1) Viết tập hợp sau bằng cách liệt kê các phần tử của nó:
a) 𝑨 = {𝒙 ∈ 𝒁|−𝟓 < 𝒙 ≤ 𝟏}
→ \(A=\left\{-4;-3;-2;-1;0;1\right\}\)
 b) 𝑩 = {𝒙 ∈ 𝒁| − 𝟑 ≤ 𝒙 ≤ 𝟎}
→ \(B=\left\{-3;-2;-1;0\right\}\)

\(a,=703-140:70-17^2=703-2-289=412\\ b,=36.5.11-37.5.11+11.11.5=11.5(36-37+11)=55.10=550\\ c,=1152-374-1152-65+374=-65\\ d,=53-76+76-53=0\)

\(=12\cdot2-14\cdot4+18\cdot8-110\cdot10\)

=24-56+144-1100

=-988

= 12 x 2 + 14 x 4 + 18 x 8 + 110 x 10

= 24 + 56 + 144 + 1100

= 1324

Lời giải:
a. $7^{2x-6}=49=7^2$

$\Rightarrow 2x-6=2$

$2x=8$

$x=4$
b. 

$105-(135-7x):9=97$

$(135-7x):9=105-97=8$

$135-7x=8.9=72$

$7x=135-72=63$

$x=63:7=9$

c.

$3^{x-3}-3^2=2.3^2$
$3^{x-3}=3^2+2.3^2=3^2(1+2)=3^3$

$\Rightarrow x-3=3$

$\Rightarrow x=6$

d.

$275-(113+x)+63=158$

$338-(113+x)=158$

$113+x=338-158=180$

$x=180-113=67$

C

C

 c nhé vì 12/28 rút gọn = 3/7

a) \(52^2\)

\(=\left(50+2\right)^2\)

\(=50^2+2\cdot2\cdot50+2^2\)

\(=2500+200+4\)

\(=2704\)

b) \(98^2\)

\(=\left(100-2\right)^2\)

\(=100^2-2\cdot100\cdot2+2^2\)

\(=10000-400+4\)

\(=9604\)

`a, 52^2 = (50+2)^2 = 2500 + 200 + 4 = 2704`

`b, 98^2  = (100-2)^2 = 100^2 - 2 . 100 . 2 + 4 = 10000 - 400 + 4`

`= 9604`

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