a: =(-8,3+8,3)-7,5=-7,5

b: =8,2+31,6=39,8

c: =(3,56+6,44)+(-4,62-3,38)

=10-8

=2

\(a,=-8,3-7,5+8,3\\ =\left[\left(-8,3\right)+8,3\right]-7,5\\ =0-7,5=-7,5\\ b,=6,4+1,8+31,6\\ =\left(6,4+31,6\right)+1,8\\ =38+1,8=39,8\\\)

\(=20.\left(-9\right)+\left(-20\right).21\)

\(=-180+\left(-420\right)\)

\(=-600\)

a) =20.(-9)+(-20).21

=20.(-9)+20.(-21)

=20[(-9)+(-21)]

=20.(-30)

=-600

Cách 1: Theo kiểu dài                       |           Cách 2:Ngắn gọn
a) (29 – 9). (-9) + (-13 – 7). 21          |       a) (29-9) . (-9) + (-13-7) . 21
= 20. (-9) + [- (13 + 7). 21]                 |       =20.(-9)+(-20).21
= 20. (-9) + (-20). 21                          |       =180+(-420)
= (-20). 9 + (-20). 21                          |       =600
= (-20). (9 + 21)                                 |
= (-20). 30                                          |
= - (20. 30)                                         |
= - 600.                                              |

(Chúc bạn học tốt nha~!)

a: \(\left(-\dfrac{5}{6}+\dfrac{2}{5}\right):\dfrac{3}{8}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right):\dfrac{3}{8}\)

\(=\left(-\dfrac{5}{6}+\dfrac{2}{5}\right)\cdot\dfrac{8}{3}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right)\cdot\dfrac{8}{3}\)

\(=\dfrac{8}{3}\left(-\dfrac{5}{6}+\dfrac{2}{5}+\dfrac{4}{5}-\dfrac{11}{30}\right)\)

\(=\dfrac{8}{3}\cdot\dfrac{-25+36-11}{30}\)

=0

b: \(\left(-\dfrac{3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+\dfrac{-1}{4}\right):\dfrac{3}{7}\)

\(=\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\cdot\dfrac{7}{3}+\left(\dfrac{3}{5}-\dfrac{1}{4}\right)\cdot\dfrac{7}{3}\)

\(=\dfrac{7}{3}\left(-\dfrac{3}{4}+\dfrac{2}{5}+\dfrac{3}{5}-\dfrac{1}{4}\right)\)

\(=\dfrac{7}{3}\cdot0=0\)

c: \(\dfrac{-13}{18}\cdot\dfrac{5}{8}+\dfrac{-5}{18}\cdot\dfrac{2}{9}+\dfrac{-13}{18}\cdot\dfrac{3}{8}+\dfrac{-5}{18}\cdot\dfrac{7}{9}\)

\(=\left(-\dfrac{13}{18}\cdot\dfrac{5}{8}+\dfrac{-13}{18}\cdot\dfrac{3}{8}\right)+\left(-\dfrac{5}{18}\cdot\dfrac{2}{9}+\dfrac{-5}{18}\cdot\dfrac{7}{9}\right)\)

\(=-\dfrac{13}{18}\left(\dfrac{5}{8}+\dfrac{3}{8}\right)+\dfrac{-5}{18}\left(\dfrac{2}{9}+\dfrac{7}{9}\right)\)

\(=-\dfrac{13}{18}-\dfrac{5}{18}=-\dfrac{18}{18}=-1\)

d: Sửa đề: \(\dfrac{-11}{19}\cdot\dfrac{4}{9}+\dfrac{-8}{19}\cdot\dfrac{3}{7}+\dfrac{-11}{19}\cdot\dfrac{5}{9}+\dfrac{-8}{19}\cdot\dfrac{4}{7}\)

\(=\left(-\dfrac{11}{19}\cdot\dfrac{4}{9}+\dfrac{-11}{19}\cdot\dfrac{5}{9}\right)+\left(\dfrac{-8}{19}\cdot\dfrac{3}{7}+\dfrac{-8}{19}\cdot\dfrac{4}{7}\right)\)

\(=-\dfrac{11}{19}\left(\dfrac{4}{9}+\dfrac{5}{9}\right)+\dfrac{-8}{19}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\)

\(=-\dfrac{11}{19}-\dfrac{8}{19}=-\dfrac{19}{19}=-1\)

\(a.\left(-\dfrac{5}{6}+\dfrac{2}{5}\right):\dfrac{3}{8}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right):\dfrac{3}{8}\)

\(=\left(-\dfrac{13}{30}\right):\dfrac{3}{8}+\dfrac{13}{30}:\dfrac{3}{8}\)

\(=\left[\left(-\dfrac{13}{30}+\dfrac{13}{30}\right)\right]:\dfrac{3}{8}\)

\(=0:\dfrac{3}{8}=0\)

\(b.\left(-\dfrac{3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+-\dfrac{1}{4}\right):\dfrac{3}{7}\)

\(=\left(-\dfrac{7}{20}\right):\dfrac{3}{7}+\dfrac{7}{20}:\dfrac{3}{7}\)

\(=\left[\left(-\dfrac{7}{20}+\dfrac{7}{20}\right)\right]:\dfrac{3}{7}=0:\dfrac{3}{7}=0\)

\(c.-\dfrac{13}{18}.\dfrac{5}{8}+-\dfrac{5}{18}.\dfrac{2}{9}+-\dfrac{13}{18}.\dfrac{3}{8}+-\dfrac{5}{18}.\dfrac{7}{9}\)

\(=\left(\dfrac{5}{8}+\dfrac{3}{8}\right).-\dfrac{13}{18}+\left(\dfrac{2}{9}+\dfrac{7}{9}\right).-\dfrac{5}{18}\)

\(=1.-\dfrac{13}{18}+1.-\dfrac{5}{18}=-\dfrac{13}{18}+-\dfrac{5}{18}=-1\)

\(d.-\dfrac{11}{19}.\dfrac{4}{9}+\dfrac{-8}{19}.\dfrac{3}{7}+-\dfrac{11}{19}.\dfrac{5}{9}+-\dfrac{9}{19}.\dfrac{4}{7}\)

\(=\left(\dfrac{4}{9}+\dfrac{5}{9}\right).-\dfrac{11}{19}+-\dfrac{24}{133}+-\dfrac{36}{133}\)

\(=-\dfrac{11}{19}+-\dfrac{60}{133}=-\dfrac{137}{133}\)

\(A=22+\left(27-7\times6\right)-\left(94\times7-27\times99\right)\\ =22+27-7\times6-94\times7+27\times99\\ =22+\left(27+27\times99\right)+\left(-7\times6-94\times7\right)\\ =22+27\times\left(1+99\right)+7\times\left(-6-94\right)\\ =22+27\times100+7\times\left(-100\right)\\ =22+2700-700\\ =2022\)

-94x7-27x99) 

chỗ này ngoặc chỗ ở chỗ nào vậy 

a: \(A=21\cdot100-11\cdot100+90\cdot100+100\cdot125\cdot16\)

\(=100\left(21-11+90\right)+100\cdot2000\)

\(=100\left(10+90+2000\right)=2100\cdot100=210000\)

b: \(=\dfrac{5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}}{5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}\)

\(=\dfrac{2^{29}\cdot3^{18}\left(5\cdot2-3^2\right)}{2^{28}\cdot3^{18}\left(5\cdot3-7\cdot2\right)}=2\)

a)= 2021.2021-2020.(2021+1)
  = 2021.(2020+1)-2020.(2021+1)
  = (2021.2020)+2021-(2020.2021)-2020
  = 1

b) B= (1+2-3-4)+(5+6-7-8)+(9+10-11-12)...........+(2017+2018-2019-2020)+2021
    B= -4+(-4)+....................(-4)+2021
    B= -4x505+2021
    B= -2020 + 2021
    B = 1

A = 512 x 4 + 512 x 58
A = 512 x (4 + 58)
A = 512 x 62
A = 31 744
 

B = 312 x 36 - 312 x 26
B = 312 x (36 - 26)
B = 312 x 10
B = 3120
 

C = 745 x 11 - 745
C = 745 x (11 - 1)
C = 745 x 10
C = 7450
 

D = 837 x 15 - 837 x 5
D = 837 x (15 - 5)
D = 837 x 10
D = 8370
 

E = 578 x 78 - 578 x 14 + 578 x 36
E = 578 x (78 - 14 + 36)
E = 578 x 100
E = 57 800  
 

F = 645 x 78 + 645 x 22
F = 645 x (78 + 22)
F = 645 x 100
F = 64 500

\(\text{B = 312 x 36 - 312 x 26}\)

\(B=312\times\left(36-26\right)\)

\(B=312\times10\)

\(B=3120\)

a) 145 + 43 + (-145) + 57

= [145 + (-145)] + [43 + 57]

= 0 + 100

= 100

A) = (145+(-145))+(43+57)

= 0 + 100

= 100

Bài 2: Tính một cách hợp lý:

a) 145 + 43 + (– 145) + 57;

= 145 - 145 + 43 + 57 = 0 + 100 = 100

b) (– 213) + 36 + (– 787) + 64;

= -213 - 787 + 36 + 64 = -1000 + 100 = -900

c) (– 2) + (– 4) + (– 6) + (– 10) + 8 + 10 + 12;

= -2 +12 - 4 - 6 - 10 + 10 + 8 = 10 - 10 -10 + 10 + 8 = 8 

d) (– 2 020) + (– 598) + (– 201) + 498 + 301.

= -2020 - 799 + 799 = -2020