B1:Tìm x
a) (x-7).(x+3)<0
b) (2x+6).(x-5) nhỏ hơn hoặc bằng 0.
B2:Tìm x
a) (5x+8)-(2x-15)+21=2x-5
b) 3.(x-5)-4(x+8)=-12
c) |2x+6|-(-5)^2=3
+. là dấu nhân"x" nhé!
B1:Tính
a,3.52-16:22
b,22.17-23.14
c,15.141+59.10
d,17.85+15.17-120
e,100-[75-(7-2)]2
g,(23.94+93.45):(92.10-92)
B2:Tìm x
a,420+65.4=(x+175):3+30
b,96-3.(x+1)=42
c,(x-47)-115=0
d,(x-36):18=12
e,2x=16
B3:Tìm x
a,60-3.(x-2)=51
b,4x-20=25:22
c,8.6+288:(x-3)2=50
mk đang càn rất gấp
Bài 3:
a: Ta có: 60-3(x-2)=51
\(\Leftrightarrow x-2=3\)
hay x=5
b: Ta có: \(4x-20=25:2^2\)
\(\Leftrightarrow4x=\dfrac{25}{4}+20=\dfrac{105}{4}\)
hay \(x=\dfrac{105}{16}\)
c: Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
B1 CMR biểu thức sau luôn dương với mọi x
A=x^2-6x+15
B=4x^2+4x+7
B2 CMR biểu thức sau luôn âm với mọi x
A=-9x^2+6x-2021
B=-2x^2+2x-7
B3 Tìm x
A) (x-2)^2 - (3-4x)^2 +15x^2=0
B) (x-3)(x^2+3x+9)-x(x+2)(2-x)=0
Bài 1
\(A=x^2-6x+15=x^2-2.3.x+9+6=\left(x-3\right)^2+6>0\forall x\)
\(B=4x^2+4x+7=\left(2x\right)^2+2.2.x+1+6=\left(2x+1\right)^2+6>0\forall x\)
Bài 2
\(A=-9x^2+6x-2021=-\left(9x^2-6x+2021\right)=-\left[\left(3x-1\right)^2+2020\right]=-\left(3x-1\right)^2-2020< 0\forall x\)
B1: Tìm x
a) (x-3)^2+(4-x)(x+4)=10
b) x^2-2x=0
c) (x^2-9)^2-(x-3)^2=0
a) \(\left(x-3\right)^2+\left(4-x\right)\left(x+4\right)=10\)
\(\Leftrightarrow\left(x^2-2\cdot x\cdot3+3^2\right)+\left(4-x\right)\left(4+x\right)=10\)
\(\Leftrightarrow x^2-6x+9+\left(4^2-x^2\right)-10=0\)
\(\Leftrightarrow x^2-6x-1+16-x^2=0\)
\(\Leftrightarrow-6x+15=0\)
\(\Leftrightarrow6x=15\)
\(\Leftrightarrow x=\dfrac{5}{2}\)
b) \(x^2-2x=0\)
\(\Leftrightarrow x\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)
c) \(\left(x^2-9\right)^2-\left(x-3\right)^2=0\)
\(\Leftrightarrow\left(x^2-3^2\right)^2-\left(x-3\right)^2=0\)
\(\Leftrightarrow\left(x-3\right)^2\left(x+3\right)^2-\left(x-3\right)^2=0\)
\(\Leftrightarrow\left(x-3\right)^2\left[\left(x+3\right)^2-1\right]=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(x-3\right)^2=0\\\left(x+3\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-3=0\\\left(x+3\right)^2=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x+3=1\\x+3=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\\x=-4\end{matrix}\right.\)
1.Tìm x
a) 9/2 - x = 3/7 b) x : 5/7 = 7/5 c) x x 3/8 = 11/3
a: x=9/2-3/7=57/14
b: =>x=7/5x5/7=1
c: =>x=11/3:3/8=11/3x8/3=88/9
a : x = \(\dfrac{9}{2}\) - \(\dfrac{3}{7}\) = \(\dfrac{57}{14}\)
b : = > x = \(\dfrac{7}{5}\) x\(\dfrac{5}{7}\) = 1
c : = > \(\dfrac{11}{3}\) : \(\dfrac{3}{8}\) = \(\dfrac{11}{3}\) x \(\dfrac{8}{3}\) = \(\dfrac{88}{9}\)
Tìm x
a) (-12) .x -14 = -2
b)(-8).x= (-5).(-7) -3
c) (-9) .x + 3 = (-2) . (-7) + 16
a.\(\left(-12\right)x-14=-2\)
\(\left(-12\right)x=-2+14\)
\(\left(-12\right)x=12\)
\(x=12:\left(-12\right)\)
\(x=-1\)
\(b,\left(-8\right)x=\left(-5\right)\left(-7\right)-3\)
\(\left(-8\right)x=35-3\)
\(\left(-8\right)x=32\)
\(x=32:\left(-8\right)\)
\(x=-4\)
\(c,\left(-9\right)x+3=\left(-2\right)\left(-7\right)+16\)
\(\left(-9\right)x+3=14+16\)
\(\left(-9\right)x+3=30\)
\(\left(-9\right)x=30-3\)
\(\left(-9\right)x=27\)
\(x=27:\left(-9\right)\)
\(x=-3\)
tìm x
a)\(\left(x-\dfrac{1}{7}\right)^4=\left(x-\dfrac{1}{7}\right)^2\)
b)\(3^{x+2}+3^x=7290\)
b) \(3^x\cdot3^2+3^x=7290\)
\(3^x\left(3^2+1\right)=720\)
\(3^x\cdot10=7290\)
\(=>3^x=729=3^6\)
=> \(x=6\)
a: Ta có: \(\left(x-\dfrac{1}{7}\right)^4=\left(x-\dfrac{1}{7}\right)^2\)
\(\Leftrightarrow\left(x-\dfrac{1}{7}\right)^2\left(x-\dfrac{1}{7}-1\right)\left(x-\dfrac{1}{7}+1\right)=0\)
\(\Leftrightarrow\left(x-\dfrac{1}{7}\right)\left(x-\dfrac{8}{7}\right)\left(x+\dfrac{6}{7}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{7}\\x=\dfrac{8}{7}\\x=-\dfrac{6}{7}\end{matrix}\right.\)
tìm x
a)\(\left(x-\dfrac{1}{7}\right)^4=\left(x-\dfrac{1}{7}\right)^2\)
b)\(3^{x+2}+3^x=7290\)
Tìm x
a)\(\dfrac{6}{x-3}=\dfrac{9}{2x-7}\)
b)\(\dfrac{-7}{x+1}=\dfrac{6}{x+27}\)
a, \(\dfrac{6}{x-3}=\dfrac{9}{2x-7}\)
=> 6(2x-7) = 9(x-3)
=> 12x - 42 = 9x - 27
=> 12x - 9x = -27 + 42
=> 3x = 15
=> x = 5
Vậy x = 5
b, \(\dfrac{-7}{x+1}=\dfrac{6}{x+27}\)
=> -7(x + 27) = 6(x + 1)
=> -7x - 189 = 6x + 6
=> -7x - 6x = 6 + 189
=> -13x = 195
=> x = -15
Vậy x = -15
a) Ta có: \(\dfrac{6}{x-3}=\dfrac{9}{2x-7}\)
\(\Leftrightarrow6\left(2x-7\right)=9\left(x-3\right)\)
\(\Leftrightarrow12x-42=9x-27\)
\(\Leftrightarrow12x-9x=-27+42\)
\(\Leftrightarrow3x=15\)
hay x=5
Vậy: x=5
b) Ta có: \(\dfrac{-7}{x+1}=\dfrac{6}{x+27}\)
\(\Leftrightarrow6\left(x+1\right)=-7\left(x+27\right)\)
\(\Leftrightarrow6x+6=-7x+189\)
\(\Leftrightarrow6x+7x=189-6\)
\(\Leftrightarrow13x=183\)
hay \(x=\dfrac{183}{13}\)
Vậy: \(x=\dfrac{183}{13}\)
B1:tìm x bt a)7×(x-9)-5×(6-x)=-6+11x
`#040911`
`a)`
\(7.(x-9)-5.(6-x)=-6+11x\)
`<=> 7x - 63 - 30 + 5x = 11x - 6`
`<=> 7x + 5x - 11x = 63 + 30 - 6`
`<=> (7 + 5 - 11)x = 87`
`<=> x = 87`
Vậy, `x = 87.`
=>7x-63-30+5x=11x-6
=>12x-93=11x-6
=>x=-6+93=87
tìm X
b1.X x 7 - X+66:6=192+17
x*7 - x + 66 : 6 = 192 + 17
=> x(7 - 1) + 11 = 209
=> 6x = 209 - 11
=> 6x = 198
=> x = 33
vậy_
b1.X x 7 - X+66:6=192+17
=>X x(7-1)+11=209
Xx6+11=209
Xx6=209-11=198
x=198:6=33
vậy x=33