a. 4P + 5O₂ \(\underrightarrow{t^o}\) 2P₂O₅

b. 4Al + 3O₂ \(\underrightarrow{t^o}\) 2Al₂O₃

c. Fe + 2HCl \(\rightarrow\) FeCl₂ + H₂\(\uparrow\)

d. H₂ + CuO \(\underrightarrow{t^o}\) Cu + H₂O

e. 3CO + Fe₂O₃ \(\underrightarrow{t^o}\) 2Fe + 3CO₂\(\uparrow\)

f. Cu + 2H₂SO₄ \(\rightarrow\) CuSO₄ + SO₂\(\uparrow\) + 2H₂O

g. Fe + 4HNO₃ \(\rightarrow\) Fe(NO₃)₃ + NO\(\uparrow\) + 2H₂O

h. 2Al + 3H₂SO₄ \(\rightarrow\) Al₂(SO₄)₃ + 3H₂\(\uparrow\)

i. Ca(HCO₃)₂ \(\underrightarrow{t^o}\) CaCO₃ + CO₂\(\uparrow\) + H₂O

à, sorry nha, lo làm cái kia nên quên lun ><

a, b là phản ứng hoá hợp

c, d, h là phản ứng thế

i là phản ứng phân huỷ

a, 4P + 5O₂ ---> 2P₂O₅

b, 4Al + 3O₂ ---> 2Al₂O₃

c, Fe + 2HCl ---> FeCl₂ + H₂

d, H₂ + CuO ---> Cu + H₂O

e, 2CO + Fe₂O₃ ---> 2CO₂ + 2Fe

f, Cu + 2H₂SO₄ ---> CuSO₄ + SO₂ + 2H₂O

g, Fe + 4HNO₃ ---> Fe(NO₃)₃ + NO + 2H₂O

h, 2Al + 3H₂SO₄ --> Al₂(SO₄)₃ + 3H₂

i, Ca(HCO₃)₂ ---> CaCO₃ + CO₂ + H₂O

a, 2Fe+6H2SO4\(\rightarrow\)Fe2(SO4)3+3SO2+6H2O

b, 3Cu+8HNO3\(\rightarrow\) 3Cu(NO3)2+2NO+4H2O

c, Fe+4HNO3\(\rightarrow\) Fe(NO3)3+NO+2H2O

d, Al+6HNO3\(\rightarrow\)Al(NO3)3+3NO2+3H2O

e, Cu+4HNO3\(\rightarrow\) Cu(NO3)2+2NO2+2H2O

Chúc bạn học tốt!

1) Cu + 4HNO₃ → Cu(NO₃)₂ + 2NO₂ + 2H₂O

2) Al + 4HNO₃ → Al(NO₃)₃ + NO + 2H₂O

3) Al + 6HNO₃ → Al(NO₃)₃ + 3NO₂ + 3H₂O

4) 2Fe + 6H₂SO₄ → Fe₂(SO₄)₃ + 3SO₂ + 6H₂O

$\rm u)S + 2HNO_3 \rightarrow H_2SO_4 + 2NO \uparrow$

$\rm v)3Ba(NO_3)_2 + Al_2(SO_4)_3 \rightarrow 3BaSO_4 \downarrow + 2Al(NO_3)_3$
$\rm w)3Ba(OH)_2 + P_2O_5 \rightarrow Ba_3(PO_4)_3 \downarrow + 3H_2O$
$\rm x)2Fe_2O_3 + 3C \xrightarrow{t^o} 4Fe + 3CO_2 \uparrow$

lưu huỳnh oxi đồng

canxi sắt

mặt trời đồng

1+1=3

hok tốt

hello Duy

hello Duy

hello Duy

$C_x{H}_y{O}_z$+$\left(x+\frac{y}{4}-\frac{z}{2}\right)O_2$---->$xC{O}_2+\frac{y}{2}{H}_{2}O$

3)

2Al + 6H2SO4 → Al2(SO4)3 + 3SO2 + 6H2O

Cân bằng CxHyOz + O2 ------> CO2 + H2O - Thuy Kim

(1) \(2H_2Se+O_2\underrightarrow{t^o}2H_2O+2Se\)

(2) \(2Cu\left(NO_3\right)_2\underrightarrow{t^o}2CuO+4NO_2\uparrow+O_2\uparrow\)

(3) \(4Sn+8HCl+2HNO_3\rightarrow5H_2O+N_2O\uparrow+4SnCl_4\)

(4) \(3Cu_2S+6FeS_2+40HNO_3\rightarrow6CuSO_4+3Fe_2\left(SO_4\right)_3+40NO\uparrow+20H_2O\)

\(2C_xH_yO_z+\dfrac{4x+y-2z}{2}O_2\underrightarrow{t^o}2xCO_2+yH_2O\)

\(2C_xH_yO+\dfrac{4x+y-2}{2}O_2\underrightarrow{t^o}2xCO_2+yH_2O\)

\(6Fe_xO_y+\left(12x-2y\right)H_2SO_{4\left(đ\right)}\underrightarrow{t^o}3xFe_2\left(SO_4\right)_3+\left(3x-2y\right)S+\left(12x-2y\right)H_2O\)

\(8Fe_xO_y+\left(30x-4y\right)HNO_3\rightarrow8xFe\left(NO_3\right)_3+\left(3x-2y\right)N_2O+\left(15x-2y\right)H_2O\)

1) \(\overset{+2}{Fe}\overset{-1}{S_2}+\overset{0}{O_2}\rightarrow\overset{+3}{Fe_2}\overset{-2}{O_3}+\overset{+4}{S}\overset{-2}{O_2}\)

quá trình OXH :\(\overset{+2}{Fe}\overset{-1}{S_2}\rightarrow\overset{+3}{Fe}+\overset{+4}{2S}+11e|\times4\)

quá trình khử : \(\overset{0}{2O}+2.2e\rightarrow\overset{-2}{2O}|\times11\)

2) \(\overset{+2}{Fe}\overset{-2}{S}+H\overset{+5}{N}O_3\rightarrow\overset{+3}{Fe}\left(\overset{+5}{N}O_3\right)_3+\overset{+2}{N}\overset{-2}{O}+H_2O+H_2\overset{+6}{S}O_4\)

quá trình OXH : \(\overset{+2}{Fe}\overset{-2}{S}\rightarrow\overset{+3}{Fe}+\overset{+6}{S}+9e|\times1\)

quá trình khử : \(\overset{+5}{N}+3e\rightarrow\overset{+2}{N}|\times3\)

\(\Rightarrow FeS+6HNO_3\rightarrow Fe\left(NO_3\right)_3+3NO+2H_2O+H_2SO_4\)

CÒN ĐỂ CHIỀU MK LM CHO NHA