Bài 1:

a, 3\(\dfrac{2}{5}\) - \(\dfrac{1}{2}\) 

= \(\dfrac{17}{5}\) - \(\dfrac{1}{2}\) 

= \(\dfrac{34}{10}\) - \(\dfrac{5}{10}\)

= \(\dfrac{29}{10}\)

b, \(\dfrac{4}{5}\) + \(\dfrac{1}{5}\) x \(\dfrac{3}{4}\)

= \(\dfrac{4\times4}{5\times4}\) + \(\dfrac{1\times3}{5\times4}\)

= \(\dfrac{16}{20}\) + \(\dfrac{3}{20}\)

= \(\dfrac{19}{20}\)

c, 4\(\dfrac{4}{9}\) : 2\(\dfrac{2}{3}\) + 3\(\dfrac{1}{6}\)

= \(\dfrac{40}{9}\) : \(\dfrac{8}{3}\) + \(\dfrac{19}{6}\)

= \(\dfrac{5}{3}\) + \(\dfrac{19}{6}\)

= \(\dfrac{10}{6}\) + \(\dfrac{19}{6}\)

= \(\dfrac{29}{6}\)

Bài 2:

   3\(\dfrac{2}{5}\) + 2\(\dfrac{1}{5}\) 

= \(\dfrac{17}{5}\) + \(\dfrac{11}{5}\)

= \(\dfrac{28}{5}\)

b, 7\(\dfrac{1}{6}\) : 5\(\dfrac{2}{3}\)

= \(\dfrac{43}{6}\) : \(\dfrac{17}{3}\)

= \(\dfrac{43}{34}\)

Bài 3:

a, 800 kg 5g > 8,005 kg

b, 9 ha 4 dam² < 9\(\dfrac{5}{100}\) ha

c, 5m 5mm > 5,0005 m

d, 250 kg > \(\dfrac{1}{5}\) tấn

`a,5 xx (-7)+(-2) xx (-5)`

`=5 xx (-7)+5 xx 2`

`= 5 xx (2-7)`

`=5 xx (-5)`

`=-25`

`b,5 xx (-9)+(-2) xx 3`

`=3 xx (-15)+3 xx (-2)`

`=3 xx (-15-2)`

`=3 xx (-17)`

`=-51`

`c,6 xx (-5)^2+3 xx (-15)`

`=2 xx 3 xx 25+3 xx (-15)`

`=3 xx 75-3 xx 15`

`=3 xx (75-15)`

`=3 xx 60`

`=180`

a) 5×(-7) +(-2) ×(-5)

=5.(-7)+2.5

=5.(-7+2)

=5.(-5)=-25

a) Ta có: \(\sin^2\alpha+\cos^2\alpha=1\)

\(\Leftrightarrow\cos^2\alpha=1-\dfrac{9}{25}=\dfrac{16}{25}\)

Ta có: \(A=5\cdot\sin^2\alpha+6\cdot\cos^2\alpha\)

\(=5\left(\sin^2\alpha+\cos^2\alpha\right)+\cos^2\alpha\)

\(=5+\dfrac{16}{25}=\dfrac{141}{25}\)

`a)-4/9(5/6*90%-8:0,32)`

`=-4/9(5/6*9/10-8:8/25)`

`=-4/9(3/4-25)`

`=-4/9*(-97)/4=97/9`

`b)(2/5)^2+5 1/2.(4,5-2)+(2^3)/(-4)`

`=4/25+11/2*5/2+8/(-4)`

`=4/25+55/4-2`

`=1191/100`

A = \(\dfrac{1+5+5^2+5^3+5^4+...+5^{17}}{1+5^2+5^4+...+5^{16}}\)

Đặt tử số là B = 1 + 5 + 5² + 5³ + 5⁴ +...+ 5¹⁷

                  5B =       5 + 5² + 5³ + 5⁴ +...+ 5¹⁷ + 5¹⁸

                  5B - B = 5¹⁸ - 1

                  4B       = 5¹⁸ - 1

                    B       = (5¹⁸ - 1) : 4

Đặt mẫu số là C  = 1 + 5² + 5⁴ +...+ 5¹⁶

                    5².C =       5² + 5⁴ +...+ 5¹⁶ + 5¹⁸

                    25.C - C  =  5¹⁸ - 1

                    24C         =   5¹⁸ - 1

                        C         =    (5¹⁸ - 1): 24 

A = \(\dfrac{B}{C}\) = \(\dfrac{\dfrac{5^{18}-1}{4}}{\dfrac{5^{18}-1}{24}}\)

A = 6 

a=6 banj nha

\(\dfrac{4}{5}\)+\(\dfrac{-5}{4}\)=\(\dfrac{0}{4}\)

\(\dfrac{-1}{3}\)+\(\dfrac{2}{5}-\dfrac{5}{6}\)=\(\dfrac{-10}{30}+\dfrac{12}{30}-\dfrac{25}{30}\)=\(\dfrac{-23}{30}\)

\(\dfrac{2}{3}-\dfrac{5}{7}.\dfrac{14}{25}\)=\(\dfrac{2}{3}-\dfrac{2}{5}\)=\(\dfrac{10}{15}-\dfrac{6}{15}\)=\(\dfrac{4}{15}\)

a: \(=\dfrac{16-25}{20}=\dfrac{-9}{20}\)

b: \(=\dfrac{-10}{30}+\dfrac{12}{30}-\dfrac{25}{30}=-\dfrac{23}{30}\)

c: \(=\dfrac{2}{3}-\dfrac{1}{5}\cdot2=\dfrac{2}{3}-\dfrac{2}{5}=\dfrac{10-6}{15}=\dfrac{4}{15}\)

d: \(=\dfrac{12-25}{30}\cdot\dfrac{15}{8}-1=\dfrac{-13}{16}-1=\dfrac{-29}{16}\)

e: \(=\dfrac{-3}{13}-\dfrac{10}{13}-\dfrac{7}{17}+\dfrac{24}{17}-\dfrac{5}{19}-\dfrac{14}{19}=-1\)

Mình đã trả lời tại link này: https://olm.vn/hoi-dap/question/180855.html?pos=3148734. Bạn tham khảo nha

mình ko hiểu

\(2+\dfrac{3}{4}=\dfrac{8}{4}+\dfrac{3}{4}=\dfrac{11}{4}\\ \dfrac{5}{7}:6=\dfrac{5}{7}\times\dfrac{1}{6}=\dfrac{5}{42}\\ 2-\dfrac{3}{5}=\dfrac{10}{5}-\dfrac{3}{5}=\dfrac{7}{5}\\ \dfrac{5}{9}\times\dfrac{2}{7}=\dfrac{10}{63}\)

a )\(\dfrac{11}{4}\)              b)\(\dfrac{5}{42}\)        c)\(\dfrac{7}{5}\)    d) \(\dfrac{10}{63}\)

11/4

30/7

7/5

10/63