2Cu + O₂ ---> 2CuO

CuO + HCl ---> CuCl₂ + H₂O

CuCl₂ + Ba(OH)₂ ---> Cu(OH)₂ + BaCl₂

Cu(OH)₂ ---t^o--> CuO + H₂O

CuO + SO₃ ---> CuSO₄

CuSO₄ + Pb(NO₃)₂ --->Cu(NO₃)₂ + PbSO₄

em tham khảo nha

 https://hoctap247.com/de-thi-kiem-tra/cau-hoi/1531862-viet-cac-phuong-trinh-hoa-hoc-tuong-ung-voi-day-chuyen-hoa-sau-cu-1cucl2-2cuno32-3cuoh2-4cuo.html

Cu + S → CuS

3CuS + 14HNO3 → 3Cu(NO3)2 +3H2SO4 + 8NO + 4H2O

Cu(NO3)2 + 2NaOH → Cu(OH)2 + 2NaNO3

Cu(OH)2 + 2HCl → CuCl2 + 2H2O

CuCl2 → Cu +Cl2.

\(Cu+S-^{t^o}\rightarrow CuS\\ CuS+10HNO_3\rightarrow Cu\left(NO_3\right)_2+H_2SO_4+4H_2O+8NO_2\\ Cu\left(NO_3\right)_2+Ba\left(OH\right)_2\rightarrow Cu\left(OH\right)_2+Ba\left(NO_3\right)_2\\ Cu\left(OH\right)_2+2HCl\rightarrow CuCl_2+2H_2O\\ CuCl_2-^{đpdd}\rightarrow Cu+Cl_2\)

Đáp án C

Các chất thỏa mãn : Cu ; Cu₂O ; CuS ; Cu₂S ; CuSO₃

=>C

$Cu(OH)_2 \xrightarrow{t^o} CuO + H_2O$
$CuO + 2HCl \to CuCl_2 + H_2o$

$CuCl_2 + 2AgNO_3 \to Cu(NO_3)_2 + 2AgCl$
$Cu(NO_3)_2 + 2KOH \to Cu(OH)_2 + 2KNO_3$

\(CuO+H_2SO_4\rightarrow CuSO_4+H_2O\\ CuSO_4+Ba\left(NO_3\right)_2\rightarrow BaSO_4+Cu\left(NO_3\right)_2\\ Cu\left(NO_3\right)_2+2KOH\rightarrow Cu\left(OH\right)_2+2KNO_3\\ Cu\left(OH\right)_2\rightarrow\left(t^o\right)CuO+H_2O\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2\rightarrow\left(t^o\right)Cu+Cl_2\)

Bn tách ra nhé

a. 

S + O₂ ---t^o---> SO₂

\(2SO_2+O_2\xrightarrow[V_2O_5]{t^o}2SO_3\)

SO₃ + H₂O ---> H₂SO₄

H₂SO₄ + 2NaOH ---> Na₂SO₄ + 2H₂O

3Na₂SO₄ + 4Na₂S ---> 4Na₂SO₃

Na₂SO₃ + H₂O ---> 2NaOH + SO₂