3x(x - 10) = x - 10

(x - 10)(3x - 1) = 0

Th1:

x - 10 = 0

x = 10

TH2:

3x - 1 = 0

3x = 1

x = 1/3

Vậy x = 10 hoặc x = 1/3

x(x + 7) - (4x + 28) = 0

x(x + 7) - 4(x + 7) = 0

(x + 7)(x - 4) = 0

Th1:

x + 7 = 0

x = - 7

Th2:

x - 4 = 0

x = 4

Vậy x = - 7 hoặc x = 4

x(x - 4) = 2x - 8

x(x - 4) - 2(x - 4) = 0

(x - 2)(x - 4) = 0

Th1:

x - 2 = 0

x = 2

Th2:

x - 4 = 0

x = 4 

Vậy x = 2 hoặc x = 4

(2x + 3)(x - 1) + (2x - 3)(x - 1) = 0

(x - 1)(2x + 3 + 2x - 3) = 0

4x(x - 1) = 0

Th1:

x = 0

Th2:

x - 1 = 0

x = 1

Vậy x = 0 hoặc x = 1

a)

\(3x\left(x-10\right)=x-10\)

\(\Rightarrow3x\left(x-10\right)-\left(x-10\right)=0\)

\(\Rightarrow\left(3x-1\right)\left(x-10\right)=0\)

\(\Rightarrow\left[\begin{array}{nghiempt}3x-1=0\\x-10=0\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{1}{3}\\x=10\end{array}\right.\)

b)

\(x\left(x+7\right)-\left(4x+28\right)=0\)

\(\Rightarrow x\left(x+7\right)-4\left(x+7\right)=0\)

\(\Rightarrow\left(x-4\right)\left(x+7\right)=0\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=4\\x=-7\end{array}\right.\)

c)

\(x\left(x-4\right)=2x-8\)

\(\Rightarrow x\left(x-4\right)-2\left(x-4\right)=0\)

\(\Rightarrow\left(x-4\right)\left(x-2\right)=0\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=4\\x=2\end{array}\right.\)

d)

\(\left(2x+3\right)\left(x-1\right)+\left(2x+3\right)\left(x-1\right)=0\)

\(\Rightarrow2\left(2x+3\right)\left(x-1\right)=0\)

\(\Rightarrow\left[\begin{array}{nghiempt}2x+3=0\\x-1=0\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=-\frac{3}{2}\\x=1\end{array}\right.\)

Mọi người giúp mình nhanh nhé ! Mình đang cần gấp

a)

\(3x\left(x+1\right)-6\left(x+1\right)=0\\ \Leftrightarrow\left(x+1\right)\left(3x-6\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)

b)

\(2x+25-2\left(10-3x\right)=0\\ \Leftrightarrow8x+5=0\\ \Leftrightarrow x=-\dfrac{5}{8}\)

c)

\(\left|x-3\right|=7-\left(-2\right)\\ \Rightarrow\left|x-3\right|=9\\ \Rightarrow\left[{}\begin{matrix}x=12\\x=-6\end{matrix}\right.\)

1

a, 4x - 3x + 1 = 5

        x             =5-1

       x              =4

Vậy x=4

b,  (2x - 4 ) . 3x =0

=> 2x - 4 =0     hoặc  3x = 0

=> 2x       =4    hoặc    x=0

=>  x        =2    hoặc    x=0

vậy x= 2 hoặc x=0

c, x . ( x -1 ) - ( x-1 )=0

    (x-1) . (x-1 )         =0

     (x-1)²                  =0²

     x-1                      =0 

    x                          =1

vậy x=1 

2/ a,  7 . (x - 1 )  = 6x + 3

         7x  -7        = 6x  +3

         7x - 6x       =7+3 

              x            =10

vậy x=10 

b, 8 . ( 2x - 3 )  -15x   =4

    16x  - 24       -15x   =4

     16x - 15x                =4+24

            x                      =28

vậy x=28

c, 7 . 10 + ( x-1 ) .2    =100

      70    +   2x  -2      =100

                    2x -2      =100-70

                    2x -2      =30 

                    2x           =30+2

                    2x           =32

                      x           =16

vậy x=16

chúc bn học tốt

e, 3x(2-x) =15(x-2)

\(\Leftrightarrow3x\left(2-x\right)-15\left(x-2\right)=0\)

\(\Leftrightarrow-3x\left(x-2\right)-15\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(-3x-15\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x-2=0\\-3x-15=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)

Vậy..

f, (x+5)(x+4)=0

\(\Leftrightarrow\left\{{}\begin{matrix}x+5=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-5\\x=-4\end{matrix}\right.\)

Vậy..

g, x(x+4)=0

\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=-4\end{matrix}\right.\)

,h, (2x -4)(x-2)=0

\(\Leftrightarrow2\left(x-2\right)\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(2-1\right)=0\)

\(\Leftrightarrow x-2=0\Leftrightarrow x=2\)

i, (x+1/5)(2x-3)=0

\(\Leftrightarrow\left\{{}\begin{matrix}x+\frac{1}{5}=0\\2x-3=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\frac{-1}{5}\\x=\frac{3}{2}\end{matrix}\right.\)

k, x²-4x=0

\(\Leftrightarrow x\left(x-2\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

m, 4x²-1=0

\(\Leftrightarrow\left(2x\right)^2-1^2=0\)

\(\Leftrightarrow\left(2x-1\right)\left(2x+1\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}2x-1=0\\2x+1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=1\\2x=-1\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{1}{2}\\x=\frac{-1}{2}\end{matrix}\right.\)

n, x²-6x+9=0

\(\Leftrightarrow x^2-2.x.3+3^2=0\)

\(\Leftrightarrow\left(x-3\right)^2=0\Leftrightarrow x-3=0\)

<=> x=3

l, (3x-5)²-(x+4)²=0

\(\Leftrightarrow\left(3x-5-x-4\right)\left(3x-5+x+4\right)=0\)

\(\Leftrightarrow\left(2x-9\right)\left(4x-1\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}2x-9=0\\4x-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=9\\4x=1\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{9}{2}\\x=\frac{1}{4}\end{matrix}\right.\)

Vậy ..

o, 7x(x+2)-5(x+2)=0

\(\Leftrightarrow\left(x+2\right)\left(7x-5\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x+2=0\\7x-5=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2\\7x=5\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=-2\\x=\frac{5}{7}\end{matrix}\right.\)

Vậy....

p, 3x(2x-5)-4x+10=0

\(\Leftrightarrow3x\left(2x-5\right)-\left(4x-10\right)=0\)

\(\Leftrightarrow3x\left(2x-5\right)-2\left(2x-5\right)=0\)

\(\Leftrightarrow\left(2x-5\right)\left(3x-2\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}2x-5=0\\3x-2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=5\\3x=2\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{5}{2}\\x=\frac{2}{3}\end{matrix}\right.\)

Vậy...

q, (2-2x)-x²+1=0

\(\Leftrightarrow2\left(1-x\right)-\left(x^2-1^2\right)=0\)

\(\Leftrightarrow2\left(1-x\right)-\left(x-1\right)\left(x+1\right)=0\)

\(\Leftrightarrow2\left(1-x\right)+\left(1-x\right)\left(x+1\right)=0\)

\(\Leftrightarrow\left(1-x\right)\left(2+x+1\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}1-x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-1\\x=-3\end{matrix}\right.\)

Vậy ....

r, x(1-3x)=5(1-3x)

\(\Leftrightarrow x\left(1-3x\right)-5\left(1-3x\right)=0\)

\(\Leftrightarrow\left(1-3x\right)\left(x-5\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}1-3x=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-3x=-1\\x=5\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{1}{3}\\x=5\end{matrix}\right.\)

s, 2x-3/4+x+1/6=3

\(\Leftrightarrow x-\frac{7}{12}=3\Leftrightarrow x=3+\frac{7}{12}=\frac{43}{12}\)

r, x(1-3x)=5(1-3x)

➜x(1-3x)-5(1-3x)=0

➜(x-5)(1-3x)=0

➜\(\left[{}\begin{matrix}x-5=0\\1-3x=0\end{matrix}\right.\text{➜}\left[{}\begin{matrix}x=5\\x=\frac{1}{3}\end{matrix}\right.\)

Mk lười lắm mai nha!!!~~~~~~~~~~~~

Làm dần:

a, 3x+6=0

➜3x=-6

➜x=2

b, 2x-10=0

➜2x=10

➜x=5

c, 3x-7=11

➜3x=11+7

➜3x=18

➜x=6

d, 3x-9=0

➜3x=9

➜x=3

\(x^3-x=0\Leftrightarrow x\left(x^2-1\right)=0\Leftrightarrow\left(x-1\right)x\left(x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=0\\x=-1\end{matrix}\right..Vậy:x\in\left\{-1;0;-1\right\}\)

\(x^3+4x=0\Leftrightarrow x\left(x^2+4\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x^2+4=0\end{matrix}\right.mà:x^2+4\ge0+4=4\Rightarrow x=0\)

\(\left(x+2\right)^2=x+2\Leftrightarrow\left(x+2\right)\left(x+2-1\right)=0\Leftrightarrow\left(x+1\right)\left(x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x+1=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=-2\end{matrix}\right.\)

1,
( 2x-5) + 17=6
\(2x-5=6-17\)
\(2x-5=-11\)
\(2x=-11+5\)
\(2x=-6\)
\(x=-6:2\)
\(x=-3\)
Vậy \(x=3\)

2,
10-2(4-3x)=-4
\(-2\left(4-3x\right)=-4-10\)
\(-2\left(4-3x\right)=-14\)
\(4-3x=-14:\left(-2\right)\)
\(4-3x=7\)
\(-3x=7-4\)
\(-3x=3\)
\(x=3:\left(-3\right)\)
\(x=-1\)
Vậy \(x=-1\)

3,
-12+3(-x+7)=-18
\(3\left(-x+7\right)=-18+12\)
\(3\left(-x+7\right)=-6\)
\(-x+7=-6:3\)
\(-x+7=-2\)
\(-x=-2-7\)
\(-x=-9\)
\(x=9\)
\(\text{Vậy }x=9\)

4,
24:(3x -2)=-3
\(3x-2=24:\left(-3\right)\)
\(3x-2=-8\)
\(3x=-8+2\)
\(3x=-6\)
\(x=-6:3\)
\(x=-2\)
\(\text{Vậy }x=-2\)

5,
-45:5.(-3-2x)=3
\(5\left(-3-2x\right)=-45:3\)
\(5\left(-3-2x\right)=-15\)
\(-3-2x=-15:5\)
\(-3-2x=-3\)
\(-2x=-3+3\)
\(-2x=0\)
\(x=0\)
Vậy \(x=0\)

6,
x.(x+7)= 0
\(\Rightarrow\left\{{}\begin{matrix}x=0\\x+7=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=0\\x=-7\end{matrix}\right.\)
\(\text{Vậy}\left\{{}\begin{matrix}x=0\\x=-7\end{matrix}\right.\)

7,
( x+ 12 ) .( x-3)=0
\(\Rightarrow\left\{{}\begin{matrix}x+12=0\\x-3=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=-12\\x=3\end{matrix}\right.\)
\(\text{Vậy }\left\{{}\begin{matrix}x=-12\\x=3\end{matrix}\right.\)

8,
(-x+5).(3-x) =0
\(\Rightarrow\left\{{}\begin{matrix}-x+5=0\\3-x=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}-x=-5\\-x=-3\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=5\\x=3\end{matrix}\right.\)
Vậy \(x=5\text{ hoặc }x=3\)

9, x.( 2+x).(7-x)=0
\(\Rightarrow\left\{{}\begin{matrix}x=0\\2+x=0\\7-x=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=0\\x=-2\\x=7\end{matrix}\right.\)
Vậy \(\left\{{}\begin{matrix}x=0\\x=-2\\x=7\end{matrix}\right.\)

10,
(x-1).(x+2).(-x-3)=0
\(\Rightarrow\left\{{}\begin{matrix}x-1=0\\x+2=0\\-x-3=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=1\\x=-2\\-x=3\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=1\\x=-2\\x=-3\end{matrix}\right.\)
Vậy \(\left\{{}\begin{matrix}x=1\\x=-2\\x=-3\end{matrix}\right.\)

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