Tìm X biết:
a) X – 13,1 = 7,53 x 6
b) 21 x X = 9,45 : 0,1
giúp với bị mắc kẹt rùi
a) X – 13,1 = 7,53 x 6
b) 21 x X = 9,45 : 0,1
x-13,1 = 7,53 x 6 21 x X = 9,45 : 0,1
x - 13,1 = 45,18 21x X = 9,45
x = 45,18 + 13,2 x = 9,45 : 21
x = 58,28 x = 4,5
vậy x = 58,28 Vậy x = 4,5
x-13,1=7,53 x 6 21x X =9,45 :0,1
x-13,1= 45,18 21x X =94,5
x=45,18+13,1 x= 94,5:21
x=58,28 x= 4,5
a, <=> x- 13,1 = 45,18
<=> x = 58 ,28
b, 21x = 94,5
<=> x =4,5
a) X – 13,1 = 7,53 x 6
b) 21 x X = 9,45 : 0,1
b: \(\Leftrightarrow21x=94,5\)
hay x=4,5
a) X – 13,1 = 7,53 x 6
b) 21 x X = 9,45 : 0,1
a) X – 13,1 = 7,53 x 6 b) 21 x X = 9,45 : 0,1
\(a,x-13,1=7,53\times6\\ \Rightarrow x-13,1=45,18\\ \Rightarrow x=45,18+13,1\\ \Rightarrow x=58,28\\ b,21\times x=9,45:0,1\\ \Rightarrow21\times x=94,5\\ \Rightarrow x=94,5:21\\ \Rightarrow x=4,5\)
a) X – 13,1 = 7,53 x 6 b) 21 x X = 9,45 : 0,1
x-13,1=7,53 x 6 21x X =9,45 :0,1
x-13,1= 45,18 21x X =94,5
x=45,18+13,1 x= 94,5:21
x=58,28 x= 4,5
x - 13,1 = 7,53 x 6 21 x X = 9,45 : 0,1
x - 13,1 = 45,18 21 x X = 94,5
x = 45,18 + 13,1 x = 94,5 : 21
x = 58,28 x = 4,5
b: \(\Leftrightarrow21x=94,5\)
hay x=4,5
x- 13,1 = 7,53 x 6 21x X = 9,45 : 0,1
các bn giúp mik nha
x-13,1=7,53*6 21* x=9,45 :0,1
x-13,1=45,18 21* x=94,5
x=45,18+13,1 x= 94,5:21
x=58,28 x= 4,5
Vậy x= 58,28 Vậy x= 4,5
x-13,1 = 7,53 x 6 21 x X = 9,45 : 0,1
x - 13,1 = 45,18 21x X = 9,45
x = 45,18 + 13,2 x = 9,45 : 21
x = 58,28 x = 4,5
vậy x = 58,28 Vậy x = 4,5
tìm x, biết:
a, x:3.5=3/4 :-5/6
b,x-1.2/2 = 8/x-1.2
`x :3*5 = 3/4 :(-5/6)`
`x :15 =3/4*(-6/5)=-9/10`
`x = -9/10 *15 =-27/2`
`x-1*2/2 = 8/x -1.2`
`x- 1*1 = 8/x -2`
`x-8/x = -2+1`
`x-8/x =-1`
`x^2 -8x =-x`
`x^2 -8x +x=0`
`x^2 -7x =0`
`x(x-7) =0`
`=>[(x=0),(x=7):}`
`a, x \div 15=-9/10`
`x=-9/10*14`
`x=-27/2`
`b, (x-1*2)/2=8/(x-1*2)`
\(\left(x-1\cdot2\right)\cdot\left(x-1\cdot2\right)=8\cdot2\)
`(x-1*2)^2=16`
`(x-1*2)^2=(+-4)^2`
\(\Rightarrow\left[{}\begin{matrix}x-1\cdot2=4\\x-1\cdot2=-4\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x-2=4\\x-2=-4\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=4+2\\x=\left(-4\right)+2\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)
Tìm x biết:
a) 5x.(x-1)-(x+2).(5x-7)=6
b) (x+2)2-(x2-4)=0
`a)5x(x-1)-(x+2)(5x-7)=6`
`<=>5x^2-5x-(5x^2-7x+10x-14)=6`
`<=>5x^2-5x-(5x^2+3x-14)=6`
`<=>-8x+14=6`
`<=>8x=8<=>x=1`
Vậy `x=1`
`b)(x+2)^2-(x^2-4)=0`
`<=>x^2+4x+4-x^2+4=0`
`<=>4x+8=0`
`<=>4x=-8`
`<=>x=-2`
Vậy `x=-2`
a)5x.(x-1)-(x+2).(5x-7)=6
<=> 5x2-5x-(5x2-7x+10x-14)=6
<=> 5x2-5x-5x2+7x-10x+14=6
<=> -8x+14=6
<=> -8x=-8 => x=1
Vậy x=1
b) (x+2)2-(x2-4)=0
<=> (x+2)2-(x2-22)=0 <=> (x+2)2-(x-2)(x+2)=0
<=> (x+2)[(x+2)-(x-2)]=0
<=> (x+2)(x+2-x+2)=0
<=> (x+2).4=0
=> x+2=0
=> x=-2
Vậy x=-2
Tìm x biết:
a) x(x - 2) - x2 + 5x = 6
b) (x - 3)2 - x + 9 =0
giúp mình câu này nha
\(a,\Leftrightarrow x^2-2x-x^2+5x=6\\ \Leftrightarrow3x=6\\ \Leftrightarrow x=2\)
\(b,\Leftrightarrow x^2-6x+9-x+9=0\\ \Leftrightarrow x^2-7x+18=0\\ \Leftrightarrow\left(x^2-7x+\dfrac{49}{4}\right)+\dfrac{23}{4}=0\\ \Leftrightarrow\left(x-\dfrac{7}{2}\right)^2+\dfrac{23}{4}=0\left(vôlí\right)\)