Ta có: 

`11/10 = 1 + 1/10`

`7/6 = 1+1/6`

`10/9 = 1 + 1/9`

`9/8 = 1 + 1/8`

Ta có: `1/10 < 1/9 < 1/8 < 1/6`

nên `11/10 < 10/9  < 9/8 < 7/6`

\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2019.2020}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-...+\frac{1}{2019}-\frac{1}{2020}\)

\(=1-\frac{1}{2020}>1\)

Thank you bạn dcv new ^ ^

nhầm dấu rồi bé hơn 1 chứ:v bạn sửa lại hộ mình nhà

\(a,\dfrac{5}{3}>\dfrac{3}{5};b,\dfrac{6}{11}< \dfrac{9}{5};c,\dfrac{6}{11}=\dfrac{6}{11};d,\dfrac{8}{9}< \dfrac{8}{5}\)

 \(a,>\)

\(b,< \)

\(c,=\)

\(d,< \)

>

<

=

<

\(\dfrac{1}{2}< \dfrac{2}{3}\\ \dfrac{2}{3}=\dfrac{8}{12}\)

ta có :

`1/2=(1xx3)/(2xx3)=3/6 ; 2/3=(2xx2)/(3xx2)=4/6`

`-> 1/2 < 2/3`

`---`

ta có : 

`2/3=(2xx4)/(3xx4)=8/12;8/12`

`->2/3=8/12`

a)

`1/2=(1xx3)/(2xx3)=3/6`

`2/3=(2xx2)/(3xx2)=4/6`

vì 3<4 nên `3/6<4/6`

`=> 1/2<2/3`

b)

`8/12=(8:4)/(12:4)=2/3`

vì 2=2 nên `2/3=2/3`

`=> 2/3=8/12`

Ta có :

\(\frac{6}{7}=1-\frac{1}{7}\)

\(\frac{7}{8}=1-\frac{1}{8}\)

Vì \(\frac{1}{7}>\frac{1}{8}\) nên \(1-\frac{1}{7}< 1-\frac{1}{8}\)

hay \(\frac{6}{7}< \frac{7}{8}\)

#Học tốt

Ta có: \(1-\frac{1}{7}=\frac{6}{7}\)

\(1-\frac{1}{8}=\frac{7}{8}\)

Mà \(\frac{1}{7}>\frac{1}{8}\Rightarrow\frac{6}{7}< \frac{7}{8}\)

#hoktot#

a ) − 1 < 1 ; b ) − 1 6 > − 1 3 ; c ) − 1 24 < − 1 28 ; d ) 103 100 > 1

-11/8<1/24
3/20<6/15

Câu 1 : >

Câu 2 : <

Do \(\dfrac{{ - 11}}{8} < 0\) và \(\dfrac{1}{{24}} > 0\) nên \(\dfrac{{ - 11}}{8} < \dfrac{1}{{24}}\)

\(\frac{4}{5}< \frac{5}{6}< \frac{7}{8}< \frac{6}{5}\)

\(\frac{4}{5};\frac{5}{6};\frac{7}{8};\frac{6}{5}\)

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