phân hủy

P2O5 + 3 H2O -> 2 H3PO4

-> P.ứ hóa hợp

a, Fe + O₂ --to--> Fe₃O₄ (phản ứng hóa hợp )

b, KMnO₄ --to--> K₂MnO₄ + MnO₂ + O₂ ( phản ứng phân hủy)

c, P₂O_{5 ⁺} H₂O ---to-->H₃PO₄ ( phản ứng hóa hợp)

\(CuSO_4+2KOH\rightarrow Cu\left(OH\right)_2\downarrow+K_2SO_4\\ Zn+2HCl\rightarrow ZnCl_2+H_2\\ 2KClO_3\rightarrow^{t^o}2KCl+3O_2\\ 4Al+3O_2\rightarrow^{t^o}2Al_2O_3\\ 2Fe+3Cl_2\rightarrow^{t^o}2FeCl_3\\ Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow3Al_2\left(SO_4\right)_3+H_2O\)

CH4+2 O2  ---to-->.......CO2+2H2O

4P + 5O2--to---->...2P2O5.....

SO3+H2O...-------> H2SO4

P2O5+3H2O->2H3PO4

2KMnO4 ---to----->......K2MNO4...+......MnO2..+..O2.....

2KClO3-------->..2KCl.......+...3.O2...

\(CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\\ 4P+5O_2\underrightarrow{t^o}2P_2O_5\\ P_2O_5+3H_2O\rightarrow2H_3PO_4\\ 2KMnO_4\underrightarrow{t^o}K_2MnO_4+MnO_2+O_2\\ 2KCl\xrightarrow[xtMnO_2]{t^o}2KCl+3O_2\)

Ca(H2PO4)2: muối axit: canxi đihiđrophotphat

NaHSO4: muối axit: natri hiđrosunfat

CaCO3: muối trung hòa: canxi cacbonat

Fe(OH)2: sắt (II) hiđroxit

Mg(NO3)2: muối trung hòa: magie nitrat

FeS: muối trung hòa: sắt (II) sunfua

NaCl: muối trung hòa: natri clorua

BaCl2: muối trung hòa: bari clorua

CuSO4: muối trung hòa: đồng (II) sunfat

Cu(HSO4)2: muối axit: đồng (II) hiđrosunfat

Cu(H2PO4)2: muối axit: đồng (II) đihiđrophotphat 

\(a,A=log_23\cdot log_34\cdot log_45\cdot log_56\cdot log_67\cdot log_78\\ =log_28\\ =log_22^3\\ =3\\ b,B=log_22\cdot log_24...log_22^n\\ =log_22\cdot log_22^2...log_22^n\\ =1\cdot2\cdot...\cdot n\\ =n!\)

\(1)\\ a) 4Na + O_2 \xrightarrow{t^o} 2Na_2O\\ b) Zn + 2HCl \to ZnCl_2 + H_2\\ c) CaO + H_2O \to Ca(OH)_2\\ d) SO_3 + H_2O \to H_2SO_4\\ 2)\\ a) 2Ba + O_2 \xrightarrow{t^o} 2BaO\\ b) CuO + H_2 \xrightarrow{t^o} Cu + H_2O\\ c) K + H_2O \to KOH + \dfrac{1}{2}H_2\\ d) CO_2 + H_2O \to H_2CO_3\)

\(Pt: 2Al+3H_2SO_4 \rightarrow Al_2(SO_4)_3 + 3H_2\)

\(a.n_{H_2}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\)

Theo pt: \(n_{Al}=\dfrac{2}{3}n_{H_2}=0,2\left(mol\right)\)

\(\Rightarrow m_{Al}=a=0,2.27=5,4\left(g\right)\)

\(b.n_{Al_2\left(SO_4\right)_3}=\dfrac{1}{3}n_{H_2}=0,1\left(mol\right)\)

\(\Rightarrow m_{Al_2\left(SO_4\right)_3}=0,1.342=34,2g\)

\(c.\)Theo pt: \(n_{H_2SO_4}=n_{H_2}=0,3\left(mol\right)\)

\(\Rightarrow m_{H_2SO_4}=0,3.98=29,4g\)

\(C_{\%}H_2SO_4=\dfrac{29,4}{100}.100\%=29,4\%\)