( x-2) ( x-5 ) ( x ^ 2 -7x-10 )
1, Tính (x - 2)(x - 5) bằng:
A. \(x^2\) + 10. B. \(x^2\) + 7x + 10. C. \(x^2\)- 7x + 10. D. \(x^2\)- 3x + 10.
2, Kết quả của phép chia (2\(x^3\)- 5\(x^2\) + 6x – 15) : (2x – 5) là:
A. x + 3. B. x – 3. C. \(x^2\) – 3. D. \(x^2\) + 3 .
c)3x^2-7x-10=0
d)2x(x-10)-x+10=0
e)3x^3+7x^2+17x+5=0
f)(2x-1)^2-(x-3)^2=0
g)x^3-5x^2+8x=4
c, \(3x^2-7x+10=0\)
\(\Leftrightarrow3x^2+3x-10x+10=0\)
\(\Leftrightarrow3x\left(x+1\right)-10\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(3x-10\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{10}{3}\end{matrix}\right.\)
d, \(2x\left(x-10\right)-x+10=0\)
\(\Leftrightarrow2x\left(x-10\right)-\left(x-10\right)=0\)
\(\Leftrightarrow\left(x-10\right)\left(2x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=\dfrac{1}{2}\end{matrix}\right.\)
x^2 + 6x + 5
x^2 - 7x + 12
x^2 -7x + 10
\(x^2+6x+5=x^2+5x+x+5=x\left(x+5\right)+\left(x+5\right)=\left(x+1\right)\left(x+5\right)\)
\(x^2-7x+12=x^2-4x-3x+12=x\left(x-4\right)-3\left(x-4\right)=\left(x-3\right)\left(x-4\right)\)
\(x^2-7x+10=x^2-2x-5x+10=x\left(x-2\right)-5\left(x-2\right)=\left(x-2\right)\left(x-5\right)\)
\(a,x^2+6x+5=x^2+5x+x+5\)
\(=x\left(x+5\right)+\left(x+5\right)=\left(x+5\right)\left(x+1\right)\)
\(b,\)\(x^2-7x+12=x^2-3x-4x+12\)
\(=x\left(x-3\right)-4\left(x-3\right)=\left(x-3\right)\left(x-4\right)\)
\(c,\)\(x^2-7x+10=x^2-2x-5x+10\)
\(=x\left(x-2\right)-5\left(x-2\right)=\left(x-2\right)\left(x-5\right)\)
a) \(x^2+6x+5=x^2+5x+x+5\)
\(=x\left(x+5\right)+\left(x+5\right)=\left(x+1\right)\left(x+5\right)\)
b)\(x^2-7x+12=x^2-4x-3x+12=x\left(x-4\right)-3\left(x-4\right)=\left(x-3\right)\left(x-4\right)\)
c)\(x^2-7x+10=x^2-2x-5x+10=x\left(x-2\right)-5\left(x-2\right)\)
\(=\left(x-5\right)\left(x-2\right)\)
hc tốt
Tìm x :
1/ |x-5|-7(x+4)=5-7x
2/3|x+4|-2(x+1)=7-2x
3/2|x-6|+7x-2=|x-6|+7x
4/|x+8|+(x-2)=5x-10:2
5/|x+2|-6(x-4)=20-6x
1: =>|x-5|=5-7x+7x+28=33
=>x-5=33 hoặc x-5=-33
=>x=38 hoặc x=-28
3: 2|x-6|+7x-2=|x-6|+7x
=>|x-6|=2
=>x-6=2 hoặc x-6=-2
=>x=8 hoặc x=4
Giải chi tiết hộ mik với ạ
a, [(x-2)(x+10)]/3-[(x+4)(x+10)]/12=[(x-2)(x+4)] b, (x+2)2/8-2(2x+1)=25+(x-2)2/3 c, (7x2-14x-5)/15=(2x+1)2/5-(x-1)2/3. d, [(7x+1)(x-2)]/10+2/5=(x-2)2/5+[(x-1)(x-3)]/2
bài 1:
a)7x(x2-7x+3) b)(x+6)(x-7)
c)(x-8)2 d) (3x+2)2
e)(x-4)(x+4)-(5-x)2
Bài 2:
a)2(x-7)-9=10 b)(2x-5)2-x(4x-3)=2x+50
\(1,\\ a,=7x^3-49x^2+21x\\ b,=x^2-x-42\\ c,=x^2-16x+64\\ d,=9x^2+12x+4\\ e,=x^2-16-25+10x-x^2=10x-41\\ 2,\\ a,\Rightarrow2\left(x-7\right)=19\\ \Rightarrow x-7=\dfrac{19}{2}\Rightarrow x=\dfrac{33}{2}\\ b,\Rightarrow4x^2-20x+25-4x^2+3x-2x=50\\ \Rightarrow-19x=25\Rightarrow x=-\dfrac{25}{19}\)
3|x+4| - 2(x-1) = 7 - 2x
2|x -6| + 7x - 2= |x-6| + 7x
|x+8| + 5(x-2) = 5x - 10 :2
|x+2| - 6(x-4) = 20 - 6x
Giải pt:
\(x^{10}-x^6+x^2-2x+5=0\)
\(7x^8-x^5+x^2-x+3=0\)
1.Tìm x thuộc Z.Biết:
a) 2. I x - 6 I +7x - 2 = I x - 6 I + 7x
b) I x + 8 I +5 . (x-2)= 5x - 10 : 2