Đề yêu cầu gì em?

\(x^2-5x+6=\left(x-2\right)\left(x-3\right)\)

\(x^2-7x+12=\left(x-2\right)\left(x-5\right)\)

\(x^2+x-12=\left(x-5\right)\left(x+6\right)\)

\(x^2-9x+20=\left(x-4\right)\left(x-5\right)\)

\(2x^2-3x+2=2\left(x+\dfrac{1}{2}\right)\left(x-2\right)\)

\(4x^2-7x-2=4\left(x-2\right)\left(x+\dfrac{1}{4}\right)\)

\(4x^2+15x+9=4\left(x+\dfrac{3}{4}\right)\left(x+3\right)\)

Ta có:

\(\frac{12x-15y}{7}=\frac{20z-12x}{9}=\frac{15y-20z}{11}\)

Áp dụng tính chất dãy tỉ số bằng nhau ta được:

Áp dụng tính chất dãy tỉ số bằng nhau ta được:

Vậy \(\left(x;y;z\right)=\left(20;16;12\right).\)

Chúc bạn học tốt!

a) 

=x² - x +16x -16

=x(x-1) +16(x-1)

=(x+16)(x-1)

b)

=x²- x + 13x - 13

=x(x-1) + 13(x-1)

=(x+13)(x-1)

15x² - 12x = 0

=> x.(15x - 12) = 0

=> x = 0 hoặc 15x - 12 = 0

=> x = 0 hoặc 15x = 12

=> x = 0 hoặc x = 4/5

Vậy...

Cam on Minh Hien!!!

T a có: 15.x.x-12x=0

suy ra x.(15-12-1)=0

suy ra x. 2=0

suy ra x=0:2

suy ra x=0

Vậy x=0

Bạn học căn thức chưa ?

phan tich cac da thuc sau thanh nhan tu theo mau:

a)\(2x^3-x\)

\(=x\left(2x^2-1\right)\)

\(=x\left(\left(\sqrt{2}x\right)^2-1^2\right)\)\

\(=x\left(\sqrt{2}x-1\right)\left(\sqrt{2}x+1\right)\)

b)\(5x^2\left(x-1\right)-15x\left(x-1\right)\)

\(=\left(5x^2-15x\right)\left(x-1\right)\)

\(=5x\left(x-3\right)\left(x-1\right)\)

d)\(3x\left(x-2y\right)+6y\left(2y-x\right)\)

\(=3x\left(x-2y\right)-6y\left(x-2y\right)\)

\(=\left(3x-6y\right)\left(x-2y\right)\)

\(=3\left(x-2y\right)\left(x-2y\right)\)

\(=3\left(x-2y\right)^2\)

a: \(=\dfrac{x^5}{3x}+\dfrac{12x^2}{3x}+\dfrac{5x}{3x}=\dfrac{1}{3}x^4+4x+\dfrac{5}{3}\)

b: \(=\dfrac{-5x^4}{-5x}-\dfrac{15x^3}{5x}+\dfrac{18x}{5x}=x^3-3x^2+\dfrac{18}{5}\)

c: \(=\dfrac{-x^6}{0.5x}+\dfrac{5x^4}{0.5x}-\dfrac{2x^3}{0.5x}=-2x^5+10x^3-4x^2\)

\(5xy\left(2x^3y^2-7xy+3y\right)=10x^4y^3-35x^2y^2+15xy^2\\ \left(-6x^6+15x^2-4x^4\right):3x^2=-2x^4+5-\dfrac{4}{3}x^2\\ \left(x^2-y^2-12x+36\right):\left(x+y-6\right)\\ =\left[\left(x-6\right)^2-y^2\right]:\left(x+y-6\right)\\ =\left(x-y-6\right)\left(x+y-6\right):\left(x+y-6\right)\\ =x-y-6\)

\(a,\left(x-1\right)\left(2x-1\right)\)

\(=2x^2-x-2x+1\)

\(=2x^2-3x+1\)

\(b,\left(9x^4+12x^3-15x^2-3x\right):3x\)

\(=3x^3+4x^2-5x-1\)