b: Tọa độ giao điểm là:

\(\left\{{}\begin{matrix}\dfrac{1}{2}x-5=-\dfrac{3}{2}x-1\\y=\dfrac{1}{2}x-5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=4\\y=\dfrac{1}{2}x-5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=-4\end{matrix}\right.\)

9,45 nha bn

9,45 nha bn

tham khảo

\(4^{x+2}+4^x=272\)

\(\Leftrightarrow4^x=16\)

hay x=2

4^x+2 + 4^x =272

4^x.4² + 4^x =272

4^x.(4²+1)=272

4^x.17=272

4^x=272:17

4^x=16

4^x=4²

=>x=2

quy đồng mẫu số : 1/4=7/28 ; 2/7= 8/28

 Vì 8/18 > 7/28 nên 2/4 > 1/7

   Vậy Hòa được tặng nhiều hoa hơn 

\(t,=\dfrac{3^{64}\cdot7^{24}}{7^{23}\cdot9^{66}}=\dfrac{7}{3^2}=\dfrac{7}{9}\\ u,=\dfrac{5^3\cdot3^4\cdot2^5}{5^2\cdot3^3\cdot2^4}=5\cdot3\cdot2=30\\ v,=\dfrac{3^6\cdot2^{15}}{2^6\cdot3^6\cdot2^8}=2\)

\(\dfrac{3^{64}.49^{12}}{7^{23}.9^{33}}\)

\(=\dfrac{3^{64}.\left(7^2\right)^{12}}{7^{23}.\left(3^2\right)^{33}}\)

\(=\dfrac{3^{64}.7^{24}}{7^{23}.3^{66}}\)

\(=\dfrac{7}{9}\)

a: 6/5-2/3=18/15-10/15=8/15

b: 9/7-5/8=72/56-35/56=37/56

c: 7/6-3/4=14/12-9/12=5/12

d: 9/8-8/9=81/72-64/72=17/72

e: 7/5-7/6=7(1/5-1/6)=7/30

f: 3/4-2/5=15/20-8/20=7/20

g: 4/7-5/6=24/42-35/42=-11/41

i: 6/13-5/11=66/143-65/143=1/143

k: 1-4/5=1/5

m: 2-5/9=18/9-5/9=13/9

n: 3-9/5=15/5-9/5=6/5

p: 4-3/4=16/4-3/4=13/4

a) \(\dfrac{6}{5}-\dfrac{2}{3}=\dfrac{18}{15}-\dfrac{10}{15}=\dfrac{8}{15}\)

b) \(\dfrac{9}{7}-\dfrac{5}{8}=\dfrac{72}{56}-\dfrac{35}{56}=\dfrac{37}{56}\)

c) \(\dfrac{7}{6}-\dfrac{3}{4}=\dfrac{28}{24}-\dfrac{18}{24}=\dfrac{10}{24}=\dfrac{5}{12}\)

d) \(\dfrac{9}{8}-\dfrac{8}{9}=\dfrac{81}{72}-\dfrac{64}{72}=\dfrac{17}{72}\)

e) \(\dfrac{7}{5}-\dfrac{7}{6}=\dfrac{42}{30}-\dfrac{35}{30}=\dfrac{7}{30}\)

h) \(\dfrac{4}{7}-\dfrac{5}{6}=\dfrac{24}{42}-\dfrac{35}{42}=-\dfrac{11}{42}\)

i) \(\dfrac{6}{13}-\dfrac{5}{11}=\dfrac{66}{143}-\dfrac{65}{143}=\dfrac{1}{143}\)

k) \(1-\dfrac{4}{5}=\dfrac{5}{5}-\dfrac{4}{5}=\dfrac{1}{5}\)

m) \(2-\dfrac{5}{9}=\dfrac{18}{9}-\dfrac{5}{9}=\dfrac{13}{9}\)

n) \(3-\dfrac{9}{5}=\dfrac{15}{5}-\dfrac{9}{5}=\dfrac{6}{5}\)

p) \(4-\dfrac{3}{4}=\dfrac{16}{4}-\dfrac{3}{4}=\dfrac{13}{4}\)

Ko

2. hẹp-sâu

ko có