Chọn D

\(3^2\cdot5+2^3\cdot10-3^4:3\\ =9\cdot5+8\cdot10-3^4\\ =45+80-27\\ =98\)

\(3^2.5+2^3.10-3^4:3\)

\(=9.5+8.10-3^3\)

\(=45+80-27\)

\(=125-27\)

\(=98\)

\(#WendyDang\)

Anh ơi, dòng 2 ( \(3^4:3\) thì ra \(3^3\) -> a mới đổi thành được \(27\) chứ ạ? )

a: \(=-\left(10x^2+15x-8x-12\right)=-10x^2-7x+12\)

-10x^2-7x+12

= 12-7x-10x^2

=2⁷ - 7²⁰²² 

=2⁷ - 7²⁰²² 

Ta có:

\(\left(x-1\right).\left(x+1\right).\left(x+2\right)\)

\(=\left(x^2+x-x-1\right).\left(x+2\right)\)

\(=\left(x^2-1\right).\left(x+2\right)\)

\(=x^3+2x^2-x-2\)

a)\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)

\(=\frac{5}{9}:\left[\left(\frac{1}{11}-\frac{5}{22}\right)+\left(\frac{1}{15}-\frac{2}{3}\right)\right]\)

\(=\frac{5}{9}:\left[-\frac{3}{22}+-\frac{3}{5}\right]\)

\(=\frac{5}{9}:\frac{-81}{110}\)

\(=\frac{-550}{729}\)

\(60-\left[15.2+\left(4+1^{35}\right)^2\right]\)
\(\Rightarrow60-\left[30+\left(4+1\right)^2\right]\)
\(\Rightarrow60-\left[30+25\right]\)
\(\Rightarrow60-55\)
\(\Rightarrow5\)

60-[30+(4+1)²

60-[30+25]

60-55

5